結果
問題 | No.184 たのしい排他的論理和(HARD) |
ユーザー | hiro71687k |
提出日時 | 2023-07-18 18:17:47 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 3,094 bytes |
コンパイル時間 | 4,640 ms |
コンパイル使用メモリ | 263,500 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-09-18 17:40:49 |
合計ジャッジ時間 | 9,579 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 3 ms
5,248 KB |
testcase_01 | AC | 3 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 3 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 3 ms
5,376 KB |
testcase_06 | AC | 3 ms
5,376 KB |
testcase_07 | AC | 3 ms
5,376 KB |
testcase_08 | AC | 82 ms
5,376 KB |
testcase_09 | AC | 19 ms
5,376 KB |
testcase_10 | AC | 63 ms
5,376 KB |
testcase_11 | AC | 46 ms
5,376 KB |
testcase_12 | AC | 96 ms
5,376 KB |
testcase_13 | AC | 103 ms
5,376 KB |
testcase_14 | AC | 60 ms
5,376 KB |
testcase_15 | AC | 111 ms
5,376 KB |
testcase_16 | AC | 93 ms
5,376 KB |
testcase_17 | AC | 100 ms
5,376 KB |
testcase_18 | WA | - |
testcase_19 | AC | 3 ms
5,376 KB |
testcase_20 | AC | 30 ms
5,376 KB |
testcase_21 | AC | 114 ms
5,376 KB |
testcase_22 | AC | 115 ms
5,376 KB |
testcase_23 | AC | 2 ms
5,376 KB |
testcase_24 | AC | 3 ms
5,376 KB |
testcase_25 | AC | 2 ms
5,376 KB |
testcase_26 | AC | 3 ms
5,376 KB |
testcase_27 | AC | 3 ms
5,376 KB |
testcase_28 | AC | 71 ms
5,376 KB |
testcase_29 | AC | 98 ms
5,376 KB |
testcase_30 | AC | 87 ms
5,376 KB |
testcase_31 | AC | 75 ms
5,376 KB |
testcase_32 | AC | 92 ms
5,376 KB |
testcase_33 | AC | 112 ms
5,376 KB |
testcase_34 | AC | 112 ms
5,376 KB |
testcase_35 | AC | 115 ms
5,376 KB |
testcase_36 | AC | 114 ms
5,376 KB |
ソースコード
#include <bits/stdc++.h> #include <atcoder/all> using namespace atcoder; using namespace std; using ll=long long; using ld=long double; ld pie=3.141592653589793; ll mod=1000000007; ld inf=10000999999999900; const int MAX_ROW = 100002; // to be set appropriately const int MAX_COL = 62; // to be set appropriately struct BitMatrix { int H, W; bitset<MAX_COL> val[MAX_ROW]; BitMatrix(int m = 1, int n = 1) : H(m), W(n) {} inline bitset<MAX_COL>& operator [] (int i) {return val[i];} }; ostream& operator << (ostream& s, BitMatrix A) { s << endl; for (int i = 0; i < A.H; ++i) { for (int j = 0; j < A.W; ++j) { s << A[i][j] << ", "; } s << endl; } return s; } inline BitMatrix operator * (BitMatrix A, BitMatrix B) { BitMatrix R(A.H, B.W); BitMatrix tB(B.W, B.H); for (int i = 0; i < tB.H; ++i) for (int j = 0; j < tB.W; ++j) tB[i][j] = B[j][i]; for (int i = 0; i < R.H; ++i) for (int j = 0; j < R.W; ++j) R[i][j] = ((A[i] & tB[j]).count() & 1); return R; } inline BitMatrix pow(BitMatrix A, long long n) { BitMatrix R(A.H, A.H); for (int i = 0; i < A.H; ++i) R[i][i] = 1; while (n > 0) { if (n & 1) R = R * A; A = A * A; n >>= 1; } return R; } int GaussJordan(BitMatrix &A, bool is_extended = false) { int rank = 0; for (int col = 0; col < A.W; ++col) { if (is_extended && col == A.W - 1) break; int pivot = -1; for (int row = rank; row < A.H; ++row) { if (A[row][col]) { pivot = row; break; } } if (pivot == -1) continue; swap(A[pivot], A[rank]); for (int row = 0; row < A.H; ++row) { if (row != rank && A[row][col]) A[row] ^= A[rank]; } ++rank; } return rank; } int linear_equation(BitMatrix A, vector<int> b, vector<int> &res) { int m = A.H, n = A.W; BitMatrix M(m, n + 1); for (int i = 0; i < m; ++i) { for (int j = 0; j < n; ++j) M[i][j] = A[i][j]; M[i][n] = b[i]; } int rank = GaussJordan(M, true); // check if it has no solution for (int row = rank; row < m; ++row) if (M[row][n]) return -1; // answer res.assign(n, 0); for (int i = 0; i < rank; ++i) res[i] = M[i][n]; return rank; } const int MOD = 998244353; long long modpow(long long a, long long n, long long mod) { long long res = 1; while (n > 0) { if (n & 1) res = res * a % mod; a = a * a % mod; n >>= 1; } return res; } int main() { int N, M; cin >> N; M=61; BitMatrix A(N, M); vector<ll>two(61,1); for (ll i = 1; i < two.size(); i++) { two[i]=two[i-1]*2; } for (int i = 0; i < N; ++i) { ll x; cin >> x; for (ll j = 0; j <=60; j++) { if (two[j]&x) { A[i][j]=1; }else{ A[i][j]=0; } } } vector<int> res; int r = GaussJordan(A); cout << two[r] << endl; }