結果

問題 No.2361 Many String Compare Queries
ユーザー dyktr_06dyktr_06
提出日時 2023-06-23 23:37:02
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 6,837 bytes
コンパイル時間 6,730 ms
コンパイル使用メモリ 305,296 KB
実行使用メモリ 14,764 KB
最終ジャッジ日時 2024-07-01 03:24:18
合計ジャッジ時間 11,592 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge1
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 2 ms
5,376 KB
testcase_02 AC 2 ms
5,376 KB
testcase_03 AC 2 ms
5,376 KB
testcase_04 WA -
testcase_05 AC 2 ms
5,376 KB
testcase_06 WA -
testcase_07 AC 2 ms
5,376 KB
testcase_08 WA -
testcase_09 WA -
testcase_10 WA -
testcase_11 AC 461 ms
13,824 KB
testcase_12 AC 455 ms
13,708 KB
testcase_13 AC 383 ms
13,788 KB
testcase_14 WA -
testcase_15 WA -
権限があれば一括ダウンロードができます

ソースコード

diff # 

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")

#include <bits/stdc++.h>
#include <atcoder/all>

using namespace std;
using namespace atcoder;

#define overload4(_1, _2, _3, _4, name, ...) name
#define rep1(n) for(int i = 0; i < (int)(n); ++i)
#define rep2(i, n) for(int i = 0; i < (int)(n); ++i)
#define rep3(i, a, b) for(int i = (a); i < (int)(b); ++i)
#define rep4(i, a, b, c) for(int i = (a); i < (int)(b); i += (c))
#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)

#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; --i)
#define ALL(a) a.begin(), a.end()
#define Sort(a) sort(a.begin(), a.end())
#define RSort(a) sort(a.rbegin(), a.rend())

typedef long long int ll;
typedef unsigned long long ul;
typedef long double ld;
typedef vector<int> vi;
typedef vector<long long> vll;
typedef vector<char> vc;
typedef vector<string> vst;
typedef vector<double> vd;
typedef vector<long double> vld;
typedef pair<long long, long long> P;

template<class T> long long sum(const T& a){ return accumulate(a.begin(), a.end(), 0LL); }
template<class T> auto min(const T& a){ return *min_element(a.begin(), a.end()); }
template<class T> auto max(const T& a){ return *max_element(a.begin(), a.end()); }

const long long MINF = 0x7fffffffffff;
const long long INF = 0x1fffffffffffffff;
const long long MOD = 998244353;
const long double EPS = 1e-9;
const long double PI = acos(-1);
 
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

template<typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p){ is >> p.first >> p.second; return is; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){ os << "(" << p.first << ", " << p.second << ")"; return os; }
template<typename T> istream &operator>>(istream &is, vector<T> &v){ for(T &in : v) is >> in; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &v){ for(int i = 0; i < (int) v.size(); ++i){ os << v[i] << (i + 1 != (int) v.size() ? " " : ""); } return os; }
template <typename T, typename S> ostream &operator<<(ostream &os, const map<T, S> &mp){ for(auto &[key, val] : mp){ os << key << ":" << val << " "; } return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, queue<T> q){ while(q.size()){ os << q.front() << " "; q.pop(); } return os; }
template <typename T> ostream &operator<<(ostream &os, deque<T> q){ while(q.size()){ os << q.front() << " "; q.pop_front(); } return os; }
template <typename T> ostream &operator<<(ostream &os, stack<T> st){ while(st.size()){ os << st.top() << " "; st.pop(); } return os; }
template <class T, class Container, class Compare> ostream &operator<<(ostream &os, priority_queue<T, Container, Compare> pq){ while(pq.size()){ os << pq.top() << " "; pq.pop(); } return os; }

