結果
| 問題 |
No.8011 品物の並び替え (Extra)
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-08-03 17:52:39 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 9,379 bytes |
| コンパイル時間 | 4,262 ms |
| コンパイル使用メモリ | 272,776 KB |
| 最終ジャッジ日時 | 2025-02-15 21:50:09 |
|
ジャッジサーバーID (参考情報) |
judge2 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | WA * 9 |
ソースコード
#ifndef HIDDEN_IN_VS // 折りたたみ用
// 警告の抑制
#define _CRT_SECURE_NO_WARNINGS
// ライブラリの読み込み
#include <bits/stdc++.h>
using namespace std;
// 型名の短縮
using ll = long long; // -2^63 ~ 2^63 = 9 * 10^18(int は -2^31 ~ 2^31 = 2 * 10^9)
using pii = pair<int, int>; using pll = pair<ll, ll>; using pil = pair<int, ll>; using pli = pair<ll, int>;
using vi = vector<int>; using vvi = vector<vi>; using vvvi = vector<vvi>; using vvvvi = vector<vvvi>;
using vl = vector<ll>; using vvl = vector<vl>; using vvvl = vector<vvl>; using vvvvl = vector<vvvl>;
using vb = vector<bool>; using vvb = vector<vb>; using vvvb = vector<vvb>;
using vc = vector<char>; using vvc = vector<vc>; using vvvc = vector<vvc>;
using vd = vector<double>; using vvd = vector<vd>; using vvvd = vector<vvd>;
template <class T> using priority_queue_rev = priority_queue<T, vector<T>, greater<T>>;
using Graph = vvi;
// 定数の定義
const double PI = acos(-1);
const vi DX = { 1, 0, -1, 0 }; // 4 近傍(下,右,上,左)
const vi DY = { 0, 1, 0, -1 };
int INF = 1001001001; ll INFL = 4004004003104004004LL; // (int)INFL = 1010931620;
double EPS = 1e-15;
// 入出力高速化
struct fast_io { fast_io() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(18); } } fastIOtmp;
// 汎用マクロの定義
#define all(a) (a).begin(), (a).end()
#define sz(x) ((int)(x).size())
#define lbpos(a, x) (int)distance((a).begin(), std::lower_bound(all(a), x))
#define ubpos(a, x) (int)distance((a).begin(), std::upper_bound(all(a), x))
#define Yes(b) {cout << ((b) ? "Yes\n" : "No\n");}
#define rep(i, n) for(int i = 0, i##_len = int(n); i < i##_len; ++i) // 0 から n-1 まで昇順
#define repi(i, s, t) for(int i = int(s), i##_end = int(t); i <= i##_end; ++i) // s から t まで昇順
#define repir(i, s, t) for(int i = int(s), i##_end = int(t); i >= i##_end; --i) // s から t まで降順
#define repe(v, a) for(const auto& v : (a)) // a の全要素(変更不可能)
#define repea(v, a) for(auto& v : (a)) // a の全要素(変更可能)
#define repb(set, d) for(int set = 0; set < (1 << int(d)); ++set) // d ビット全探索(昇順)
#define repp(a) sort(all(a)); for(bool a##_perm = true; a##_perm; a##_perm = next_permutation(all(a))) // a の順列全て(昇順)
#define smod(n, m) ((((n) % (m)) + (m)) % (m)) // 非負mod
#define uniq(a) {sort(all(a)); (a).erase(unique(all(a)), (a).end());} // 重複除去
#define EXIT(a) {cout << (a) << endl; exit(0);} // 強制終了
#define inQ(x, y, u, l, d, r) ((u) <= (x) && (l) <= (y) && (x) < (d) && (y) < (r)) // 半開矩形内判定
// 汎用関数の定義
template <class T> inline ll pow(T n, int k) { ll v = 1; rep(i, k) v *= n; return v; }
template <class T> inline bool chmax(T& M, const T& x) { if (M < x) { M = x; return true; } return false; } // 最大値を更新(更新されたら true を返す)
template <class T> inline bool chmin(T& m, const T& x) { if (m > x) { m = x; return true; } return false; } // 最小値を更新(更新されたら true を返す)
template <class T> inline T get(T set, int i) { return (set >> i) & T(1); }
// 演算子オーバーロード
template <class T, class U> inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }
template <class T> inline istream& operator>>(istream& is, vector<T>& v) { repea(x, v) is >> x; return is; }
template <class T> inline vector<T>& operator--(vector<T>& v) { repea(x, v) --x; return v; }
template <class T> inline vector<T>& operator++(vector<T>& v) { repea(x, v) ++x; return v; }
#endif // 折りたたみ用
#if __has_include(<atcoder/all>)
#include <atcoder/all>
using namespace atcoder;
#ifdef _MSC_VER
#include "localACL.hpp"
#endif
//using mint = modint1000000007;
using mint = modint998244353;
//using mint = modint; // mint::set_mod(m);
namespace atcoder {
inline istream& operator>>(istream& is, mint& x) { ll x_; is >> x_; x = x_; return is; }
inline ostream& operator<<(ostream& os, const mint& x) { os << x.val(); return os; }
}
using vm = vector<mint>; using vvm = vector<vm>; using vvvm = vector<vvm>; using vvvvm = vector<vvvm>;
#endif
#ifdef _MSC_VER // 手元環境(Visual Studio)
#include "local.hpp"
#else // 提出用(gcc)
inline int popcount(int n) { return __builtin_popcount(n); }
inline int popcount(ll n) { return __builtin_popcountll(n); }
inline int lsb(int n) { return n != 0 ? __builtin_ctz(n) : -1; }
inline int lsb(ll n) { return n != 0 ? __builtin_ctzll(n) : -1; }
inline int msb(int n) { return n != 0 ? (31 - __builtin_clz(n)) : -1; }
inline int msb(ll n) { return n != 0 ? (63 - __builtin_clzll(n)) : -1; }
#define gcd __gcd
#define dump(...)
