結果

問題 No.318 学学学学学
ユーザー AEn
提出日時 2023-05-30 02:01:14
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 452 ms / 2,000 ms
コード長 2,879 bytes
コンパイル時間 1,153 ms
コンパイル使用メモリ 82,176 KB
実行使用メモリ 117,504 KB
最終ジャッジ日時 2024-12-28 11:14:42
合計ジャッジ時間 7,480 ms
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 26
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

bucket_size = 350
class SqrtDecomposition:
def __init__(self, N, init,ide):
"""
"""
self.N = N
self.data = []
self.lazydata = []
d = []
if init==0:
for i in range(bucket_size):
self.data.append([ide]*bucket_size)
self.lazydata.append(None)
else:
for i in range(self.N):
if (i+1)%bucket_size==0:
d.append(init[i])
self.data.append(d)
self.lazydata.append(None)
d = []
else:
d.append(init[i])
if d:
self.data.append(d+[ide]*(bucket_size-len(d)))
self.lazydata.append(None)
def update(self, l, r, x):
"""0-indexed[l,r)x"""
#
a1, b1 = l//bucket_size, l%bucket_size
a2, b2 = r//bucket_size, r%bucket_size
if a1==a2:
if self.lazydata[a1] != None:
for i in range(bucket_size):
if b1<=i<b2:
self.data[a1][i] = x
else:
self.data[a1][i] = self.lazydata[a1]
self.lazydata[a1] = None
else:
for i in range(b1,b2):
self.data[a1][i] = x
else:
if self.lazydata[a1] != None:
for i in range(bucket_size):
if i>=b1:
self.data[a1][i] = x
else:
self.data[a1][i] = self.lazydata[a1]
self.lazydata[a1] = None
else:
for i in range(b1,bucket_size):
self.data[a1][i] = x
for i in range(a1+1, a2):
self.lazydata[i] = x
if self.lazydata[a2] != None:
for i in range(bucket_size):
if i<b2:
self.data[a2][i] = x
else:
self.data[a2][i] = self.lazydata[a2]
self.lazydata[a2] = None
else:
for i in range(b2):
self.data[a2][i] = x
def get(self, i):
"""0-indexedi"""
a, b = i//bucket_size, i%bucket_size
if self.lazydata[a] != None:
return self.lazydata[a]
else:
return self.data[a][b]
from collections import defaultdict
N = int(input())
a = list(map(int, input().split()))
d = defaultdict(list)
for i in range(N):
d[a[i]].append(i)
sd = SqrtDecomposition(N,a,0)
a = sorted(list(set(a)))
for nn in a:
sd.update(d[nn][0],d[nn][-1]+1,nn)
ans = [sd.get(i) for i in range(N)]
print(*ans)
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0