結果
問題 | No.2403 "Eight" Bridges of Königsberg |
ユーザー | tokusakurai |
提出日時 | 2023-08-04 21:37:32 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 36 ms / 2,000 ms |
コード長 | 5,186 bytes |
コンパイル時間 | 2,240 ms |
コンパイル使用メモリ | 204,668 KB |
実行使用メモリ | 6,528 KB |
最終ジャッジ日時 | 2024-05-05 01:22:09 |
合計ジャッジ時間 | 3,700 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 1 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 16 ms
5,376 KB |
testcase_05 | AC | 30 ms
5,376 KB |
testcase_06 | AC | 33 ms
5,376 KB |
testcase_07 | AC | 20 ms
5,376 KB |
testcase_08 | AC | 24 ms
5,376 KB |
testcase_09 | AC | 36 ms
5,376 KB |
testcase_10 | AC | 33 ms
5,376 KB |
testcase_11 | AC | 26 ms
5,376 KB |
testcase_12 | AC | 34 ms
5,376 KB |
testcase_13 | AC | 24 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | AC | 2 ms
5,376 KB |
testcase_16 | AC | 2 ms
5,376 KB |
testcase_17 | AC | 2 ms
5,376 KB |
testcase_18 | AC | 2 ms
5,376 KB |
testcase_19 | AC | 5 ms
6,528 KB |
testcase_20 | AC | 2 ms
5,376 KB |
testcase_21 | AC | 4 ms
5,376 KB |
testcase_22 | AC | 5 ms
6,272 KB |
testcase_23 | AC | 5 ms
6,144 KB |
testcase_24 | AC | 4 ms
5,376 KB |
testcase_25 | AC | 4 ms
5,376 KB |
testcase_26 | AC | 2 ms
5,376 KB |
testcase_27 | AC | 6 ms
6,272 KB |
testcase_28 | AC | 5 ms
5,632 KB |
testcase_29 | AC | 3 ms
5,376 KB |
testcase_30 | AC | 4 ms
5,376 KB |
testcase_31 | AC | 5 ms
6,528 KB |
testcase_32 | AC | 3 ms
5,376 KB |
testcase_33 | AC | 3 ms
5,376 KB |
testcase_34 | AC | 3 ms
5,376 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #define rep(i, n) for (int i = 0; i < (n); i++) #define per(i, n) for (int i = (n)-1; i >= 0; i--) #define rep2(i, l, r) for (int i = (l); i < (r); i++) #define per2(i, l, r) for (int i = (r)-1; i >= (l); i--) #define each(e, v) for (auto &e : v) #define MM << " " << #define pb push_back #define eb emplace_back #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define sz(x) (int)x.size() using ll = long long; using pii = pair<int, int>; using pil = pair<int, ll>; using pli = pair<ll, int>; using pll = pair<ll, ll>; template <typename T> using minheap = priority_queue<T, vector<T>, greater<T>>; template <typename T> using maxheap = priority_queue<T>; template <typename T> bool chmax(T &x, const T &y) { return (x < y) ? (x = y, true) : false; } template <typename T> bool chmin(T &x, const T &y) { return (x > y) ? (x = y, true) : false; } template <typename T> int flg(T x, int i) { return (x >> i) & 1; } int pct(int x) { return __builtin_popcount(x); } int pct(ll x) { return __builtin_popcountll(x); } int topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); } int topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); } int botbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); } int botbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); } template <typename T> void print(const vector<T> &v, T x = 0) { int n = v.size(); for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' '); if (v.empty()) cout << '\n'; } template <typename T> void printn(const vector<T> &v, T x = 0) { int n = v.size(); for (int i = 0; i < n; i++) cout << v[i] + x << '\n'; } template <typename T> int lb(const vector<T> &v, T x) { return lower_bound(begin(v), end(v), x) - begin(v); } template <typename T> int ub(const vector<T> &v, T x) { return upper_bound(begin(v), end(v), x) - begin(v); } template <typename T> void rearrange(vector<T> &v) { sort(begin(v), end(v)); v.erase(unique(begin(v), end(v)), end(v)); } template <typename T> vector<int> id_sort(const vector<T> &v, bool greater = false) { int n = v.size(); vector<int> ret(n); iota(begin(ret), end(ret), 0); sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; }); return ret; } template <typename T> void reorder(vector<T> &a, const vector<int> &ord) { int n = a.size(); vector<T> b(n); for (int i = 0; i < n; i++) b[i] = a[ord[i]]; swap(a, b); } template <typename T> T floor(T x, T y) { assert(y != 0); if (y < 0) x = -x, y = -y; return (x >= 0 ? x / y : (x - y + 1) / y); } template <typename T> T ceil(T x, T y) { assert(y != 0); if (y < 0) x = -x, y = -y; return (x >= 0 ? (x + y - 1) / y : x / y); } template <typename S, typename T> pair<S, T> operator+(const pair<S, T> &p, const pair<S, T> &q) { return make_pair(p.first + q.first, p.second + q.second); } template <typename S, typename T> pair<S, T> operator-(const pair<S, T> &p, const pair<S, T> &q) { return make_pair(p.first - q.first, p.second - q.second); } template <typename S, typename T> istream &operator>>(istream &is, pair<S, T> &p) { S a; T b; is >> a >> b; p = make_pair(a, b); return is; } template <typename S, typename T> ostream &operator<<(ostream &os, const pair<S, T> &p) { return os << p.first << ' ' << p.second; } struct io_setup { io_setup() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout << fixed << setprecision(15); } } io_setup; constexpr int inf = (1 << 30) - 1; constexpr ll INF = (1LL << 60) - 1; // constexpr int MOD = 1000000007; constexpr int MOD = 998244353; struct Union_Find_Tree { vector<int> data; const int n; int cnt; Union_Find_Tree(int n) : data(n, -1), n(n), cnt(n) {} int root(int x) { if (data[x] < 0) return x; return data[x] = root(data[x]); } int operator[](int i) { return root(i); } bool unite(int x, int y) { x = root(x), y = root(y); if (x == y) return false; if (data[x] > data[y]) swap(x, y); data[x] += data[y], data[y] = x; cnt--; return true; } int size(int x) { return -data[root(x)]; } int count() { return cnt; }; bool same(int x, int y) { return root(x) == root(y); } void clear() { cnt = n; fill(begin(data), end(data), -1); } }; void solve() { int N, M; cin >> N >> M; Union_Find_Tree uf(N); vector<int> deg(N, 0), deg2(N, 0); rep(i, M) { int u, v; cin >> u >> v; u--, v--; uf.unite(u, v); deg[u]++, deg[v]--; deg2[u]++, deg2[v]++; } vector<int> c1(N, 0), c2(N, 0); rep(i, N) { int u = uf[i]; if (deg[i] > 0) c1[u] += deg[i]; c2[u] += deg2[i]; } // print(c1), print(c2); int K = 0; int ans = 0; rep(i, N) { ans += max(c1[i] - 1, 0); if (c2[i] >= 1) K++; } cout << ans + K - 1 << '\n'; } int main() { int T = 1; // cin >> T; while (T--) solve(); }