結果
問題 |
No.2423 Merge Stones
|
ユーザー |
|
提出日時 | 2023-07-15 13:32:20 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 636 ms / 4,000 ms |
コード長 | 1,745 bytes |
コンパイル時間 | 991 ms |
コンパイル使用メモリ | 103,572 KB |
最終ジャッジ日時 | 2025-02-15 14:59:18 |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 72 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:25:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 25 | scanf("%d", &A[i]); | ~~~~~^~~~~~~~~~~~~ main.cpp:33:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 33 | scanf("%d", &C[i]); | ~~~~~^~~~~~~~~~~~~
ソースコード
#include <iostream> #include <algorithm> #include <map> #include <set> #include <queue> #include <stack> #include <numeric> #include <bitset> #include <cmath> static const int MOD = 1000000007; using ll = long long; using uint = unsigned; using ull = unsigned long long; using namespace std; template<class T> constexpr T INF = ::numeric_limits<T>::max() / 32 * 15 + 208; ll dp[600][601]; int main() { int n, k; cin >> n >> k; vector<int> A(2*n), C(2*n); for (int i = 0; i < n; ++i) { scanf("%d", &A[i]); A[i+n] = A[i]; } vector<ll> S(2*n+1); for (int i = 0; i < 2*n; ++i) { S[i+1] = S[i] + A[i]; } for (int i = 0; i < n; ++i) { scanf("%d", &C[i]); C[i+n] = C[i]; } n *= 2; for (int i = 0; i < n; ++i) { for (int j = i+1; j <= n; ++j) { dp[i][j] = 0; } dp[i][i+1] = (1LL << C[i]); } for (int len = 2; len <= n; ++len) { for (int l = 0; l+len <= n; ++l) { int r = l+len; for (int mid = l+1; mid < r; ++mid) { ll lval = dp[l][mid], rval = dp[mid][r]; if(lval == 0 || rval == 0) continue; dp[l][r] |= lval & rval; for (int i = 1; i <= k; ++i) { dp[l][r] |= lval & (rval << i); dp[l][r] |= lval & (rval >> i); dp[l][r] |= lval << i & rval; dp[l][r] |= lval >> i & rval; } } } } ll ans = 0; for (int i = 0; i < n; ++i) { for (int j = i+1; j <= n && j-i <= n/2; ++j) { if(dp[i][j] > 0) ans = max(ans, S[j]-S[i]); } } cout << ans << "\n"; return 0; }