template<class T, class U> inline T vin(T& vec, U n) { vec.resize(n); for(int i = 0; i < (int) n; ++i) cin >> vec[i]; return vec; }
template<class T> inline void vout(T vec, string s = "\n"){ for(auto x : vec) cout << x << s; }
template<class... T> void in(T&... a){ (cin >> ... >> a); }
void out(){ cout << '\n'; }
template<class T, class... Ts> void out(const T& a, const Ts&... b){ cout << a; (cout << ... << (cout << ' ', b)); cout << '\n'; }
template<class T, class U> void inGraph(vector<vector<T>>& G, U n, U m, bool directed = false){ G.resize(n); for(int i = 0; i < m; ++i){ int a, b; cin >> a >> b; a--, b--; G[a].push_back(b); if(!directed) G[b].push_back(a); } }

template <typename X>
struct SegTree{
    using FX = function<X(X, X)>; // X•X -> X となる関数の型
    int n;
    FX fx;
    const X ex;
    vector<X> dat;

    SegTree(int n_, const FX &fx_, const X &ex_) : n(), fx(fx_), ex(ex_){
        int x = 1;
        while(n_ > x){
            x *= 2;
        }
        n = x;
        dat.assign(n * 2, ex);
    }

    X get(int i) const {
        return dat[i + n];
    }
    
    void set(int i, X x){ dat[i + n] = x; }

    void build(){
        for(int k = n - 1; k >= 1; k--) dat[k] = fx(dat[k * 2], dat[k * 2 + 1]);
    }

    void update(int i, X x){
        i += n;
        dat[i] = x;
        while(i > 0){
            i >>= 1;  // parent
            dat[i] = fx(dat[i * 2], dat[i * 2 + 1]);
        }
    }

    X query(int a, int b){
        X vl = ex;
        X vr = ex;
        int l = a + n;
        int r = b + n;
        while(l < r){
            if(l & 1) vl = fx(vl, dat[l++]);
            if(r & 1) vr = fx(dat[--r], vr);
            l >>= 1;
            r >>= 1;
        }
        return fx(vl, vr);
    }
    
    X operator [](int i) const {
        return dat[i + n];
    }
};

ll n, q;
string s;

void input(){
    in(n, q, s);
}

void solve(){
    vi sa = suffix_array(s);
    vi la = lcp_array(s, sa);
    vll inv(n);
    rep(i, n){
        inv[sa[i]] = i;
    }
    vll s(n + 1), s2(n);
    rep(i, n) s[i + 1] = s[i] + (n - sa[i]);
    rep(i, n - 1) s2[i + 1] = s2[i] + la[i];

    auto fx = [](ll a, ll b){
        return min(a, b);
    };
    SegTree<ll> seg(n - 1, fx, INF);
    rep(i, n - 1) seg.update(i, la[i]);
    
    while(q--){
        ll l, r; in(l, r); l--, r--;
        ll ans = r - l;
        ll idx = inv[l], len = r - l + 1;

        ll ok = idx, ng = n;
        while(abs(ok - ng) > 1){
            ll mid = (ok + ng) / 2;
            if(seg.query(idx, mid + 1) >= len){
                ok = mid;
            }else{
                ng = mid;
            }
        }

        idx = ok;
        if(idx == 0){
            out(ans);
            continue;
        }

        ll ok2 = idx, ng2 = -1;
        while(abs(ok2 - ng2) > 1){
            ll mid = (ok2 + ng2) / 2;
            if(seg.query(mid, idx) >= len){
                ok2 = mid;
            }else{
                ng2 = mid;
            }
        }

        ll ok3 = ok, ng3 = n;
        while(abs(ok3 - ng3) > 1){
            ll mid = (ok3 + ng3) / 2;
            if(seg.query(ok, mid) >= 1){
                ok3 = mid;
            }else{
                ng3 = mid;
            }
        }
        ans += s[ok2] + (idx - ok2) * (r - l);
        if(len >= 2) ans += s2[ok3] - s2[idx];
        out(ans);
    }
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    
    input();
    solve();
}
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