結果
問題 | No.2374 ASKT Subsequences |
ユーザー |
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提出日時 | 2023-06-16 11:21:48 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 3,965 bytes |
コンパイル時間 | 1,149 ms |
コンパイル使用メモリ | 110,748 KB |
最終ジャッジ日時 | 2025-02-14 03:41:23 |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 2 WA * 26 |
ソースコード
#include <algorithm> #include <iostream> #include <iomanip> #include <limits.h> #include <map> #include <math.h> #include <numeric> #include <queue> #include <set> #include <sstream> #include <string> #include <utility> #include <vector> #include <stack> #include <complex> using namespace std; #define rep(i, n) for (int i = 0; i < n; i++) #define rep1(i, n) for (int i = 1; i < n + 1; i++) #define rev(i, n) for (int i = n - 1; i >= 0; i--) #define all(A) A.begin(), A.end() #define itr(A, l, r) A.begin() + l, A.begin() + r #define debug(var) cout << #var << " = " << var << endl; typedef long long ll; template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << "(" << p.first << "," << p.second << ")"; return os; } template <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; } template <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { for (int i = 0; i < (int)v.size(); i++) { os << v[i] << (i + 1 != (int)v.size() ? " " : ""); } return os; } template <typename T> ostream &operator<<(ostream &os, const vector<vector<T>> &v) { for (int i = 0; i < (int)v.size(); i++) { os << v[i] << endl; } return os; } template <typename T> ostream &operator<<(ostream &os, const vector<vector<vector<T>>> &v) { for (int i = 0; i < (int)v.size(); i++) { os << "i = " << i << endl; os << v[i]; } return os; } template <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; } template <typename T, typename S> ostream &operator<<(ostream &os, map<T, S> &mp) { for (auto &[key, val] : mp) { os << key << ":" << val << " "; } cout << endl; return os; } template <typename T> ostream &operator<<(ostream &os, set<T> st) { auto itr = st.begin(); for (int i = 0; i < (int)st.size(); i++) { os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; } template <typename T> ostream &operator<<(ostream &os, multiset<T> st) { auto itr = st.begin(); for (int i = 0; i < (int)st.size(); i++) { os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; } template <typename T> ostream &operator<<(ostream &os, queue<T> q) { while (q.size()) { os << q.front() << " "; q.pop(); } return os; } template <typename T> ostream &operator<<(ostream &os, deque<T> q) { while (q.size()) { os << q.front() << " "; q.pop_front(); } return os; } template <typename T> ostream &operator<<(ostream &os, stack<T> st) { while (st.size()) { os << st.top() << " "; st.pop(); } return os; } template <typename T> ostream &operator<<(ostream &os, priority_queue<T> pq) { while (pq.size()) { os << pq.top() << " "; pq.pop(); } return os; } template <typename T> ostream &operator<<(ostream &os, priority_queue<T, vector<T>, greater<T>> mpq) { while (mpq.size()) { os << mpq.top() << " "; mpq.pop(); } return os; } int main() { int n; cin >> n; vector<int> a(n); cin >> a; ll ans = 0; rep(d, 10) { // debug(d); vector<vector<int>> dp(n, vector<int>(4)); dp[0][0] = 1; rep(i, n) { rep(k, i) { dp[i][1] += dp[k][0] * (a[k] == a[i] - d - 10); } rep(k, i) { dp[i][2] += dp[k][1] * (a[k] == a[i] + d); } rep(k, i) { dp[i][3] += dp[k][2] * (a[k] == a[i] - d - 1); } } // cout << dp << endl; rep(i, n) { ans += dp[i][3]; } } cout << ans << endl; }