結果

問題 No.2360 Path to Integer
ユーザー milanis48663220
提出日時 2023-07-14 01:42:05
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 133 ms / 2,500 ms
コード長 3,501 bytes
コンパイル時間 1,517 ms
コンパイル使用メモリ 129,364 KB
最終ジャッジ日時 2025-02-15 10:18:01
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 15
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <algorithm>
#include <iomanip>
#include <vector>
#include <queue>
#include <deque>
#include <set>
#include <map>
#include <tuple>
#include <cmath>
#include <numeric>
#include <functional>
#include <cassert>
#include <atcoder/modint>
#define debug_value(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << #x << "=" << x << endl;
#define debug(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << x << endl;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
using namespace std;
typedef long long ll;
template<typename T>
vector<vector<T>> vec2d(int n, int m, T v){
return vector<vector<T>>(n, vector<T>(m, v));
}
template<typename T>
vector<vector<vector<T>>> vec3d(int n, int m, int k, T v){
return vector<vector<vector<T>>>(n, vector<vector<T>>(m, vector<T>(k, v)));
}
template<typename T>
void print_vector(vector<T> v, char delimiter=' '){
if(v.empty()) {
cout << endl;
return;
}
for(int i = 0; i+1 < v.size(); i++) cout << v[i] << delimiter;
cout << v.back() << endl;
}
using mint = atcoder::modint998244353;
ostream& operator<<(ostream& os, const mint& m){
os << m.val();
return os;
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0);
cout << setprecision(10) << fixed;
int n; cin >> n;
vector<string> a(n);
for(int i = 0; i < n; i++) cin >> a[i];
vector<vector<int>> g(n);
for(int i = 0; i < n-1; i++){
int u, v; cin >> u >> v; u--; v--;
g[u].push_back(v);
g[v].push_back(u);
}
vector<vector<mint>> dp(n);
vector<int> subtree_size(n);
for(int i = 0; i < n; i++) dp[i].resize(g[i].size());
function<mint(int, int)> dfs1 = [&](int v, int p){
subtree_size[v] = 1;
mint pw = mint(10).pow(a[v].size());
mint ans = pw;
for(int i = 0; i < g[v].size(); i++){
int u = g[v][i];
if(u == p) continue;
dp[v][i] = dfs1(u, v);
ans += dp[v][i]*pw;
subtree_size[v] += subtree_size[u];
}
return ans;
};
dfs1(0, -1);
function<void(int, int, mint)> dfs2 = [&](int v, int p, mint from_par){
int deg = g[v].size();
for(int i = 0; i < deg; i++){
if(g[v][i] == p){
dp[v][i] = from_par;
break;
}
}
mint pw = mint(10).pow(a[v].size());
vector<mint> from_right(deg+1, 0);
for(int i = deg-1; i >= 0; i--){
from_right[i] = from_right[i+1] + dp[v][i];
}
mint from_left = 0;
for(int i = 0; i < deg; i++){
int u = g[v][i];
if(u != p){
mint x = (from_left+from_right[i+1]+1)*pw;
dfs2(u, v, x);
}
from_left = from_left + dp[v][i];
}
};
dfs2(0, -1, mint(0));
mint ans = 0;
for(int v = 0; v < n; v++){
mint x = stoll(a[v]);
mint sum = 0;
for(int i = 0; i < g[v].size(); i++){
int to = g[v][i];
if(subtree_size[to] > subtree_size[v]){
sum += dp[v][i]*x*subtree_size[v];
}else{
sum += dp[v][i]*x*(n-subtree_size[to]);
}
}
sum += x*n;
ans += sum;
// cout << v << ':' << sum << endl;
}
cout << ans << endl;
}
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