結果

問題 No.2327 Inversion Sum
ユーザー rlangevin
提出日時 2023-07-09 16:07:11
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 120 ms / 2,000 ms
コード長 1,938 bytes
コンパイル時間 520 ms
コンパイル使用メモリ 82,140 KB
実行使用メモリ 83,992 KB
最終ジャッジ日時 2024-07-23 13:16:31
合計ジャッジ時間 4,258 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
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ファイルパターン 結果
sample AC * 3
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
input = sys.stdin.readline
class Fenwick_Tree:
def __init__(self, n):
self._n = n
self.data = [0] * n
def add(self, p, x):
assert 0 <= p < self._n
p += 1
while p <= self._n:
self.data[p - 1] += x
p += p & -p
def sum(self, l, r):
assert 0 <= l <= r <= self._n
return self._sum(r) - self._sum(l)
def _sum(self, r):
s = 0
while r > 0:
s += self.data[r - 1]
r -= r & -r
return s
def get_size(self, x):
x = self.find(x)
while r > 0:
s += self.data[r - 1]
r -= r & -r
return s
def get(self, k):
k += 1
x, r = 0, 1
while r < self._n:
r <<= 1
len = r
while len:
if x + len - 1 < self._n:
if self.data[x + len - 1] < k:
k -= self.data[x + len - 1]
x += len
len >>= 1
return x
N, M = map(int, input().split())
mod = 998244353
D = [-1] * N
space = [0] * (N + 1)
num = [1] * N
for i in range(M):
p, k = map(int, input().split())
p, k = p - 1, k - 1
D[k] = p
num[p] = 0
Ac = [0] * (N + 1)
for i in range(N):
space[i + 1] = space[i] + (D[i] == -1)
Ac[i + 1] = Ac[i] + num[i]
nokori = N - M
fact = [1] * (N + 1)
for i in range(N):
fact[i + 1] = fact[i] * (i + 1)
fact[i + 1] %= mod
fact.append(0)
ans = 0
if nokori >= 2:
ans += (nokori * (nokori - 1)//2)**2 * fact[nokori - 2]
ans %= mod
T = Fenwick_Tree(N)
for i in range(N):
if D[i] != -1:
ans += T.sum(D[i], N) * fact[nokori]
left = space[i]
right = nokori - left
ans += right * Ac[D[i] + 1] * fact[nokori - 1]
ans += left * (Ac[-1] - Ac[D[i] + 1]) * fact[nokori - 1]
ans %= mod
T.add(D[i], 1)
print(ans)
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