結果
問題 | No.2337 Equidistant |
ユーザー |
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提出日時 | 2023-06-02 22:52:31 |
言語 | C++17(clang) (17.0.6 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 1,613 ms / 4,000 ms |
コード長 | 4,745 bytes |
コンパイル時間 | 4,908 ms |
コンパイル使用メモリ | 161,496 KB |
実行使用メモリ | 107,776 KB |
最終ジャッジ日時 | 2024-12-28 21:05:50 |
合計ジャッジ時間 | 23,739 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 28 |
ソースコード
#define ATCODER#define _USE_MATH_DEFINES#include<stdio.h>#include<iostream>#include<fstream>#include<algorithm>#include<vector>#include<string>#include <cassert>#include <numeric>#include <unordered_map>#include <unordered_set>#include <queue>#include <math.h>#include <climits>#include <set>#include <map>#include <list>#include <random>#include <iterator>#include <bitset>using namespace std;using ll = long long;using ld = long double;using pll = pair<ll, ll>;using pdd = pair<ld, ld>;//template<class T> using pq = priority_queue<T, vector<T>, greater<T>>;#define FOR(i, a, b) for(ll i=(a); i<(b);i++)#define REP(i, n) for(ll i=0; i<(n);i++)#define ROF(i, a, b) for(ll i=(b-1); i>=(a);i--)#define PER(i, n) for(ll i=n-1; i>=0;i--)#define REPREP(i,j,a,b) for(ll i=0;i<a;i++)for(ll j=0;j<b;j++)#define VV(type) vector< vector<type> >#define VV2(type,n,m,val) vector< vector<type> > val;val.resize(n);for(ll i;i<n;i++)val[i].resize(m)#define vec(type) vector<type>#define VEC(type,n,val) vector<type> val;val.resize(n)#define VL vector<ll>#define VVL vector< vector<ll> >#define VP vector< pair<ll,ll> >#define SZ size()#define all(i) begin(i),end(i)#define SORT(i) sort(all(i))#define BITI(i) (1<<i)#define BITSET(x,i) x | (ll(1)<<i)#define BITCUT(x,i) x & ~(ll(1)<<i)#define EXISTBIT(x,i) (((x>>i) & 1) != 0)#define ALLBIT(n) (ll(1)<<n-1)#define TOMAX(n,v) n=n<v?v:n#define TOMIN(n,v) n=n>v?v:n#define MP(a,b) make_pair(a,b)#define DET2(x1,y1,x2,y2) x1*y2-x2*y1#define DET3(x1,y1,z1,x2,y2,z2,x3,y3,z3) x1*y2*z3+x2*y3*z1+x3*y1*z2-z1*y2*x3-z2*y3*x1-z3*y1*x2#define INC(a) for(auto& v:a)v++;#define DEC(a) for(auto& v:a)v--;#define SQU(x) (x)*(x)#define L0 ll(0)#ifdef ATCODER#include <atcoder/all>using namespace atcoder;using mint = modint1000000007;using mint2 = modint998244353;#endiftemplate<typename T = ll>vector<T> read(size_t n) {vector<T> ts(n);for (size_t i = 0; i < n; i++) cin >> ts[i];return ts;}template<typename TV, const ll N> void read_tuple_impl(TV&) {}template<typename TV, const ll N, typename Head, typename... Tail>void read_tuple_impl(TV& ts) {get<N>(ts).emplace_back(*(istream_iterator<Head>(cin)));read_tuple_impl<TV, N + 1, Tail...>(ts);}template<typename... Ts> decltype(auto) read_tuple(size_t n) {tuple<vector<Ts>...> ts;for (size_t i = 0; i < n; i++) read_tuple_impl<decltype(ts), 0, Ts...>(ts);return ts;}using val = ll;using func = ll;val op(val a, val b) { return a + b; }val e() { return 0; }val mp(func f, val a) {if (f == -1)return a;return f;}func comp(func f, func g) {if (f == -1)return g;return f;}func id() { return -1; }ll di[4] = { 1,0,-1,0 };ll dj[4] = { 0,1,0,-1 };//ll di[4] = { -1,-1,1,1 };//ll dj[4] = { -1,1,-1,1 };ll di8[8] = { 0,-1,-1,-1,0,1,1,1 };ll dj8[8] = { -1,-1,0,1,1,1,0,-1 };ll n;VVL g;VVL c;VL d;vector<VP> lc;VL pc;ll dfs(ll now, ll p) {ll res = 1;pc[now] = n - 1;REP(i, g[now].size()) {ll v = g[now][i];if (v == p)continue;lc[v][0]=MP(now,i);d[v] = d[now] + 1;ll r = dfs(v, now);pc[now] -= r;c[now][i] = r;res += r;}return res;}void solve() {ll q;cin >> n >> q;g.resize(n);c.resize(n);d.resize(n);lc.resize(n);pc.resize(n);REP(i, n - 1) {ll a, b;cin >> a >> b;a--; b--;g[a].push_back(b);g[b].push_back(a);}REP(i, n) {c[i].resize(g[i].size(), -1);lc[i].resize(20, MP(-1, -1));}dfs(0, -1);REP(i, 19) {REP(j, n) {auto [v, in] = lc[j][i];if (v >= 0)lc[j][i + 1] = lc[v][i];}}while (q--) {ll s, t;cin >> s >> t;s--; t--;if (d[s] < d[t])swap(s, t);ll ss = s;ll tt = t;if ((d[ss] + d[tt]) % 2) {cout << "0\n";continue;}PER(i, 20) {ll up = ll(1) << i;if (d[ss] - up < d[tt])continue;ss = lc[ss][i].first;}ll lca;if (ss != tt) {PER(i, 20) {if (lc[ss][i].first != lc[tt][i].first) {ss = lc[ss][i].first;tt = lc[tt][i].first;}}lca = lc[ss][0].first;}else {lca = ss;}if (d[s] == d[t]) {cout << n - c[lca][lc[ss][0].second] - c[lca][lc[tt][0].second] << "\n";}else{ll dd = d[lca] + (d[s] - d[t]) / 2;ll sss = s;PER(i, 20) {ll up = ll(1) << i;if (d[sss] - up <= dd)continue;sss = lc[sss][i].first;}auto [p, ip] = lc[sss][0];cout << n - pc[p] - c[p][ip] << "\n";}}}int main() {ll t = 1;//cin >> t;while (t--) {solve();}return 0;}