結果

問題 No.2176 LRM Question 1
ユーザー poyonpoyon
提出日時 2023-08-13 22:26:06
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 16 ms / 2,000 ms
コード長 9,306 bytes
コンパイル時間 2,157 ms
コンパイル使用メモリ 207,488 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2024-11-21 16:28:03
合計ジャッジ時間 3,230 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,816 KB
testcase_01 AC 2 ms
6,816 KB
testcase_02 AC 16 ms
6,816 KB
testcase_03 AC 2 ms
6,816 KB
testcase_04 AC 2 ms
6,816 KB
testcase_05 AC 1 ms
6,820 KB
testcase_06 AC 2 ms
6,816 KB
testcase_07 AC 2 ms
6,816 KB
testcase_08 AC 2 ms
6,816 KB
testcase_09 AC 2 ms
6,820 KB
testcase_10 AC 14 ms
6,816 KB
testcase_11 AC 2 ms
6,816 KB
testcase_12 AC 1 ms
6,816 KB
testcase_13 AC 14 ms
6,816 KB
testcase_14 AC 16 ms
6,820 KB
testcase_15 AC 14 ms
6,820 KB
testcase_16 AC 10 ms
6,820 KB
testcase_17 AC 2 ms
6,816 KB
testcase_18 AC 13 ms
6,816 KB
testcase_19 AC 10 ms
6,816 KB
testcase_20 AC 4 ms
6,816 KB
testcase_21 AC 8 ms
6,820 KB
testcase_22 AC 3 ms
6,820 KB
testcase_23 AC 7 ms
6,820 KB
testcase_24 AC 8 ms
6,816 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

// clang-format off
#ifdef _LOCAL
    #include <pch.hpp>
#else
    #include <bits/stdc++.h>
    #define cerr if (false) cerr
    #define debug_bar
    #define debug(...)
    #define debug2(vv)
    #define debug3(vvv)
#endif

