結果

問題 No.2411 Reverse Directions
ユーザー chro_96
提出日時 2023-08-11 23:08:05
言語 C
(gcc 13.3.0)
結果
AC  
実行時間 16 ms / 2,000 ms
コード長 3,988 bytes
コンパイル時間 1,374 ms
コンパイル使用メモリ 33,824 KB
実行使用メモリ 8,452 KB
最終ジャッジ日時 2024-11-18 18:25:29
合計ジャッジ時間 2,061 ms
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 29
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <stdio.h>
int dmap[4][2] = { { -1, 0 }, { 1, 0 }, { 0, -1 }, { 0, 1 } };
char dchar[4] = { 'U', 'D', 'L', 'R' };
int main () {
int h = 0;
int w = 0;
int k = 0;
int l = 0;
int r = 0;
char s[500][501] = {};
int res = 0;
int is_ok = 0;
char t[500001] = "";
int d[500][500][2] = {};
int prev[500][500][2] = {};
int q[250000][2] = {};
int q_hd = 0;
int q_tl = 0;
res = scanf("%d", &h);
res = scanf("%d", &w);
res = scanf("%d", &k);
res = scanf("%d", &l);
res = scanf("%d", &r);
for (int i = 0; i < h; i++) {
res = scanf("%s", s[i]);
}
if ((r-l)%2 == 0) {
printf("No\n");
return 0;
}
for (int i = 0; i < h; i++) {
for (int j = 0; j < w; j++) {
d[i][j][0] = h*w;
d[i][j][1] = h*w;
}
}
d[0][0][0] = 0;
q[q_tl][0] = 0;
q[q_tl][1] = 0;
prev[0][0][0] = -1;
q_tl++;
while (q_hd < q_tl) {
int ci = q[q_hd][0];
int cj = q[q_hd][1];
int tmp_d = d[ci][cj][0];
q_hd++;
for (int i = 0; i < 4; i++) {
int ni = ci+dmap[i][0];
int nj = cj+dmap[i][1];
if (ni >= 0 && ni < h && nj >= 0 && nj < w && s[ni][nj] == '.' && d[ni][nj][0] >= h*w) {
d[ni][nj][0] = tmp_d+1;
prev[ni][nj][0] = i;
q[q_tl][0] = ni;
q[q_tl][1] = nj;
q_tl++;
}
}
}
q_hd = 0;
q_tl = 0;
d[h-1][w-1][1] = 0;
q[q_tl][0] = h-1;
q[q_tl][1] = w-1;
prev[h-1][w-1][1] = -1;
q_tl++;
while (q_hd < q_tl) {
int ci = q[q_hd][0];
int cj = q[q_hd][1];
int tmp_d = d[ci][cj][1];
q_hd++;
for (int i = 0; i < 4; i++) {
int ni = ci+dmap[i][0];
int nj = cj+dmap[i][1];
if (ni >= 0 && ni < h && nj >= 0 && nj < w && s[ni][nj] == '.' && d[ni][nj][1] >= h*w) {
d[ni][nj][1] = tmp_d+1;
prev[ni][nj][1] = i;
q[q_tl][0] = ni;
q[q_tl][1] = nj;
q_tl++;
}
}
}
for (int i = 0; i < h; i++) {
for (int j = 1; j < w-1; j++) {
if (is_ok <= 0 && d[i][j][0] < h*w && d[i][j][0] < l && d[i][j][0]%2 != l%2 && s[i][j-1] == '.' && s[i][j+1] == '.' && d[i][j][1] < h*w &&
          d[i][j][1] <= k-r && d[i][j][1]%2 == (k-r)%2) {
int ti = i;
int tj = j;
is_ok = 1;
for (int p = d[i][j][0]; p > 0; p--) {
int ni = ti+dmap[((prev[ti][tj][0])^1)][0];
int nj = tj+dmap[((prev[ti][tj][0])^1)][1];
t[p-1] = dchar[prev[ti][tj][0]];
ti = ni;
tj = nj;
}
for (int p = d[i][j][0]; p < k-d[i][j][1]; p++) {
t[p] = dchar[2+p%2];
}
ti = i;
tj = j;
for (int p = k-d[i][j][1]; p < k; p++) {
int ni = ti+dmap[((prev[ti][tj][1])^1)][0];
int nj = tj+dmap[((prev[ti][tj][1])^1)][1];
t[p] = dchar[((prev[ti][tj][1])^1)];
ti = ni;
tj = nj;
}
t[k] = '\0';
}
}
}
for (int i = 1; i < h-1; i++) {
for (int j = 0; j < w; j++) {
if (is_ok <= 0 && d[i][j][0] < h*w && d[i][j][0] < l && d[i][j][0]%2 != l%2 && s[i-1][j] == '.' && s[i+1][j] == '.' && d[i][j][1] < h*w &&
          d[i][j][1] <= k-r && d[i][j][1]%2 == (k-r)%2) {
int ti = i;
int tj = j;
is_ok = 1;
for (int p = d[i][j][0]; p > 0; p--) {
int ni = ti+dmap[((prev[ti][tj][0])^1)][0];
int nj = tj+dmap[((prev[ti][tj][0])^1)][1];
t[p-1] = dchar[prev[ti][tj][0]];
ti = ni;
tj = nj;
}
for (int p = d[i][j][0]; p < k-d[i][j][1]; p++) {
t[p] = dchar[p%2];
}
ti = i;
tj = j;
for (int p = k-d[i][j][1]; p < k; p++) {
int ni = ti+dmap[((prev[ti][tj][1])^1)][0];
int nj = tj+dmap[((prev[ti][tj][1])^1)][1];
t[p] = dchar[((prev[ti][tj][1])^1)];
ti = ni;
tj = nj;
}
t[k] = '\0';
}
}
}
if (is_ok > 0) {
printf("Yes\n%s\n", t);
} else {
printf("No\n");
}
return 0;
}
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