結果

問題 No.1073 無限すごろく
ユーザー rnanornano
提出日時 2023-06-07 23:32:12
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 3,511 bytes
コンパイル時間 2,044 ms
コンパイル使用メモリ 174,116 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-12-30 05:16:21
合計ジャッジ時間 3,170 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for (int i = 0; i < (int)(n); ++i)
#define rrep(i,n) for (int i = (int)(n-1); i >= 0; --i)
#define Rep(i,a,b) for (int i = a; i < b; ++i)
#define rRep(i,a,b) for (int i = a; i > b; --i)
#define fore(i,a) for(auto &i:a)
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define Unique(v) v.erase(unique(v.begin(), v.end()), v.end());
#define Bit(x,i) (((x)>>(i))&1)
using ll = long long;
using vi = vector<int>;
using vll = vector<long long>;
using vvi = vector<vi>;
using vvll = vector<vll>;
using vb = vector<bool>;
using vs = vector<string>;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
struct settings{settings(){ios_base::sync_with_stdio(0); cin.tie(0); cout<<fixed<<setprecision(15);};}settingss;
const double PI = acos(-1);
const int INF = 1001001001;
const ll LINF = 1001001001001001001LL;
const int mod = 1000000007;
class modint {
long long x;
public:
modint(long long x=0) : x((x%mod+mod)%mod) {}
modint operator-() const {
return modint(-x);
}
modint& operator+=(const modint& a) {
if ((x += a.x) >= mod) x -= mod;
return *this;
}
modint& operator-=(const modint& a) {
if ((x += mod-a.x) >= mod) x -= mod;
return *this;
}
modint& operator*=(const modint& a) {
(x *= a.x) %= mod;
return *this;
}
modint operator+(const modint& a) const {
modint res(*this);
return res+=a;
}
modint operator-(const modint& a) const {
modint res(*this);
return res-=a;
}
modint operator*(const modint& a) const {
modint res(*this);
return res*=a;
}
modint pow(ll t) const {
if (!t) return 1;
modint a = pow(t>>1);
a *= a;
if (t&1) a *= *this;
return a;
}
modint inv() const {
return pow(mod-2);
}
modint& operator/=(const modint& a) {
return (*this) *= a.inv();
}
modint operator/(const modint& a) const {
modint res(*this);
return res/=a;
}
friend ostream& operator<<(ostream& os, const modint& m){
os << m.x;
return os;
}
};
// given: a_0, ..., a_k-1 and d_0, ..., d_k-1
// a_k = d_0 a_0 + d_1 a_1 + ... + d_k-1 a_k-1
template<typename T>
struct Kitamasa{
vector<T> a;
vector<T> d;
int k;
Kitamasa(vector<T>& a, vector<T>& d) : a(a), d(d), k((int)a.size()) {}
vector<T> dfs(ll n){
if(n == k) return d;
vector<T> res(k);
if(n & 1 || n < k * 2) {
vector<T> x = dfs(n - 1);
for(int i = 0; i < k; ++i) res[i] = d[i] * x[k - 1];
for(int i = 0; i + 1 < k; ++i) res[i + 1] += x[i];
} else {
vector<vector<T>> x(k, vector<T>(k));
x[0] = dfs(n >> 1);
for(int i = 0; i + 1 < k; ++i) {
for(int j = 0; j < k; ++j) x[i + 1][j] = d[j] * x[i][k - 1];
for(int j = 0; j + 1 < k; ++j) x[i + 1][j + 1] += x[i][j];
}
for(int i = 0; i < k; ++i) {
for(int j = 0; j < k; ++j) {
res[j] += x[0][i] * x[i][j];
}
}
}
return res;
}
T calc(ll n){
if(n < k) return a[n];
vector<T> x = dfs(n);
T res = 0;
for(int i = 0; i < k; ++i) res += x[i] * a[i];
return res;
}
};
int main() {
ll N; cin >> N;
vector<modint> a(6, 0);
a[5] = 1;
modint dv = 1;
dv /= 6;
vector<modint> d(6, dv);
Kitamasa<modint> Kita(a, d);
cout << Kita.calc(N+5) << endl;
}
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