結果
| 問題 |
No.1320 Two Type Min Cost Cycle
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-07-02 03:23:02 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 824 ms / 2,000 ms |
| コード長 | 3,470 bytes |
| コンパイル時間 | 2,442 ms |
| コンパイル使用メモリ | 212,252 KB |
| 最終ジャッジ日時 | 2025-02-15 05:31:33 |
|
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 57 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
constexpr int INF = (int)1e9 + 1001010;
constexpr ll llINF = (ll)4e18 + 22000020;
const string endn = "\n";
template <class T> inline vector<vector<T>> vector2(size_t i, size_t j, const T &init = T()) {return vector<vector<T>>(i, vector<T>(j, init));}
const string ELEM_SEPARATION = " ", VEC_SEPARATION = endn;
template<class T> istream& operator >>(istream &i, vector<T> &A) {for(auto &I : A) {i >> I;} return i;}
template<class T> ostream& operator <<(ostream &o, const vector<vector<T>> &A) {int i=A.size(); for(auto &I : A){o << I << (--i ? VEC_SEPARATION : "");} return o;}
template<class T> ostream& operator <<(ostream &o, const vector<T> &A) {int i=A.size(); for(auto &I : A){o << I << (--i ? ELEM_SEPARATION : "");} return o;}
template<class T> vector<T>& operator ++(vector<T> &A, int n) {for(auto &I : A) {I++;} return A;}
template<class T> vector<T>& operator --(vector<T> &A, int n) {for(auto &I : A) {I--;} return A;}
template<class T, class U> bool chmax(T &a, const U &b) {return ((a < b) ? (a = b, true) : false);}
template<class T, class U> bool chmin(T &a, const U &b) {return ((a > b) ? (a = b, true) : false);}
ll floor(ll a, ll b) {assert(b != 0); return((a%b != 0 && ((a>0) != (b>0))) ? a/b-1 : a/b);}
ll ceil (ll a, ll b) {assert(b != 0); return((a%b != 0 && ((a>0) == (b>0))) ? a/b+1 : a/b);}
// ================================== ここまでテンプレ ==================================
template<class T> using priority_queue_greater = priority_queue<T, vector<T>, greater<T>>;
int main(){
ios::sync_with_stdio(false);
cin.tie(nullptr);
int t; cin >> t;
int n, m; cin >> n >> m;
auto edges = vector2<pair<int, ll>>(n, 0);
for(int i = 0; i < m; i++){
int u, v, w; cin >> u >> v >> w;
u--; v--;
edges[u].emplace_back(v, w);
if(t == 0) edges[v].emplace_back(u, w);
}
auto solve = [&](int root) -> ll {
// rootを根とする最短路木を作る
vector<ll> distance(n, llINF);
vector<int> label(n);
{
priority_queue_greater<tuple<ll, int, int>> pq; // {dist, vIndex}
pq.emplace(0, root, root);
while(!pq.empty()){
auto [d, now, pre] = pq.top(); pq.pop();
if(distance[now] < d) continue;
distance[now] = d;
if(pre == root) label[now] = now;
else label[now] = label[pre];
for(auto [nxt, cost] : edges[now]){
pq.emplace(d+cost, nxt, now);
}
}
}
// 最短閉路を見つける
ll ret = llINF;
for(int from = 0; from < n; from++){
if(from == root) continue;
for(auto [to, cost] : edges[from]){
if(t == 0){
if(label[from] == label[to]) continue;
if(to == root && label[from] == from) continue;
else chmin(ret, distance[from] + distance[to] + cost);
}
if(t == 1){
if(to != root) continue;
else chmin(ret, distance[from] + cost);
}
}
}
return ret;
};
ll ans = llINF;
for(int i = 0; i < n; i++){
auto s = solve(i);
chmin(ans, s);
}
if(ans == llINF) cout << -1 << endl;
else cout << ans << endl;
return 0;
}