using namespace std;
using ll = long long;
using ld = long double;
using str = string;
#define FOR(i,l,r) for (ll i = (l); i < (r); ++i)
#define RFOR(i,l,r) for (ll i = (r)-1; (l) <= i; --i)
#define REP(i,n) FOR(i,0,n)
#define RREP(i,n) RFOR(i,0,n)
#define ALL(c) (c).begin(), (c).end()
#define SORT(c) sort(ALL(c))
#define RSORT(c) sort((c).rbegin(), (c).rend())
#define MIN(c) *min_element(ALL(c))
#define MAX(c) *max_element(ALL(c))
#define COUNT(c,v) count(ALL(c),(v))
#define SZ(c) ((ll)(c).size())
#define BIT(b,i) (((b)>>(i)) & 1)
#define PCNT(b) ((ll)__builtin_popcountll(b))
#define LB(c,v) distance((c).begin(), lower_bound(ALL(c), (v)))
#define UB(c,v) distance((c).begin(), upper_bound(ALL(c), (v)))
#define UQ(c) do { SORT(c); (c).erase(unique(ALL(c)), (c).end()); (c).shrink_to_fit(); } while (0)
#define END(...) do { print(__VA_ARGS__); exit(0); } while (0)
template<class... T> void input(T&... a) { (cin >> ... >> a); }
void print() { cout << '\n'; }
template<class T> void print(const T& a) { cout << a << '\n'; }
template<class P1, class P2> void print(const pair<P1, P2>& a) { cout << a.first << " " << a.second << '\n'; }
template<class T, class... Ts> void print(const T& a, const Ts&... b) { cout << a; (cout << ... << (cout << ' ', b)); cout << '\n'; }
template<class T> void cout_line(const vector<T>& ans, int l, int r) { for (int i = l; i < r; i++) { if (i != l) { cout << ' '; } cout << ans[i]; } cout << '\n'; }
template<class T> void print(const vector<T>& a) { cout_line(a, 0, a.size()); }
template<class T> bool chmin(T& a, const T b) { if (b < a) { a = b; return 1; } return 0; }
template<class T> bool chmax(T& a, const T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> T SUM(const vector<T>& A) { return accumulate(ALL(A), T(0)); }
template<class T> vector<T> cumsum(const vector<T>& A, bool offset = false) { int N = A.size(); vector<T> S(N+1, 0); for (int i = 0; i < N; i++) { S[i+1] = S[i] + A[i]; } if (not offset) { S.erase(S.begin()); } return S; }
template<class T> string to_binary(T x, int B = 0) { string s; while (x) { s += ('0' + (x & 1)); x >>= 1; } while ((int)s.size() < B) { s += '0'; } reverse(s.begin(), s.end()); return s; }
template<class F> ll binary_search(const F& is_ok, ll ok, ll ng) { while (abs(ok - ng) > 1) { ll m = (ok + ng) / 2; (is_ok(m) ? ok : ng) = m; } return ok; }
template<class F> double binary_search_real(const F& is_ok, double ok, double ng, int iter = 90) { for (int i = 0; i < iter; i++) { double m = (ok + ng) / 2; (is_ok(m) ? ok : ng) = m; } return ok; }
template<class T> ll len(const vector<T>& a) { return (ll)a.size(); }
ll min(int a, ll b) { return min((ll)a, b); }
ll min(ll a, int b) { return min(a, (ll)b); }
ll max(int a, ll b) { return max((ll)a, b); }
ll max(ll a, int b) { return max(a, (ll)b); }
ll mod(ll x, ll m) { assert(m > 0); return (x % m + m) % m; }
ll ceil(ll a, ll b) { if (b < 0) { return ceil(-a, -b); } assert(b > 0); return (a < 0 ? a / b : (a + b - 1) / b); }
ll floor(ll a, ll b) { if (b < 0) { return floor(-a, -b); } assert(b > 0); return (a > 0 ? a / b : (a - b + 1) / b); }
ll powint(ll x, ll n) { assert(n >= 0); if (n == 0) { return 1; }; ll res = powint(x, n>>1); res *= res; if (n & 1) { res *= x; } return res; }
pair<ll,ll> divmod(ll a, ll b) { assert(b != 0); ll q = floor(a, b); return make_pair(q, a - q * b); }
ll bitlen(ll b) { if (b <= 0) { return 0; } return (64LL - __builtin_clzll(b)); }
ll digitlen(ll n) { assert(n >= 0); if (n == 0) { return 1; } ll sum = 0; while (n > 0) { sum++; n /= 10; } return sum; }
ll msb(ll b) { return (b <= 0 ? -1 : (63 - __builtin_clzll(b))); }
ll lsb(ll b) { return (b <= 0 ? -1 : __builtin_ctzll(b)); }
int a2i(const char& c) { assert(islower(c)); return (c - 'a'); }
int A2i(const char& c) { assert(isupper(c)); return (c - 'A'); }
int d2i(const char& d) { assert(isdigit(d)); return (d - '0'); }
char i2a(const int& i) { assert(0 <= i && i < 26); return ('a' + i); }
char i2A(const int& i) { assert(0 <= i && i < 26); return ('A' + i); }
char i2d(const int& i) { assert(0 <= i && i <= 9); return ('0' + i); }
template<class T> using PQ_max = priority_queue<T>;
template<class T> using PQ_min = priority_queue<T, vector<T>, greater<T>>;
using P = pair<ll,ll>;
using VP = vector<P>;
using VVP = vector<VP>;
using VC = vector<char>;
using VS = vector<string>;
using VVS = vector<VS>;
using VI = vector<int>;
using VVI = vector<VI>;
using VVVI = vector<VVI>;
using VLL = vector<ll>;
using VVLL = vector<VLL>;
using VVVLL = vector<VVLL>;
using VB = vector<bool>;
using VVB = vector<VB>;
using VVVB = vector<VVB>;
using VD = vector<double>;
using VVD = vector<VD>;
using VVVD = vector<VVD>;
using VLD = vector<ld>;
using VVLD = vector<VLD>;
using VVVLD = vector<VVLD>;
const ld EPS = 1e-10;
const ld PI  = acosl(-1.0);
constexpr int inf = (1 << 30) - 1;   // 1073741824 - 1
constexpr ll INF = (1LL << 62) - 1;  // 4611686018427387904 - 1
// --------------------------------------------------------

#include <atcoder/modint>
using namespace atcoder;

// constexpr ll MOD = 1000003;
using mint = modint;

// using mint = modint1000000007;
// using mint = modint998244353;

using VM = vector<mint>;
using VVM = vector<VM>;
using VVVM = vector<VVM>;
using VVVVM = vector<VVVM>;

