結果

問題 No.2411 Reverse Directions
ユーザー square1001
提出日時 2023-08-11 21:52:49
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 20 ms / 2,000 ms
コード長 2,804 bytes
コンパイル時間 984 ms
コンパイル使用メモリ 88,692 KB
最終ジャッジ日時 2025-02-16 01:17:43
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 29
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <queue>
#include <string>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
const int INF = 1012345678;
const vector<int> dx = { 0, 1, 0, -1 };
const vector<int> dy = { 1, 0, -1, 0 };
const string ds = "RDLU";
vector<vector<int> > distance(int H, int W, const vector<string>& S, int sx, int sy) {
vector<vector<int> > dist(H, vector<int>(W, INF));
dist[sx][sy] = 0;
queue<int> que;
que.push(sx * W + sy);
while (!que.empty()) {
int cx = que.front() / W;
int cy = que.front() % W;
que.pop();
for (int i = 0; i < 4; i++) {
int tx = cx + dx[i];
int ty = cy + dy[i];
if (0 <= tx && tx < H && 0 <= ty && ty < W && S[tx][ty] == '.' && dist[tx][ty] == INF) {
dist[tx][ty] = dist[cx][cy] + 1;
que.push(tx * W + ty);
}
}
}
return dist;
}
int main() {
int H, W, K, L, R;
cin >> H >> W >> K >> L >> R;
L -= 1;
vector<string> S(H);
for (int i = 0; i < H; i++) {
cin >> S[i];
}
if ((R - L) % 2 == 1) {
cout << "No" << endl;
}
else {
vector<vector<int> > d1 = distance(H, W, S, 0, 0);
vector<vector<int> > d2 = distance(H, W, S, H - 1, W - 1);
bool found = false;
string answer;
for (int i = 0; i < H && !found; i++) {
for (int j = 0; j < W && !found; j++) {
if (d1[i][j] <= L && d1[i][j] % 2 == L % 2 && d2[i][j] <= K - R && d2[i][j] % 2 == (K - R) % 2) {
int bit = 0;
if (i != 0 && i != H - 1 && S[i - 1][j] == '.' && S[i + 1][j] == '.') {
bit |= 1;
}
if (j != 0 && j != W - 1 && S[i][j - 1] == '.' && S[i][j + 1] == '.') {
bit |= 2;
}
if (bit != 0) {
found = true;
int ax = i, ay = j;
for (int k = 0; k < L; k++) {
int best = INF, nx = -1, ny = -1, nd = -1;
for (int l = 0; l < 4; l++) {
int tx = ax + dx[l], ty = ay + dy[l];
if (0 <= tx && tx < H && 0 <= ty && ty < W && best > d1[tx][ty]) {
best = d1[tx][ty];
nx = tx;
ny = ty;
nd = l ^ 2;
}
}
answer += ds[nd];
ax = nx;
ay = ny;
}
reverse(answer.begin(), answer.end());
for (int i = L; i < R; i++) {
answer += (bit & 1 ? (i % 2 == 0 ? 'U' : 'D') : (i % 2 == 0 ? 'L' : 'R'));
}
int bx = i, by = j;
for (int k = R; k < K; k++) {
int best = INF, nx = -1, ny = -1, nd = -1;
for (int l = 0; l < 4; l++) {
int tx = bx + dx[l], ty = by + dy[l];
if (0 <= tx && tx < H && 0 <= ty && ty < W && best > d2[tx][ty]) {
best = d2[tx][ty];
nx = tx;
ny = ty;
nd = l;
}
}
answer += ds[nd];
bx = nx;
by = ny;
}
}
}
}
}
if (!found) {
cout << "No" << endl;
}
else {
cout << "Yes" << endl;
cout << answer << endl;
}
}
return 0;
}
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