結果

問題 No.1983 [Cherry 4th Tune C] 南の島のマーメイド
ユーザー koba-e964koba-e964
提出日時 2023-06-13 00:15:37
言語 Rust
(1.77.0 + proconio)
結果
AC  
実行時間 293 ms / 4,000 ms
コード長 6,755 bytes
コンパイル時間 18,386 ms
コンパイル使用メモリ 399,968 KB
実行使用メモリ 106,824 KB
最終ジャッジ日時 2024-06-11 23:44:07
合計ジャッジ時間 26,856 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 1 ms
6,812 KB
testcase_01 AC 1 ms
6,816 KB
testcase_02 AC 1 ms
6,812 KB
testcase_03 AC 1 ms
6,940 KB
testcase_04 AC 1 ms
6,944 KB
testcase_05 AC 1 ms
6,940 KB
testcase_06 AC 1 ms
6,944 KB
testcase_07 AC 1 ms
6,944 KB
testcase_08 AC 4 ms
6,940 KB
testcase_09 AC 6 ms
6,940 KB
testcase_10 AC 9 ms
6,940 KB
testcase_11 AC 9 ms
6,940 KB
testcase_12 AC 5 ms
6,944 KB
testcase_13 AC 125 ms
31,468 KB
testcase_14 AC 161 ms
35,676 KB
testcase_15 AC 191 ms
45,052 KB
testcase_16 AC 65 ms
28,260 KB
testcase_17 AC 164 ms
36,164 KB
testcase_18 AC 187 ms
44,544 KB
testcase_19 AC 250 ms
53,364 KB
testcase_20 AC 177 ms
42,148 KB
testcase_21 AC 202 ms
40,872 KB
testcase_22 AC 221 ms
43,776 KB
testcase_23 AC 275 ms
57,268 KB
testcase_24 AC 279 ms
57,260 KB
testcase_25 AC 293 ms
58,136 KB
testcase_26 AC 271 ms
58,060 KB
testcase_27 AC 282 ms
57,324 KB
testcase_28 AC 276 ms
57,200 KB
testcase_29 AC 257 ms
57,216 KB
testcase_30 AC 284 ms
58,684 KB
testcase_31 AC 264 ms
57,640 KB
testcase_32 AC 269 ms
58,304 KB
testcase_33 AC 1 ms
6,944 KB
testcase_34 AC 58 ms
27,064 KB
testcase_35 AC 132 ms
78,600 KB
testcase_36 AC 113 ms
42,292 KB
testcase_37 AC 1 ms
6,940 KB
testcase_38 AC 31 ms
6,940 KB
testcase_39 AC 183 ms
106,824 KB
testcase_40 AC 126 ms
56,832 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

use std::io::{Write, BufWriter};
// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
    ($($r:tt)*) => {
        let stdin = std::io::stdin();
        let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));
        let mut next = move || -> String{
            bytes.by_ref().map(|r|r.unwrap() as char)
                .skip_while(|c|c.is_whitespace())
                .take_while(|c|!c.is_whitespace())
                .collect()
        };
        input_inner!{next, $($r)*}
    };
}

macro_rules! input_inner {
    ($next:expr) => {};
    ($next:expr,) => {};
    ($next:expr, $var:ident : $t:tt $($r:tt)*) => {
        let $var = read_value!($next, $t);
        input_inner!{$next $($r)*}
    };
}

macro_rules! read_value {
    ($next:expr, ( $($t:tt),* )) => { ($(read_value!($next, $t)),*) };
    ($next:expr, [ $t:tt ; $len:expr ]) => {
        (0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
    };
    ($next:expr, usize1) => (read_value!($next, usize) - 1);
    ($next:expr, $t:ty) => ($next().parse::<$t>().expect("Parse error"));
}

// Verified by: https://codeforces.com/contest/700/submission/165850980
// This function uses O(n) stack space.
mod tecomp {
    use std::cmp::min;
    const INF: usize = 1 << 28;
    fn dfs<EIdx: Copy + PartialEq>(v: usize, paridx: EIdx, g: &[Vec<(usize, EIdx)>],
           ord: &mut [usize], low: &mut [usize], k: &mut usize,
           bridges: &mut Vec<EIdx>) {
        ord[v] = *k;
        low[v] = *k;
        *k += 1;
        for &(w, eidx) in g[v].iter() {
            if paridx == eidx { continue; }
            if ord[w] < ord[v] {
                low[v] = min(low[v], ord[w]);
            } else if ord[w] == INF {
                dfs(w, eidx, g, ord, low, k, bridges);
                low[v] = min(low[v], low[w]);
                if ord[v] < low[w] {
                    bridges.push(eidx);
                }
            }
        }
    }
    fn dfs_comp<EIdx: Copy>(
        v: usize, g: &[Vec<(usize, EIdx)>],
        ord: &[usize], low: &[usize],
        cur_becomp: usize, becomp_count: &mut usize, becomp: &mut [usize], tree: &mut [Vec<(usize, EIdx)>],
        vis: &mut [bool],
    ) {
        becomp[v] = cur_becomp;
        vis[v] = true;
        for &(w, eidx) in g[v].iter() {
            if ord[w] > ord[v] && !vis[w] {
                if ord[v] < low[w] {
                    *becomp_count += 1;
                    tree[cur_becomp].push((*becomp_count, eidx));
                    dfs_comp(w, g, ord, low, *becomp_count, becomp_count, becomp, tree, vis);
                } else {
                    dfs_comp(w, g, ord, low, cur_becomp, becomp_count, becomp, tree, vis);
                }
            }
        }
    }

    type EIdx = usize;

