結果

問題 No.492 IOI数列
ユーザー 👑 CleyL
提出日時 2023-06-20 15:08:13
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 3,947 bytes
コンパイル時間 912 ms
コンパイル使用メモリ 80,704 KB
最終ジャッジ日時 2025-02-14 23:23:13
ジャッジサーバーID
（参考情報） 		judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 9 WA * 10
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ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <vector>
using namespace std;
const long long MOD = 1000000007;
template <int mod>
struct ModInt{
  int n;
  ModInt():n(0){}
  ModInt(int n_):n(n_ >= 0 ? n_%mod : mod - ((-n_)%mod) ){}
  ModInt &operator+=(const ModInt &p){
    if((n+=p.n) >= mod)n-=mod;
    return *this;
  }
  ModInt &operator-=(const ModInt &p){
    n+=mod-p.n;
    if(n >= mod)n-=mod;
    return *this;
  }
  ModInt &operator*=(const ModInt &p){
    n = (int) ((1LL*n*p.n)%mod);
    return *this;
  }
  ModInt &operator/=(const ModInt &p){
    *this *= p.inverse();
    return *this;
  }
  ModInt operator-() const {return ModInt(-n);}
  ModInt operator+(const ModInt &p) const {return ModInt(*this) += p;}
  ModInt operator-(const ModInt &p) const {return ModInt(*this) -= p;}
  ModInt operator*(const ModInt &p) const {return ModInt(*this) *= p;}
  ModInt operator/(const ModInt &p) const {return ModInt(*this) /= p;}
  bool operator==(const ModInt &p) const {return n==p.n;}
    bool operator<(const ModInt &p) const {return n<p.n;}
    bool operator>(const ModInt &p) const {return n>p.n;}
    bool operator>=(const ModInt &p) const {return n>=p.n;}
    bool operator<=(const ModInt &p) const {return n<=p.n;}
  bool operator!=(const ModInt &p) const {return n!=p.n;}
  ModInt inverse() const {
    int a = n,b = mod,u = 1,v = 0;
    while(b){
      int t = a/b;
      a -= t*b; swap(a,b);
      u -= t*v; swap(u,v);
    }
    return ModInt(u);
  }
  ModInt pow(int64_t z) const {
    ModInt ret(1),mul(n);
    while(z > 0){
      if(z & 1) ret *= mul;
      mul *= mul;
      z >>= 1;
    }
    return ret;
  }
  friend ostream &operator<<(ostream &os, const ModInt &p){
    return os << p.n;
  }
  friend istream &operator>>(istream &is, ModInt &a){
    int64_t t;
    is >> t;
    a = ModInt<mod> (t);
    return (is);
  }
};
using mint = ModInt<MOD>;
template <typename T>
struct mat{
  vector<vector<T>> x;
  int h,w;
  mat():x(vector<vector<T>>()){}
  mat(int h,int w):x(vector<vector<T>>(h,vector<T>(w))),h(h),w(w){}
  mat(int h,int w, T c):x(vector<vector<T>>(h,vector<T>(w,c))),h(h),w(w){}
  mat(vector<vector<T>> A):x(A),h(A.size()),w(A[0].size()){}
  vector<T>& operator[](int i){return x[i];}
  
  mat& operator*=(mat& y){
    mat<T> ret(h,y.w,0);
    if(w != y.h){
      for(int i = 0; h > i; i++){
        for(int j = 0; y.w > j; j++){
          ret[i][j] = -1;
        }
      }
    }else{
      for(int i = 0; h > i; i++){
        for(int j = 0; y.w > j; j++){
          for(int k = 0; w > k; k++){
            ret[i][j] = ret[i][j] + x[i][k]*y[k][j];
          }
        }
      }
    }
    for(int i = 0; h > i; i++){
      x[i].resize(y.w);
    }
    w = y.w;
    for(int i = 0; h > i; i++){
      for(int j = 0; y.w > j; j++){
        x[i][j] = ret[i][j];
      }
    }
    return *this;
  }
  mat operator*(mat& y){return mat(*this) *= y;}
  mat pow(long long n){//正方行列のみ
    mat<T> res(h,w);
    mat<T> ret(h,w,0);
    mat<T> a(h,w);
    for(int i = 0; h > i; i++){
      ret[i][i] = 1;
    }
    for(int i = 0; h > i; i++){
      for(int j = 0; w > j; j++){
        a[i][j] = (*this)[i][j];
      }
    }
    while(n > 0){
      if(n & 1){
        ret *= a;
      }
      a *= a;
      n/=2;
    }
    for(int i = 0; h > i; i++){
      for(int j = 0; w > j; j++){
        res[i][j] = ret[i][j];
      }
    }
    return res;
  }
  friend ostream &operator<<(ostream &os, const mat &m){
    for(int i = 0; m.h > i; i++){
      for(int j = 0; m.w > j; j++){
        os << m.x[i][j];
        if(j+1 != m.w)cout << " ";
      }
      if(i+1 != m.h)cout << "\n";
    }
    return os;
  }
};
int main(){
  long long n;cin>>n;
  mat<mint> A(3,3);
  A[0][0] = A[1][1] = 100;
  A[2][0] = A[2][1] = A[2][2] = 1;
  mat<mint> B(1,3);
  B[0][0] = 0;
  B[0][1] = 1;
  B[0][2] = 1;
  A = A.pow(n);
  cout << (B*A)[0][0] << endl;
  n=(n-1)%9;
  for(int i = 0; n > i; i++){
    cout << "10";
  }
  cout << "1" << endl;
}
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