結果
| 問題 |
No.2368 I love a square root of 2
|
| コンテスト | |
| ユーザー |
Nachia
|
| 提出日時 | 2023-06-30 21:47:19 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 75 ms / 2,000 ms |
| コード長 | 2,749 bytes |
| コンパイル時間 | 1,014 ms |
| コンパイル使用メモリ | 83,116 KB |
| 最終ジャッジ日時 | 2025-02-15 03:44:03 |
|
ジャッジサーバーID (参考情報) |
judge1 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 20 |
ソースコード
#line 1 "..\\Main.cpp"
#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <atcoder/modint>
#line 2 "D:\\Programming\\VSCode\\competitive-cpp\\nachia\\math\\floor-of-kth-root.hpp"
#include <cassert>
namespace nachia{
namespace internal{
// mod 2^64
constexpr unsigned long long PowerOfULongLong(unsigned long long a, unsigned long long i){
unsigned long long res = 1;
while(i){ if(i&1){ res *= a; } i /= 2; a *= a; }
return res;
}
}
unsigned long long FloorOfKthRoot(unsigned long long real, unsigned long long k){
using u64 = unsigned long long;
assert(k != 0);
if(real <= 1) return real;
if(k >= 64) return 1;
if(k == 1) return real;
struct Precalc{
// a^i <= x
static constexpr bool lesseq(u64 a, int i, u64 x) {
if (a == 0) return true;
for(int j=0; j<i; j++) x /= a;
return x >= 1;
}
unsigned long long BORDER[64];
constexpr Precalc() : BORDER() {
for (int idx = 2; idx <= 63; idx++) {
u64 l = 0, r = 1ull << 33;
while (l + 1 < r) {
u64 m = (l + r) / 2;
if (lesseq(m, idx, ~0ull)) l = m;
else r = m;
}
BORDER[idx] = r;
}
};
};
constexpr Precalc precalc;
u64 l = 0, r = precalc.BORDER[k];
while (l + 1 < r) {
u64 m = (l + r) / 2;
if(internal::PowerOfULongLong(m, k) <= real) l = m;
else r = m;
}
return l;
}
unsigned long long CeilOfKthRoot(unsigned long long real, unsigned long long k){
if(real <= 1) return real;
if(k >= 64) return 2;
if(k == 1) return real;
unsigned long long x = FloorOfKthRoot(real, k);
if(internal::PowerOfULongLong(x, k) != real) x++;
return x;
}
} // namespace nachia
#line 8 "..\\Main.cpp"
using namespace std;
using i32 = int;
using u32 = unsigned int;
using i64 = long long;
using u64 = unsigned long long;
#define rep(i,n) for(int i=0; i<(int)(n); i++)
const i64 INF = 1001001001001001001;
using Modint = atcoder::static_modint<998244353>;
int main(){
i64 N; cin >> N;
i64 x = 0;
while(true){
i64 c = nachia::FloorOfKthRoot(x*x/2, 2) + 1;
if(c >= N) break;
N -= c;
x++;
}
vector<pair<i64, i64>> A;
for(i64 y=0; y*y*2<=x*x; y++) A.emplace_back(y, x - nachia::CeilOfKthRoot(y*y*2, 2));
sort(A.begin(), A.end(), [](pair<i64, i64> l, pair<i64, i64> r){
i64 x = r.first - l.first;
i64 y = r.second - l.second;
if(x < 0) return x*x*2 < y*y;
return x*x*2 > y*y;
});
cout << A[N-1].second << ' ' << A[N-1].first << endl;
return 0;
}
Nachia