    // Returns (the number of 2-edge connected components, [the id of the component v belongs to | v <- [0 .. g.len()]], the resulting tree, the ids of bridges).
    // Graphs are given and provided in the adjacent list format. (to, edge_id).
    // The provided tree has its own vertex ids, but edge ids are reused.
    // This function uses O(n) stack space.
    pub fn decomp(g: &[Vec<(usize, EIdx)>])
                 -> (usize, Vec<usize>, Vec<Vec<(usize, EIdx)>>, Vec<EIdx>) {
        let n_vert = g.len();
        let mut ord = vec![INF; n_vert];
        let mut low = vec![INF; n_vert];
        let mut k = 0;
        let mut becomp_count = 0;
        let mut becomp = vec![INF; n_vert];
        let mut bridges = Vec::new();
        // rooted forest
        let mut tree = vec![Vec::new(); n_vert];
        let mut vis = vec![false; n_vert];
        for i in 0 .. n_vert {
            if !vis[i] {
                dfs(i, !0, &g, &mut ord, &mut low, &mut k, &mut bridges);
                dfs_comp(i, &g, &ord, &low,
                         becomp_count, &mut becomp_count, &mut becomp,
                         &mut tree, &mut vis);
                becomp_count += 1;
            }
        }
        tree = tree[..becomp_count].to_vec();
        (becomp_count, becomp, tree, bridges)
    }
} // mod tecomp

// Union-Find tree.
// Verified by https://atcoder.jp/contests/pakencamp-2019-day3/submissions/9253305
struct UnionFind { disj: Vec<usize>, rank: Vec<usize> }

impl UnionFind {
    fn new(n: usize) -> Self {
        let disj = (0..n).collect();
        UnionFind { disj: disj, rank: vec![1; n] }
    }
    fn root(&mut self, x: usize) -> usize {
        if x != self.disj[x] {
            let par = self.disj[x];
            let r = self.root(par);
            self.disj[x] = r;
        }
        self.disj[x]
    }
    fn unite(&mut self, x: usize, y: usize) {
        let mut x = self.root(x);
        let mut y = self.root(y);
        if x == y { return }
        if self.rank[x] > self.rank[y] {
            std::mem::swap(&mut x, &mut y);
        }
        self.disj[x] = y;
        self.rank[y] += self.rank[x];
    }
    #[allow(unused)]
    fn is_same_set(&mut self, x: usize, y: usize) -> bool {
        self.root(x) == self.root(y)
    }
    #[allow(unused)]
    fn size(&mut self, x: usize) -> usize {
        let x = self.root(x);
        self.rank[x]
    }
}

fn main() {
    // In order to avoid potential stack overflow, spawn a new thread.
    let stack_size = 104_857_600; // 100 MB
    let thd = std::thread::Builder::new().stack_size(stack_size);
    thd.spawn(|| solve()).unwrap().join().unwrap();
}

// https://yukicoder.me/problems/no/1983 (3.5)
// 関節点と橋を求め、橋だけで関節点・次数 1 の頂点すべてを繋いだときに同じ連結成分に属しているかどうか。
// パスが一意 => 構成する辺は全て橋: 橋以外が含まれているとそれを除去した時連結なので別のパスが取れる。
// パスが一意 => 通過する頂点はすべて関節点 or 次数 1: => そうでないとそれを除去した時、連結なままなので別のパスが取れる。
// 橋の両端は関節点 or 次数 1 であるため、後者の条件はいらないはず。
fn solve() {
    let out = std::io::stdout();
    let mut out = BufWriter::new(out.lock());
    macro_rules! puts {($($format:tt)*) => (let _ = write!(out,$($format)*););}
    input! {
        n: usize, m: usize, q: usize,
        uv: [(usize1, usize1); m],
        xy: [(usize1, usize1); q],
    }
    let mut uf = UnionFind::new(n);
    let mut g = vec![vec![]; n];
    for i in 0..m {
        let (u, v) = uv[i];
        g[u].push((v, i));
        g[v].push((u, i));
    }
    let (_, _, _, bridges) = tecomp::decomp(&g);
    for &idx in &bridges {
        let (u, v) = uv[idx];
        uf.unite(u, v);
    }
    for (x, y) in xy {
        puts!("{}\n", if uf.is_same_set(x, y) { "Yes" } else { "No" });
    }
}
0