結果
| 問題 |
No.2403 "Eight" Bridges of Königsberg
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-07-13 21:51:32 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 530 ms / 2,000 ms |
| コード長 | 2,219 bytes |
| コンパイル時間 | 186 ms |
| コンパイル使用メモリ | 82,588 KB |
| 実行使用メモリ | 172,984 KB |
| 最終ジャッジ日時 | 2024-11-26 17:45:56 |
| 合計ジャッジ時間 | 7,706 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 31 |
ソースコード
# https://github.com/shakayami/ACL-for-python/blob/master/dsu.py
class dsu():
n=1
parent_or_size=[-1 for i in range(n)]
def __init__(self,N):
self.n=N
self.parent_or_size=[-1 for i in range(N)]
def merge(self,a,b):
assert 0<=a<self.n, "0<=a<n,a={0},n={1}".format(a,self.n)
assert 0<=b<self.n, "0<=b<n,b={0},n={1}".format(b,self.n)
x=self.leader(a)
y=self.leader(b)
if x==y:
return x
if (-self.parent_or_size[x]<-self.parent_or_size[y]):
x,y=y,x
self.parent_or_size[x]+=self.parent_or_size[y]
self.parent_or_size[y]=x
return x
def same(self,a,b):
assert 0<=a<self.n, "0<=a<n,a={0},n={1}".format(a,self.n)
assert 0<=b<self.n, "0<=b<n,b={0},n={1}".format(b,self.n)
return self.leader(a)==self.leader(b)
def leader(self,a):
assert 0<=a<self.n, "0<=a<n,a={0},n={1}".format(a,self.n)
if (self.parent_or_size[a]<0):
return a
self.parent_or_size[a]=self.leader(self.parent_or_size[a])
return self.parent_or_size[a]
def size(self,a):
assert 0<=a<self.n, "0<=a<n,a={0},n={1}".format(a,self.n)
return -self.parent_or_size[self.leader(a)]
def groups(self):
leader_buf=[0 for i in range(self.n)]
group_size=[0 for i in range(self.n)]
for i in range(self.n):
leader_buf[i]=self.leader(i)
group_size[leader_buf[i]]+=1
result=[[] for i in range(self.n)]
for i in range(self.n):
result[leader_buf[i]].append(i)
result2=[]
for i in range(self.n):
if len(result[i])>0:
result2.append(result[i])
return result2
n,m=map(int,input().split())
u,v=[list(e) for e in zip(*[map(lambda s: int(s)-1, input().split()) for i in range(m)])]
g=dsu(n)
outdeg=[0 for i in range(n)]
indeg=[0 for i in range(n)]
for i in range(m):
g.merge(u[i],v[i])
outdeg[u[i]]+=1
indeg[v[i]]+=1
ccs=g.groups()
ans=-1
for cc in ccs:
tmp=0
ok=False
for p in cc:
if indeg[p]>0:
ok=True
tmp+=abs(outdeg[p]-indeg[p])
tmp//=2
ans+=max(tmp-1,0)+ok
print(ans)