結果

問題 No.2411 Reverse Directions
ユーザー woodywoodywoodywoody
提出日時 2023-08-11 22:20:15
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 6,987 bytes
コンパイル時間 4,439 ms
コンパイル使用メモリ 244,584 KB
実行使用メモリ 23,760 KB
最終ジャッジ日時 2024-11-18 16:49:07
合計ジャッジ時間 8,872 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 WA -
testcase_01 AC 2 ms
6,820 KB
testcase_02 AC 2 ms
6,816 KB
testcase_03 AC 2 ms
6,820 KB
testcase_04 WA -
testcase_05 AC 2 ms
6,820 KB
testcase_06 AC 2 ms
6,816 KB
testcase_07 AC 12 ms
17,152 KB
testcase_08 AC 2 ms
6,824 KB
testcase_09 AC 2 ms
6,816 KB
testcase_10 WA -
testcase_11 WA -
testcase_12 WA -
testcase_13 AC 27 ms
9,060 KB
testcase_14 WA -
testcase_15 WA -
testcase_16 AC 5 ms
6,816 KB
testcase_17 WA -
testcase_18 WA -
testcase_19 AC 2 ms
6,820 KB
testcase_20 WA -
testcase_21 AC 35 ms
13,432 KB
testcase_22 WA -
testcase_23 AC 45 ms
12,388 KB
testcase_24 WA -
testcase_25 AC 10 ms
6,820 KB
testcase_26 AC 6 ms
6,820 KB
testcase_27 AC 23 ms
7,936 KB
testcase_28 WA -
testcase_29 WA -
testcase_30 WA -
testcase_31 AC 68 ms
17,052 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,b) for(int i=0;i<b;i++)
#define rrep(i,b) for(int i=b-1;i>=0;i--)
#define rep1(i,b) for(int i=1;i<b;i++)
#define repx(i,x,b) for(int i=x;i<b;i++)
#define rrepx(i,x,b) for(int i=b-1;i>=x;i--)
#define fore(i,a) for(auto& i:a)
#define rng(x) (x).begin(), (x).end()
#define rrng(x) (x).rbegin(), (x).rend()
#define sz(x) ((int)(x).size())
#define pb push_back
#define fi first
#define se second
#define pcnt __builtin_popcountll

using namespace std;
using namespace atcoder;

using ll = long long;
using ld = long double;
template<typename T> using mpq = priority_queue<T, vector<T>, greater<T>>;
template<typename T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<typename T> bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
template<typename T> ll sumv(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;}
bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}}
#define retval(x) {cout << #x << endl; return;}
#define cout2(x,y) cout << x << " " << y << endl;
#define coutp(p) cout << p.fi << " " << p.se << endl;
#define out cout << ans << endl;
#define outd cout << fixed << setprecision(20) << ans << endl;
#define outm cout << ans.val() << endl;
#define outv fore(yans , ans) cout << yans << "\n";
#define outdv fore(yans , ans) cout << yans.val() << "\n";
#define coutv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;}
#define coutv2(v) fore(vy , v) cout << vy << "\n";
#define coutvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;}
#define coutvm2(v) fore(vy , v) cout << vy.val() << "\n";
using pll = pair<ll,ll>;using pil = pair<int,ll>;using pli = pair<ll,int>;using pii = pair<int,int>;using pdd = pair<ld,ld>;
using vi = vector<int>;using vd = vector<ld>;using vl = vector<ll>;using vs = vector<string>;using vb = vector<bool>;
using vpii = vector<pii>;using vpli = vector<pli>;using vpll = vector<pll>;using vpil = vector<pil>;
using vvi = vector<vector<int>>;using vvl = vector<vector<ll>>;using vvs = vector<vector<string>>;using vvb = vector<vector<bool>>;
using vvpii = vector<vector<pii>>;using vvpli = vector<vector<pli>>;using vvpll = vector<vpll>;using vvpil = vector<vpil>;
using mint = modint998244353;
//using mint = modint1000000007;
//using mint = dynamic_modint<0>;
using vm = vector<mint>;
using vvm = vector<vector<mint>>;
vector<int> dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1};
ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;}
ll lcm(ll a, ll b) { return a/gcd(a,b)*b;}
#define yes {cout <<"Yes"<<endl;}
#define no {cout <<"No"<<endl;}
const double eps = 1e-10;
const ll LINF = 1001002003004005006ll;
const int INF = 1001001001;
#ifdef MY_LOCAL_DEBUG
#define show(x) cerr<<#x<<" = "<<x<<endl
#define showp(p) cerr<<#p<<" = "<<p.fi<<" : "<<p.se<<endl
#define show2(x,y) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<endl
#define show3(x,y,z) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<endl
#define show4(x,y,z,x2) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<" : "<<#x2<<" = "<<x2<<endl
#define test(x) cout << "test" << x << endl
#define showv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;}
#define showv2(v) fore(vy , v) cout << vy << "\n";
#define showvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;}
#define showvm2(v) fore(vy , v) cout << vy.val() << "\n";
#else
#define show(x)
#define showp(p)
#define show2(x,y)
#define show3(x,y,z)
#define show4(x,y,z,x2)
#define test(x)
#define showv(v)
#define showv2(v)
#define showvm(v)
#define showvm2(v)
#endif

