結果
問題 | No.2360 Path to Integer |
ユーザー |
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提出日時 | 2023-07-14 01:42:05 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 133 ms / 2,500 ms |
コード長 | 3,501 bytes |
コンパイル時間 | 1,517 ms |
コンパイル使用メモリ | 129,364 KB |
最終ジャッジ日時 | 2025-02-15 10:18:01 |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 15 |
ソースコード
#include <iostream>#include <algorithm>#include <iomanip>#include <vector>#include <queue>#include <deque>#include <set>#include <map>#include <tuple>#include <cmath>#include <numeric>#include <functional>#include <cassert>#include <atcoder/modint>#define debug_value(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << #x << "=" << x << endl;#define debug(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << x << endl;template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }using namespace std;typedef long long ll;template<typename T>vector<vector<T>> vec2d(int n, int m, T v){return vector<vector<T>>(n, vector<T>(m, v));}template<typename T>vector<vector<vector<T>>> vec3d(int n, int m, int k, T v){return vector<vector<vector<T>>>(n, vector<vector<T>>(m, vector<T>(k, v)));}template<typename T>void print_vector(vector<T> v, char delimiter=' '){if(v.empty()) {cout << endl;return;}for(int i = 0; i+1 < v.size(); i++) cout << v[i] << delimiter;cout << v.back() << endl;}using mint = atcoder::modint998244353;ostream& operator<<(ostream& os, const mint& m){os << m.val();return os;}int main(){ios::sync_with_stdio(false);cin.tie(0);cout << setprecision(10) << fixed;int n; cin >> n;vector<string> a(n);for(int i = 0; i < n; i++) cin >> a[i];vector<vector<int>> g(n);for(int i = 0; i < n-1; i++){int u, v; cin >> u >> v; u--; v--;g[u].push_back(v);g[v].push_back(u);}vector<vector<mint>> dp(n);vector<int> subtree_size(n);for(int i = 0; i < n; i++) dp[i].resize(g[i].size());function<mint(int, int)> dfs1 = [&](int v, int p){subtree_size[v] = 1;mint pw = mint(10).pow(a[v].size());mint ans = pw;for(int i = 0; i < g[v].size(); i++){int u = g[v][i];if(u == p) continue;dp[v][i] = dfs1(u, v);ans += dp[v][i]*pw;subtree_size[v] += subtree_size[u];}return ans;};dfs1(0, -1);function<void(int, int, mint)> dfs2 = [&](int v, int p, mint from_par){int deg = g[v].size();for(int i = 0; i < deg; i++){if(g[v][i] == p){dp[v][i] = from_par;break;}}mint pw = mint(10).pow(a[v].size());vector<mint> from_right(deg+1, 0);for(int i = deg-1; i >= 0; i--){from_right[i] = from_right[i+1] + dp[v][i];}mint from_left = 0;for(int i = 0; i < deg; i++){int u = g[v][i];if(u != p){mint x = (from_left+from_right[i+1]+1)*pw;dfs2(u, v, x);}from_left = from_left + dp[v][i];}};dfs2(0, -1, mint(0));mint ans = 0;for(int v = 0; v < n; v++){mint x = stoll(a[v]);mint sum = 0;for(int i = 0; i < g[v].size(); i++){int to = g[v][i];if(subtree_size[to] > subtree_size[v]){sum += dp[v][i]*x*subtree_size[v];}else{sum += dp[v][i]*x*(n-subtree_size[to]);}}sum += x*n;ans += sum;// cout << v << ':' << sum << endl;}cout << ans << endl;}