結果
問題 | No.1073 無限すごろく |
ユーザー |
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提出日時 | 2023-06-07 23:32:12 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 3 ms / 2,000 ms |
コード長 | 3,511 bytes |
コンパイル時間 | 2,044 ms |
コンパイル使用メモリ | 174,116 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-12-30 05:16:21 |
合計ジャッジ時間 | 3,170 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 30 |
ソースコード
#include <bits/stdc++.h>using namespace std;#define rep(i,n) for (int i = 0; i < (int)(n); ++i)#define rrep(i,n) for (int i = (int)(n-1); i >= 0; --i)#define Rep(i,a,b) for (int i = a; i < b; ++i)#define rRep(i,a,b) for (int i = a; i > b; --i)#define fore(i,a) for(auto &i:a)#define all(v) (v).begin(),(v).end()#define rall(v) (v).rbegin(),(v).rend()#define Unique(v) v.erase(unique(v.begin(), v.end()), v.end());#define Bit(x,i) (((x)>>(i))&1)using ll = long long;using vi = vector<int>;using vll = vector<long long>;using vvi = vector<vi>;using vvll = vector<vll>;using vb = vector<bool>;using vs = vector<string>;using pii = pair<int, int>;using pll = pair<ll, ll>;template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }struct settings{settings(){ios_base::sync_with_stdio(0); cin.tie(0); cout<<fixed<<setprecision(15);};}settingss;const double PI = acos(-1);const int INF = 1001001001;const ll LINF = 1001001001001001001LL;const int mod = 1000000007;class modint {long long x;public:modint(long long x=0) : x((x%mod+mod)%mod) {}modint operator-() const {return modint(-x);}modint& operator+=(const modint& a) {if ((x += a.x) >= mod) x -= mod;return *this;}modint& operator-=(const modint& a) {if ((x += mod-a.x) >= mod) x -= mod;return *this;}modint& operator*=(const modint& a) {(x *= a.x) %= mod;return *this;}modint operator+(const modint& a) const {modint res(*this);return res+=a;}modint operator-(const modint& a) const {modint res(*this);return res-=a;}modint operator*(const modint& a) const {modint res(*this);return res*=a;}modint pow(ll t) const {if (!t) return 1;modint a = pow(t>>1);a *= a;if (t&1) a *= *this;return a;}modint inv() const {return pow(mod-2);}modint& operator/=(const modint& a) {return (*this) *= a.inv();}modint operator/(const modint& a) const {modint res(*this);return res/=a;}friend ostream& operator<<(ostream& os, const modint& m){os << m.x;return os;}};// given: a_0, ..., a_k-1 and d_0, ..., d_k-1// a_k = d_0 a_0 + d_1 a_1 + ... + d_k-1 a_k-1template<typename T>struct Kitamasa{vector<T> a;vector<T> d;int k;Kitamasa(vector<T>& a, vector<T>& d) : a(a), d(d), k((int)a.size()) {}vector<T> dfs(ll n){if(n == k) return d;vector<T> res(k);if(n & 1 || n < k * 2) {vector<T> x = dfs(n - 1);for(int i = 0; i < k; ++i) res[i] = d[i] * x[k - 1];for(int i = 0; i + 1 < k; ++i) res[i + 1] += x[i];} else {vector<vector<T>> x(k, vector<T>(k));x[0] = dfs(n >> 1);for(int i = 0; i + 1 < k; ++i) {for(int j = 0; j < k; ++j) x[i + 1][j] = d[j] * x[i][k - 1];for(int j = 0; j + 1 < k; ++j) x[i + 1][j + 1] += x[i][j];}for(int i = 0; i < k; ++i) {for(int j = 0; j < k; ++j) {res[j] += x[0][i] * x[i][j];}}}return res;}T calc(ll n){if(n < k) return a[n];vector<T> x = dfs(n);T res = 0;for(int i = 0; i < k; ++i) res += x[i] * a[i];return res;}};int main() {ll N; cin >> N;vector<modint> a(6, 0);a[5] = 1;modint dv = 1;dv /= 6;vector<modint> d(6, dv);Kitamasa<modint> Kita(a, d);cout << Kita.calc(N+5) << endl;}