// template<int M> istream &operator>>(istream &is, static_modint<M> &m) { ll v; is >> v; m = v; return is; }
// template<int M> istream &operator>>(istream &is, dynamic_modint<M> &m) { ll v; is >> v; m = v; return is; }
// template<int M> ostream &operator<<(ostream &os, const static_modint<M> &m) { return os << m.val(); }
// template<int M> ostream &operator<<(ostream &os, const dynamic_modint<M> &m) { return os << m.val(); }
istream &operator>>(istream &is, mint &m) { ll v; is >> v; m = v; return is; }
ostream &operator<<(ostream &os, const mint &m) { return os << m.val(); }
void input(mint& a) { cin >> a; }
void print(const mint& a) { cout << a << '\n'; }
void print(const vector<mint>& A) { for (int i = 0; i < (int)A.size(); i++) { cout << A[i] << " \n"[i == (int)A.size() - 1]; } }

// It is assumed that M (= mod) is prime number
struct combination {
  public:
    combination() : combination(1) {}
    combination(int n) : N(1), _fact(2,1), _ifact(2,1) {
        M = mint().mod();
        assert(0 < n && n < M);
        if (N < n) { build(n); }
    }

    mint P(int n, int k) {
        if (N < n) { build(n); }
        if (n < 0 || k < 0 || n < k) { return 0; }
        return _fact[n] * _ifact[n-k];
    }
    mint C(int n, int k) {
        if (N < n) { build(n); }
        if (n < 0 || k < 0 || n < k) { return 0; }
        return _fact[n] * _ifact[n-k] * _ifact[k];
    }
    mint H(int n, int k) {
        if (n == 0 && k == 0) { return 1; }
        if (n < 0 || k < 0) { return 0; }
        return C(n + k - 1, k);
    }
    mint fact(int n) {
        if (N < n) { build(n); }
        if (n < 0) { return 0; }
        return _fact[n];
    }
    mint ifact(int n) {
        if (N < n) { build(n); }
        if (n < 0) { return 0; }
        return _ifact[n];
    }
    mint P_naive(ll n, int k) const noexcept {
        if (n < 0 || k < 0 || n < k) { return 0; }
        mint res = 1;
        for (int i = 1; i <= k; i++) { res *= (n - i + 1); }
        return res;
    }
    mint C_naive(ll n, int k) const noexcept {
        if (n < 0 || k < 0 || n < k) { return 0; }
        if (k > n - k) { k = n - k; }
        mint nume = 1, deno = 1;
        for (int i = 1; i <= k; i++) { nume *= (n - i + 1); deno *= i; }
        return nume / deno;
    }
    mint H_naive(ll n, int k) const noexcept {
        if (n == 0 && k == 0) { return 1; }
        if (n < 0 || k < 0) { return 0; }
        return C_naive(n + k - 1, k);
    }
    mint catalan(int n) {
        if (N < 2 * n) { build(2 * n); }
        return _fact[2 * n] * _ifact[n + 1] * _ifact[n];
    }
    template<class... Ts>
    mint C_multinomial(int n, int k, Ts... ks) {
        if (N < n) { build(n); }
        if (n < 0 || k < 0 || n < k) { return 0; }
        return C_multinomial(n, ks...) * _ifact[k];
    }
    mint C_multinomial(int n, int k) {
        if (N < n) { build(n); }
        if (n < 0 || k < 0 || n < k) { return 0; }
        return _fact[n] * _ifact[k];
    }

  private:
    int N;
    int M;  // mod
    vector<mint> _fact, _ifact;

    void build(int N_new) {
        assert(N < N_new);
        assert(N_new < M);
        _fact.resize(N_new + 1);
        _ifact.resize(N_new + 1);
        for (int i = N + 1; i <= N_new; i++) { _fact[i] = _fact[i - 1] * i; }
        _ifact[N_new] = _fact[N_new].inv();
        for (int i = N_new - 1; N + 1 <= i; i--) { _ifact[i] = _ifact[i + 1] * (i + 1); }
        N = N_new;
    }
};

// clang-format on
int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout << fixed << setprecision(15);

    ll L, R, M;
    input(L, R, M);

    mint::set_mod(M);

    mint ans = 0;
    mint prod = 1;
    mint fact = 1;
    FOR (n, 1, min(R, M) + 1) {
        fact *= n;
        prod *= fact;
        if (L <= n && n <= R) { ans += prod; }
    }
    print(ans);

    return 0;
}
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