結果

問題 No.2395 区間二次変換一点取得
ユーザー risujirohrisujiroh
提出日時 2023-07-28 21:53:20
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 88 ms / 2,000 ms
コード長 4,113 bytes
コンパイル時間 3,166 ms
コンパイル使用メモリ 268,108 KB
実行使用メモリ 31,336 KB
最終ジャッジ日時 2024-10-06 18:31:36
合計ジャッジ時間 5,281 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 20
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#if __INCLUDE_LEVEL__ == 0
#include <bits/stdc++.h>
using namespace std;
#include __BASE_FILE__
namespace {
using Mint = atcoder::modint;
using S = array<Mint, 5>;
S op(S x, S y) {
S z;
for (int i : rep(5)) {
z[i] = x[i] + y[i];
}
return z;
}
S e() { return {}; }
using F = array<array<Mint, 5>, 5>;
S mapping(F f, S x) {
S y{};
for (int i : rep(5)) {
for (int j : rep(5)) {
y[i] += f[i][j] * x[j];
}
}
return y;
}
F composition(F g, F f) {
F ret{};
for (int i : rep(5)) {
for (int k : rep(5)) {
if (f[i][k].val() == 0) {
continue;
}
for (int j : rep(5)) {
ret[i][j] += f[i][k] * g[k][j];
}
}
}
return ret;
}
F id() {
F ret{};
for (int i : rep(5)) {
ret[i][i] = 1;
}
return ret;
}
using Seg = atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>;
void solve() {
int n, b, q;
cin >> tie(n, b, q);
Mint::set_mod(b);
Seg seg(vector<S>(n, {1, 1, 1, 1, 1}));
F f;
f[0] = {1, 0, 0, 0, 1};
f[1] = {0, 3, 2, 2, 0};
f[2] = {0, 0, 3, 0, 0};
f[3] = {0, 0, 3, 3, 0};
f[4] = {0, 0, 0, 0, 1};
vector<F> pw(q + 1);
pw[0] = id();
for (int i : rep(q)) {
pw[i + 1] = composition(f, pw[i]);
}
atcoder::fenwick_tree<int> ft(n + 1);
while (q--) {
int l, m, r;
cin >> tie(l, m, r);
--l, --m;
ft.add(l, 1);
ft.add(r, -1);
int p = ft.sum(0, m + 1);
auto e = mapping(pw[p], {1, 1, 1, 1, 1});
print(e[0], e[1], e[2]);
}
}
} // namespace
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
solve();
}
#else // __INCLUDE_LEVEL__
#undef assert
#define assert(expr) (expr) || (__builtin_unreachable(), 0)
#include <atcoder/fenwicktree>
#include <atcoder/lazysegtree>
#include <atcoder/modint>
template <class T, class U = T>
bool chmin(T& x, U&& y) {
return y < x && (x = forward<U>(y), true);
}
template <class T, class U = T>
bool chmax(T& x, U&& y) {
return x < y && (x = forward<U>(y), true);
}
namespace std {
template <class T1, class T2>
istream& operator>>(istream& is, pair<T1, T2>& p) {
return is >> p.first >> p.second;
}
template <class... Ts>
istream& operator>>(istream& is, tuple<Ts...>& t) {
return apply([&is](auto&... xs) -> istream& { return (is >> ... >> xs); }, t);
}
template <class... Ts>
istream& operator>>(istream& is, tuple<Ts&...>&& t) {
return is >> t;
}
template <class R, enable_if_t<!is_convertible_v<R, string>>* = nullptr>
auto operator>>(istream& is, R&& r) -> decltype(is >> *begin(r)) {
for (auto&& e : r) {
is >> e;
}
return is;
}
template <class T1, class T2>
ostream& operator<<(ostream& os, const pair<T1, T2>& p) {
return os << p.first << ' ' << p.second;
}
template <class... Ts>
ostream& operator<<(ostream& os, const tuple<Ts...>& t) {
auto f = [&os](const auto&... xs) -> ostream& {
[[maybe_unused]] auto sep = "";
((os << exchange(sep, " ") << xs), ...);
return os;
};
return apply(f, t);
}
template <class R, enable_if_t<!is_convertible_v<R, string_view>>* = nullptr>
auto operator<<(ostream& os, R&& r) -> decltype(os << *begin(r)) {
auto sep = "";
for (auto&& e : r) {
os << exchange(sep, " ") << e;
}
return os;
}
} // namespace std
namespace atcoder {
template <class T, internal::is_modint_t<T>* = nullptr>
istream& operator>>(istream& is, T& x) {
int v;
is >> v;
x = T::raw(v);
return is;
}
template <class T, internal::is_modint_t<T>* = nullptr>
ostream& operator<<(ostream& os, const T& x) {
return os << x.val();
}
} // namespace atcoder
template <class... Ts>
void print(Ts&&... xs) {
cout << tie(xs...) << '\n';
}
inline auto rep(int l, int r) { return views::iota(min(l, r), r); }
inline auto rep(int n) { return rep(0, n); }
inline auto rep1(int l, int r) { return rep(l, r + 1); }
inline auto rep1(int n) { return rep(1, n + 1); }
inline auto per(int l, int r) { return rep(l, r) | views::reverse; }
inline auto per(int n) { return per(0, n); }
inline auto per1(int l, int r) { return per(l, r + 1); }
inline auto per1(int n) { return per(1, n + 1); }
#endif // __INCLUDE_LEVEL__
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