結果
問題 | No.2368 I love a square root of 2 |
ユーザー | 👑 Nachia |
提出日時 | 2023-06-30 21:47:19 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 64 ms / 2,000 ms |
コード長 | 2,749 bytes |
コンパイル時間 | 752 ms |
コンパイル使用メモリ | 84,156 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-07-07 09:27:39 |
合計ジャッジ時間 | 2,057 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
6,816 KB |
testcase_01 | AC | 1 ms
6,940 KB |
testcase_02 | AC | 64 ms
6,940 KB |
testcase_03 | AC | 2 ms
6,944 KB |
testcase_04 | AC | 2 ms
6,940 KB |
testcase_05 | AC | 2 ms
6,940 KB |
testcase_06 | AC | 2 ms
6,944 KB |
testcase_07 | AC | 2 ms
6,940 KB |
testcase_08 | AC | 2 ms
6,944 KB |
testcase_09 | AC | 2 ms
6,940 KB |
testcase_10 | AC | 2 ms
6,944 KB |
testcase_11 | AC | 2 ms
6,940 KB |
testcase_12 | AC | 2 ms
6,944 KB |
testcase_13 | AC | 50 ms
6,944 KB |
testcase_14 | AC | 50 ms
6,944 KB |
testcase_15 | AC | 55 ms
6,944 KB |
testcase_16 | AC | 37 ms
6,944 KB |
testcase_17 | AC | 3 ms
6,944 KB |
testcase_18 | AC | 3 ms
6,944 KB |
testcase_19 | AC | 3 ms
6,944 KB |
testcase_20 | AC | 3 ms
6,944 KB |
testcase_21 | AC | 62 ms
6,940 KB |
testcase_22 | AC | 59 ms
6,944 KB |
ソースコード
#line 1 "..\\Main.cpp" #include <iostream> #include <string> #include <vector> #include <algorithm> #include <atcoder/modint> #line 2 "D:\\Programming\\VSCode\\competitive-cpp\\nachia\\math\\floor-of-kth-root.hpp" #include <cassert> namespace nachia{ namespace internal{ // mod 2^64 constexpr unsigned long long PowerOfULongLong(unsigned long long a, unsigned long long i){ unsigned long long res = 1; while(i){ if(i&1){ res *= a; } i /= 2; a *= a; } return res; } } unsigned long long FloorOfKthRoot(unsigned long long real, unsigned long long k){ using u64 = unsigned long long; assert(k != 0); if(real <= 1) return real; if(k >= 64) return 1; if(k == 1) return real; struct Precalc{ // a^i <= x static constexpr bool lesseq(u64 a, int i, u64 x) { if (a == 0) return true; for(int j=0; j<i; j++) x /= a; return x >= 1; } unsigned long long BORDER[64]; constexpr Precalc() : BORDER() { for (int idx = 2; idx <= 63; idx++) { u64 l = 0, r = 1ull << 33; while (l + 1 < r) { u64 m = (l + r) / 2; if (lesseq(m, idx, ~0ull)) l = m; else r = m; } BORDER[idx] = r; } }; }; constexpr Precalc precalc; u64 l = 0, r = precalc.BORDER[k]; while (l + 1 < r) { u64 m = (l + r) / 2; if(internal::PowerOfULongLong(m, k) <= real) l = m; else r = m; } return l; } unsigned long long CeilOfKthRoot(unsigned long long real, unsigned long long k){ if(real <= 1) return real; if(k >= 64) return 2; if(k == 1) return real; unsigned long long x = FloorOfKthRoot(real, k); if(internal::PowerOfULongLong(x, k) != real) x++; return x; } } // namespace nachia #line 8 "..\\Main.cpp" using namespace std; using i32 = int; using u32 = unsigned int; using i64 = long long; using u64 = unsigned long long; #define rep(i,n) for(int i=0; i<(int)(n); i++) const i64 INF = 1001001001001001001; using Modint = atcoder::static_modint<998244353>; int main(){ i64 N; cin >> N; i64 x = 0; while(true){ i64 c = nachia::FloorOfKthRoot(x*x/2, 2) + 1; if(c >= N) break; N -= c; x++; } vector<pair<i64, i64>> A; for(i64 y=0; y*y*2<=x*x; y++) A.emplace_back(y, x - nachia::CeilOfKthRoot(y*y*2, 2)); sort(A.begin(), A.end(), [](pair<i64, i64> l, pair<i64, i64> r){ i64 x = r.first - l.first; i64 y = r.second - l.second; if(x < 0) return x*x*2 < y*y; return x*x*2 > y*y; }); cout << A[N-1].second << ' ' << A[N-1].first << endl; return 0; }