結果
問題 | No.2225 Treasure Searching Rod (Easy) |
ユーザー |
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提出日時 | 2023-06-13 21:36:42 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 80 ms / 2,000 ms |
コード長 | 3,886 bytes |
コンパイル時間 | 1,763 ms |
コンパイル使用メモリ | 129,628 KB |
最終ジャッジ日時 | 2025-02-14 02:26:12 |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 23 |
ソースコード
#include <string.h>#include <algorithm>#include <array>#include <bitset>#include <cassert>#include <cfloat>#include <chrono>#include <ciso646>#include <climits>#include <cmath>#include <complex>#include <cstdio>#include <functional>#include <iomanip>#include <iostream>#include <map>#include <numeric>#include <optional>#include <queue>#include <random>#include <set>#include <stack>#include <string>#include <unordered_map>#include <unordered_set>#include <utility>#include <vector>#define REP_OVERLOAD(arg1, arg2, arg3, arg4, NAME, ...) NAME#define REP3(i, l, r, s) \for (int i = int(l), rep3_r = int(r), rep3_s = int(s); i < rep3_r; \i += rep3_s)#define REP2(i, l, r) REP3(i, l, r, 1)#define REP1(i, n) REP2(i, 0, n)#define rep(...) REP_OVERLOAD(__VA_ARGS__, REP3, REP2, REP1, )(__VA_ARGS__)#define repin(i, l, r) for (int i = int(l), repin_r = int(r); i <= repin_r; ++i)#define RREP_OVERLOAD(arg1, arg2, arg3, arg4, NAME, ...) NAME#define RREP3(i, l, r, s) \for (int i = int(r) - 1, rrep3_l = int(l), rrep3_s = int(s); i >= rrep3_l; \i -= rrep3_s)#define RREP2(i, l, r) RREP3(i, l, r, 1)#define RREP1(i, n) RREP2(i, 0, n)#define rrep(...) RREP_OVERLOAD(__VA_ARGS__, RREP3, RREP2, RREP1, )(__VA_ARGS__)#define rrepin(i, l, r) \for (int i = int(r), rrepin_l = int(l); i >= rrepin_l; --i)#include <algorithm>#include <cassert>#include <vector>namespace rklib {// a <- max(a, b)template <class T>bool chmax(T &a, const T &b) {if (a < b) {a = b;return true;}return false;}// a <- min(a, b)template <class T>bool chmin(T &a, const T &b) {if (a > b) {a = b;return true;}return false;}// if a < 0: a <- b// else: a <- min(a, b)template <class T>bool chmin_non_negative(T &a, const T &b) {if (a < 0 || a > b) {a = b;return true;}return false;}// floor(num / den)template <class T>T div_floor(T num, T den) {if (den < 0) num = -num, den = -den;return num >= 0 ? num / den : (num + 1) / den - 1;}// ceil(num / den)template <class T>T div_ceil(T num, T den) {if (den < 0) num = -num, den = -den;return num <= 0 ? num / den : (num - 1) / den + 1;}namespace internal {template <class T>T remainder_count(T r, T b, T m) {return r / m * b + std::min(b, r % m);}} // namespace internal// Number of integer x s.t.// - x in [l, r)// - x mod m in [a, b)template <class T>T remainder_count(T l, T r, T a, T b, T m) {assert(l >= 0);assert(m >= 1);if (l >= r || a >= b) return 0;if (m <= a || b < 0) return 0;chmax(a, T(0));chmin(b, m);auto res = internal::remainder_count(r, b, m);if (l >= 1) res -= internal::remainder_count(l, b, m);if (a >= 1) res -= internal::remainder_count(r, a, m);if (l >= 1 && a >= 1) res += internal::remainder_count(l, a, m);return res;}} // namespace rklibusing namespace std;using namespace rklib;using lint = long long;using pii = pair<int, int>;using pll = pair<lint, lint>;#include <atcoder/modint>using mint = atcoder::modint998244353;lint g(lint x) { return x * (x + 1) / 2; }lint f(lint l, lint r) { return g(r) - g(l - 1); }int main() {int h, w, K;cin >> h >> w >> K;mint ans = 0;rep(kk, K) {int x, y, v;cin >> x >> y >> v;lint tmp = 0;if (y - x + 1 >= 1) {tmp += f(1, x);} else {tmp += f(x - y + 1, x);}y = w - y + 1;if (y - x + 1 >= 1) {tmp += f(1, x);} else {tmp += f(x - y + 1, x);}tmp -= x;ans += mint(tmp) * v;}printf("%u\n", ans.val());}