結果

問題 No.2379 Burnside's Theorem
ユーザー shirokami
提出日時 2023-07-14 21:34:22
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 4,246 bytes
コンパイル時間 4,939 ms
コンパイル使用メモリ 331,856 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-09-16 06:25:21
合計ジャッジ時間 6,016 ms
ジャッジサーバーID
(参考情報)
judge6 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 20
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/extc++.h>
using namespace std;
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")
// using namespace __gnu_pbds;
// #include <boost/multiprecision/cpp_int.hpp>
// using Bint = boost::multiprecision::cpp_int;
// #include <atcoder/all>
// using namespace atcoder;
// https://atcoder.github.io/ac-library/production/document_ja/
typedef long long int ll;
typedef long double ld;
constexpr ll mod = 998244353;
constexpr ll INF = 9'223'372'036'854'775'807/10;
#define rep(i,n) for (ll i = 0; i < ll(n); ++i)
#define All(a) (a).begin(),(a).end()
#define Pi acos(-1)
using V = vector<ll>;
using P = pair<ll,ll>;
vector<ll> dx = {1, 0, -1, 0, 1, 1, -1, -1};
vector<ll> dy = {0, 1, 0, -1, 1, -1, 1, -1};
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
struct Edge{ll to, cost;};
using Graph = vector<vector<Edge>>;
struct IoSetup {
IoSetup() {
cin.tie(nullptr);
ios_base::sync_with_stdio(false);
cout << setprecision(15) << fixed;
}
} iosetup;
void print(vector<string> &v) {
for (string s : v) {
cout << s << '\n';
}
}
template<typename T>
void print(vector<pair<T, T>> &v, int w = 0) {
for (int i = 0; i < (int)v.size(); i++) {
cout << right << setw(w) << v[i].first << ' ' << v[i].second << '\n';
}
}
template<typename T>
void print(vector<T> &v, int w = 0) {
for (int i = 0; i < (int)v.size(); i++) {
cout << right << setw(w) << v[i] << " \n"[i == (int)v.size() - 1];
}
}
template<typename T>
void print(vector<vector<T>> &v, int w = 0) {
for (int i = 0; i < (int)v.size(); i++) {
print(v[i], w);
}
}
template<typename T>
void print(const T& arg) {
cout << arg << '\n';
}
template<typename T, typename... Args>
void print(const T& arg, const Args&... args) {
cout << arg << ' ';
print(args...);
}
__int128_t pow_mod_128(__int128_t A, __int128_t N, __int128_t M) {
__int128_t res = 1 % M;
A %= M;
while (N) {
if (N & 1) res = (res * A) % M;
A = (A * A) % M;
N >>= 1;
}
return res;
}
bool is_prime(long long N) {
if (N <= 1) return false;
if (N == 2) return true;
if (N % 2 == 0) return false;
vector<long long> A = {2, 325, 9375, 28178, 450775, 9780504, 1795265022};
long long s = 0, d = N - 1;
while (d % 2 == 0) {
++s;
d >>= 1;
}
for (auto a : A) {
if (a % N == 0) return true;
long long t, x = pow_mod_128(a, d, N);
if (x != 1) {
for (t = 0; t < s; ++t) {
if (x == N - 1) break;
x = __int128_t(x) * x % N;
}
if (t == s) return false;
}
}
return true;
}
long long pollard(long long N) {
if (N % 2 == 0) return 2;
if (is_prime(N)) return N;
auto f = [&](long long x) -> long long {
return (__int128_t(x) * x + 1) % N;
};
long long step = 0;
while (true) {
++step;
long long x = step, y = f(x);
while (true) {
long long p = gcd(y - x + N, N);
if (p == 0 || p == N) break;
if (p != 1) return p;
x = f(x);
y = f(f(y));
}
}
}
vector<long long> prime_factorize(long long N) {
if (N == 1) return {};
long long p = pollard(N);
if (p == N) return {p};
vector<long long> left = prime_factorize(p);
vector<long long> right = prime_factorize(N / p);
left.insert(left.end(), right.begin(), right.end());
sort(left.begin(), left.end());
return left;
}
vector<pair<long long, long long>> prime_factorize_pair(long long N) {
vector<long long> left = prime_factorize(N);
left.push_back(-1);
vector<pair<long long, long long>> g;
long long cnt = 1;
for (long long i = 1; i < left.size(); i++) {
if (left[i] == left[i-1]) {
cnt++;
}
else {
g.push_back({left[i-1], cnt});
cnt = 1;
}
}
return g;
}
/*
prime_factorize:
prime_factorize_pair: {, }
prime_factorize
12 -> {2, 2, 3}
2 -> {2}
1 -> {}
prime_factorize_pair
12 -> {{2, 2}, {3, 1}}
2 -> {{2, 1}}
1 -> {}
*/
int main() {
ll n;
cin >> n;
auto v = prime_factorize_pair(n);
if (v.size() <= 2) {
print("Yes");
} else {
print("No");
}
}
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