struct edge{
    int from,to;
    ll cost;

    edge(int from_=0,int to_=0,ll cost_=0) : from(from_),to(to_),cost(cost_) {}
    bool operator<(const edge& ot){
        return cost < ot.cost;
    }
};

void solve(){
    int h,w,k,l,r; cin>>h>>w>>k>>l>>r;

    vector<vector<edge>> e(h*w);
    vs s(h);
    rep(i,h) cin>>s[i];
    vvi p(2,vi(h*w,-1));

    rep(i,h) rep(j,w){
        if (s[i][j] == '#') continue;
        rep(kk,4){
            int x,y;
            x = i + dx[kk];
            y = j + dy[kk];
            if (x <= h-1 && x >= 0 && y <= w-1 && y >= 0 && s[x][y]=='.'){
                e[i*w + j].pb(edge(i*w + j, x*w + y , 1));
            }
        }
    }
    int d1 = l-1;
    int d2 = (k-r);

    vvl dist(2 , vl(h*w,LINF));
    rep(i,2){
        mpq<pli> q;
        
        int st = (h*w-1)*i;
        dist[i][st] = 0;
        q.push({dist[i][st] , st});
        
        while(!q.empty()){
            pli pp = q.top();
            q.pop();
            ll nowDist = pp.first;
            int from = pp.second;
        
            if (dist[i][from] < nowDist) continue;
        
            fore(ey , e[from]){
                int to = ey.to;
                ll cost = ey.cost;
        
                if (chmin(dist[i][to] , nowDist + cost)){
                    p[i][to] = from;
                    q.push({dist[i][to] , to});
                }
            }
        }
    }
    retval(No);
    bool ok = false;
    string ans;
    rep(i,h) rep(j,w){
        int f = i*w + j;
        if (ans != "") continue;
        if (dist[0][f] > d1) continue;
        if (dist[1][f] > d2) continue;
        if (dist[0][f]%2 != d1%2) continue;
        if (dist[1][f]%2 != d2%2) continue;
        if ((r-l+1)%2==1) continue;
        rep(kk,4){
            if (ans!="") continue;
            int x,y;
            x = i + dx[kk];
            y = j + dy[kk];
            if (x <= h-1 && x >= 0 && y <= w-1 && y >= 0 && s[x][y]=='.'){
                ok = true;
                int now = f;
                auto getChar = [&](int a,int b){
                    char ret;
                    if (abs(b-a)==1){
                        if (b>a) ret = 'L';
                        else ret = 'R';
                    }else{
                        if (b>a) ret = 'U';
                        else ret = 'D';
                    }
                    return ret;
                };
                while(now!=0){
                    int nxt = p[0][now];
                    ans += getChar(now,nxt);
                    swap(now,nxt);
                }
                string ss;
                if (kk==0) ss = "DU";
                else if(kk==1) ss = "RL";
                else if(kk==2) ss = "UD";
                else ss = "LR";
                reverse(rng(ans));
                int cnt = (r-l+1) + (d1 - dist[0][f]) + (d2 - dist[1][f]);
                cnt /= 2;
                rep(ii,cnt) ans += ss;
                now = f;
                while(now!=(h*w-1)){
                    int nxt = p[1][now];
                    ans += getChar(nxt,now);
                    swap(now,nxt);
                }
            }
        }
    }
    if (!ok){
        retval(No);
    }
    yes;
    out;

    return;
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);

    int t = 1;
    //cin>>t;

    rep(i,t){
        solve();
    }

    return 0;
}
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