結果

問題 No.2375 watasou and hibit's baseball
ユーザー EWire
提出日時 2023-07-07 23:30:21
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 109 ms / 2,000 ms
コード長 3,991 bytes
コンパイル時間 3,691 ms
コンパイル使用メモリ 254,868 KB
最終ジャッジ日時 2025-02-15 08:38:46
ジャッジサーバーID
（参考情報） 		judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 36
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
// input
template<class T>
istream &operator>>(istream &is, vector<T> &v){
    for(T &in : v) is >> in;
    return is;
}
template<class T, class S>
istream &operator>>(istream &is, pair<T, S> &p){
    is >> p.first >> p.second;
    return is;
}
template<class... T> void input(T&... a) {(cin >> ... >> a);}
//output
template<class T>
ostream & operator<<(ostream &os, const vector<T> &v){
    for(int i = 0; i < (int)v.size(); i++) os << (i == 0 ? "" : " ") << v[i];
    return os;
}
template<class T, class S>
ostream &operator<<(ostream &os, const pair<T, S> &p){
    os << p.first << " " << p.second;
    return os;
}
template<class T, class S>
ostream &operator<<(ostream &os, const map<T, S> &mp){
    for(auto &[key, val] : mp) os << key << ":" << val << " ";
    return os;
}
template<class T>
ostream &operator<<(ostream &os, const set<T> &st){
    for(auto itr = st.begin(); itr != st.end(); itr++) os << (itr == st.begin() ? "" : " ") << *itr;
    return os;
}
template<class T>
ostream &operator<<(ostream &os, const multiset<T> &st){
    for(auto itr = st.begin(); itr != st.end(); itr++) os << (itr == st.begin() ? "" : " ") << *itr;
    return os;
}
template<class T>
ostream &operator<<(ostream &os, queue<T> que){
    while(!que.empty()) {
        os << que.front(); que.pop();
        if(!que.empty()) os << " ";
    }
    return os;
}
template<class T>
ostream &operator<<(ostream &os, stack<T> st){
    while(!st.empty()) {
        os << st.top(); st.pop();
        if(!st.empty()) os << " ";
    }
    return os;
}
template <class T, class Container, class Compare>
ostream &operator<<(ostream &os, priority_queue<T, Container, Compare> pq)
{
    while (!pq.empty()){
        os << pq.top(); pq.pop();
        if(!pq.empty()) os << " ";
    }
    return os;
}
void print() {cout << "\n";}
template<class T> void print(const T& a) {cout << a << '\n';}
template<class T, class... Ts> void print(const T& a, const Ts&... b) {cout << a; (..., (cout  << ' ' << b)); cout << '\n';}
#define debug(var) cout << #var << " = ";print(var);
typedef long long lint;
#define _overload3(_1,_2,_3,name,...) name
#define _rep(i,n) repi(i,0,n)
#define repi(i,a,b) for(int i=int(a);i<int(b);++i)
#define rep(...) _overload3(__VA_ARGS__,repi,_rep,)(__VA_ARGS__)
#define _overload3(_1,_2,_3,name,...) name
#define _rrep(i,n) rrepi(i,n,0)
#define rrepi(i,a,b) for(int i=int(a-1);i>=int(b);--i)
#define rrep(...) _overload3(__VA_ARGS__,rrepi,_rrep)(__VA_ARGS__)
#define all(x) (x).begin(),(x).end()
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
int dist(int x, int y, int u, int v){
    return abs(x - u) + abs(y - v);
}
int main() {
    int N, A, B; input(N, A, B);
    vector<int> X(N), Y(N), K(N);
    rep(i, N) input(X[i], Y[i], K[i]);
    vector<vector<vector<int>>> dp(1<<N, vector<vector<int>>(N+1, vector<int>(N+1, -1)));
    dp[(1<<N)-1][N][N] = 1;
    rrep(S, (1<<N)){
        rep(i, N+1){
            rep(j, N+1){
                if(dp[S][i][j] == -1) continue;
                rep(k, N){
                    if(((S >> k) & 1) == 0) continue;
                    int pcnt = __builtin_popcount(S);
                    if(S == (1<<N)-1) dp[S & ~(1<<k)][k][i] = 1;
                    else if(pcnt == N-1 && A <= dist(X[k], Y[k], X[i], Y[i])) dp[S & ~(1<<k)][k][i] = 1;
                    else if(pcnt <= N-1 && B <= abs(K[k] - K[i])) dp[S & ~(1<<k)][k][i] = 1;
                    else if(pcnt <= N-2 && A <= dist(X[k], Y[k], X[i], Y[i]) + dist(X[k], Y[k], X[j], Y[j])) dp[S & ~(1<<k)][k][i] = 1;
                }
            }
        }
    }
    int ans = 1;
    rep(i, 1<<N) {
        rep(j, N+1){
            rep(k, N+1){
                if(dp[i][j][k] == 1) chmax(ans, N - __builtin_popcount(i));
            }
        }
    }
    print(ans);
}
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