結果
問題 | No.2405 Minimal Matrix Decomposition |
ユーザー |
|
提出日時 | 2023-08-07 11:47:53 |
言語 | Rust (1.83.0 + proconio) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,703 bytes |
コンパイル時間 | 13,819 ms |
コンパイル使用メモリ | 378,884 KB |
実行使用メモリ | 6,912 KB |
最終ジャッジ日時 | 2024-11-07 15:43:03 |
合計ジャッジ時間 | 18,430 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 WA * 1 |
other | AC * 3 WA * 43 |
コンパイルメッセージ
warning: call to `.clone()` on a reference in this situation does nothing --> src/main.rs:71:17 | 71 | let aold = a.clone(); | ^^^^^^^^ help: remove this redundant call | = note: the type `[Vec<i64>]` does not implement `Clone`, so calling `clone` on `&[Vec<i64>]` copies the reference, which does not do anything and can be removed = note: `#[warn(noop_method_call)]` on by default
ソースコード
#[allow(unused_imports)]use std::cmp::*;#[allow(unused_imports)]use std::collections::*;use std::io::{Write, BufWriter};// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8macro_rules! input {($($r:tt)*) => {let stdin = std::io::stdin();let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));let mut next = move || -> String{bytes.by_ref().map(|r|r.unwrap() as char).skip_while(|c|c.is_whitespace()).take_while(|c|!c.is_whitespace()).collect()};input_inner!{next, $($r)*}};}macro_rules! input_inner {($next:expr) => {};($next:expr,) => {};($next:expr, $var:ident : $t:tt $($r:tt)*) => {let $var = read_value!($next, $t);input_inner!{$next $($r)*}};}macro_rules! read_value {($next:expr, ( $($t:tt),* )) => { ($(read_value!($next, $t)),*) };($next:expr, [ $t:tt ; $len:expr ]) => {(0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()};($next:expr, chars) => {read_value!($next, String).chars().collect::<Vec<char>>()};($next:expr, usize1) => (read_value!($next, usize) - 1);($next:expr, [ $t:tt ]) => {{let len = read_value!($next, usize);read_value!($next, [$t; len])}};($next:expr, $t:ty) => ($next().parse::<$t>().expect("Parse error"));}trait Change { fn chmax(&mut self, x: Self); fn chmin(&mut self, x: Self); }impl<T: PartialOrd> Change for T {fn chmax(&mut self, x: T) { if *self < x { *self = x; } }fn chmin(&mut self, x: T) { if *self > x { *self = x; } }}fn powmod(x: i64, mut e: i64, m: i64) -> i64 {let mut sum = 1;let mut cur = x % m;while e > 0 {if e % 2 != 0 {sum = sum * cur % m;}cur = cur * cur % m;e /= 2;}sum}// p must be prime.// Returns (B, H) where HB = A, rows(B) = rank(A)// A: n * m, B: r * m, H: n * rfn find_basis_mod_p(a: &[Vec<i64>], p: i64) -> (Vec<Vec<i64>>, Vec<Vec<i64>>) {let n = a.len();let m = a[0].len();let aold = a.clone();let mut a = a.to_vec();let mut pos = vec![];let mut c = 0;let mut r = n;// TODO no pivotingfor i in 0..n {while c < m && a[i][c] == 0 {c += 1;}if c >= m {r = i;break;}pos.push(c);let aic = a[i][c];let aicinv = powmod(aic, p - 2, p);a[i][c] = 1.into();for j in c + 1..m {a[i][j] *= aicinv;a[i][j] %= p;}for j in 0..n {if i == j { continue; }let ajc = a[j][c];a[j][c] = 0;for k in c + 1..m {let val = ajc * a[i][k] % p;a[j][k] -= val;if a[j][k] < 0 {a[j][k] += p;}}}}let mut tr = vec![vec![0; r]; n];for i in 0..n {let mut cur = aold[i].clone();for j in 0..r {let idx = pos[j];let val = cur[idx];tr[i][j] = val;for k in idx + 1..m {cur[k] -= val * a[j][k] % p;if cur[k] < 0 {cur[k] += p;}}}}(a[..r].to_vec(), tr)}// https://yukicoder.me/problems/no/2405 (3.5)// 行列のランクを r としたとき、最適値は NM あるいは r(N + M) のどちらかと思われる。(つまり行列 1 個か 2 個)fn main() {// In order to avoid potential stack overflow, spawn a new thread.let stack_size = 104_857_600; // 100 MBlet thd = std::thread::Builder::new().stack_size(stack_size);thd.spawn(|| solve()).unwrap().join().unwrap();}fn solve() {let out = std::io::stdout();let mut out = BufWriter::new(out.lock());macro_rules! puts {($($format:tt)*) => (let _ = write!(out,$($format)*););}#[allow(unused)]macro_rules! putvec {($v:expr) => {for i in 0..$v.len() {puts!("{}{}", $v[i], if i + 1 == $v.len() {"\n"} else {" "});}}}input! {p: i64,n: usize, m: usize,a: [[i64; m]; n],}let (b, h) = find_basis_mod_p(&a, p);let r = b.len();if r * (m + n) > n * m {puts!("1\n{} {}\n", n, m);for i in 0..n {putvec!(a[i]);}return;}puts!("2\n{} {}\n", n, r);for i in 0..n {putvec!(h[i]);}puts!("{} {}\n", r, m);for i in 0..r {putvec!(b[i]);}}