#define dumpel(v)
#define dump_list(v)
#define dump_mat(v)
#define input_from_file(f)
#define output_to_file(f)
#define Assert(b) { if (!(b)) while (1) cout << "OLE"; }
#endif
// https://judge.yosupo.jp/submission/72030 から窃盗
// DSU_rollback
struct Data {
int time, u, par; // before `time`, `par` = par[u]
};
struct DSU {
vector<int> par;
vector<Data> change;
DSU(int n) : par(n + 5, -1) {}
// find root of x.
// if par[x] < 0 then x is a root, and its tree has -par[x] nodes
int getRoot(int x) {
while (par[x] >= 0)
x = par[x];
return x;
}
// join components containing x and y.
// t should be current time. We use it to update `change`.
bool join(int x, int y, int t) {
x = getRoot(x);
y = getRoot(y);
if (x == y) return false;
//union by rank
if (par[x] < par[y]) swap(x, y);
//now x's tree has less nodes than y's tree
change.push_back({ t, y, par[y] });
par[y] += par[x];
change.push_back({ t, x, par[x] });
par[x] = y;
return true;
}
// rollback all changes at time > t.
void rollback(int t) {
while (!change.empty() && change.back().time > t) {
par[change.back().u] = change.back().par;
change.pop_back();
}
}
};
// Directed MST
// Copied from chemthan
// Index from 0
using ll = long long;
struct Edge {
int u, v; // directed, u -> v
ll cost;
};
struct HeapNode { // lazy skew heap node
Edge key;
HeapNode* l, * r;
ll delta;
void prop() {
key.cost += delta;
if (l) l->delta += delta;
if (r) r->delta += delta;
delta = 0;
}
Edge top() {
prop();
return key;
}
};
HeapNode* merge(HeapNode* a, HeapNode* b) {
if (!a) return b;
if (!b) return a;
a->prop(); b->prop();
if (a->key.cost > b->key.cost) swap(a, b);
swap(a->l, (a->r = merge(b, a->r)));
return a;
}
void pop(HeapNode*& a) {
a->prop();
a = merge(a->l, a->r);
}
// return {cost, parent[i]}
// Not found -> return {-1, {}}
pair<ll, vector<int>> directed_mst(int n, int root, vector<Edge>& edges) {
DSU dsu(n);
int dsu_time = 0;
vector<HeapNode*> heap(n);
for (const Edge& e : edges) {
heap[e.v] = merge(heap[e.v], new HeapNode{ e });
}
ll res = 0;
vector<int> seen(n, -1), path(n);
seen[root] = root;
vector<Edge> Q(n), in(n, { -1, -1 });
deque<tuple<int, int, vector<Edge>>> cycs;
for (int s = 0; s < n; ++s) {
int u = s, qi = 0, w;
while (seen[u] < 0) {
if (!heap[u]) return { -1, {} };
Edge e = heap[u]->top();
heap[u]->delta -= e.cost;
pop(heap[u]);
Q[qi] = e;
path[qi++] = u;
seen[u] = s;
res += e.cost;
u = dsu.getRoot(e.u);
if (seen[u] == s) {
HeapNode* cyc = 0;
int end = qi;
int time = dsu_time;
do {
cyc = merge(cyc, heap[w = path[--qi]]);
} while (dsu.join(u, w, ++dsu_time));
u = dsu.getRoot(u);
heap[u] = cyc;
seen[u] = -1;
cycs.push_front({ u, time, {&Q[qi], &Q[end]} });
}
}
for (int i = 0; i < qi; i++) in[dsu.getRoot(Q[i].v)] = Q[i];
}
for (auto& [u, t, comp] : cycs) {
dsu.rollback(t);
Edge inEdge = in[u];
for (auto& e : comp) in[dsu.getRoot(e.v)] = e;
in[dsu.getRoot(inEdge.v)] = inEdge;
}
vector<int> par(n);
for (int i = 0; i < n; i++) par[i] = in[i].u;
return { res, par };
}
int main() {
// input_from_file("input.txt");
// output_to_file("output.txt");
int n, m;
cin >> n >> m;
vvl cost(n, vl(n, INF));
rep(j, m) {
int u, v; ll sc;
cin >> u >> v >> sc;
cost[u][v] = INF - sc;
}
vector<Edge> edges;
rep(s, n) rep(t, n) if (s != t) edges.push_back({ s, t, cost[s][t] });
ll cost_min = INFL; vi par_min; int root_min = -1;
rep(root, n) {
auto [total, par] = directed_mst(n, root, edges);
if (chmin(cost_min, total)) {
par_min = par;
root_min = root;
}
}
Graph g(n);
rep(s, n) if (s != root_min) g[par_min[s]].push_back(s);
cout << (ll)INF * (n - 1) - cost_min << endl;
function<void(int)> dfs = [&](int s) {
cout << s << endl;
repe(t, g[s]) dfs(t);
};
dfs(root_min);
}