結果
| 問題 |
No.2405 Minimal Matrix Decomposition
|
| コンテスト | |
| ユーザー |
gr1msl3y
|
| 提出日時 | 2023-08-17 17:41:22 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,676 bytes |
| コンパイル時間 | 557 ms |
| コンパイル使用メモリ | 82,024 KB |
| 実行使用メモリ | 79,472 KB |
| 最終ジャッジ日時 | 2024-11-26 16:07:00 |
| 合計ジャッジ時間 | 12,463 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 42 WA * 4 |
ソースコード
def prod(A, B, MOD):
n = len(A)
m = len(B[0])
res = [[0]*m for _ in range(n)]
for i in range(n):
for j in range(m):
for k in range(len(B)):
res[i][j] += A[i][k]*B[k][j] % MOD
res[i][j] %= MOD
return res
P = int(input())
N, M = map(int, input().split())
A = [list(map(int, input().split())) for _ in range(N)]
if A == [[0]*M for _ in range(N)]:
if min(N, M) == 1:
print(1)
print(N, M)
for _ in range(N):
print(*[0]*M)
else:
print(2)
print(N, 1)
for _ in range(N):
print(0)
print(1, M)
print(*[0]*M)
exit()
B = [a[:] for a in A]
for r in range(N):
for i in range(r, N):
flag = 0
for p in range(M):
if B[i][p] != 0:
flag = 1
break
if flag:
break
else:
break
B[r], B[i] = B[i], B[r]
inv = pow(B[r][p], P-2, P)
for j in range(M):
B[r][j] = B[r][j]*inv % P
for i in range(N):
if i == r:
continue
v = B[i][p]
for j in range(M):
B[i][j] -= v*B[r][j] % P
B[i][j] %= P
r = min(r, M)
if r*(N+M) >= N*M:
print(1)
print(N, M)
for a in A:
print(*a)
exit()
plist = []
p = 0
for i in range(N):
while p < M:
if B[i][p] == 1:
break
p += 1
else:
break
plist.append(p)
p += 1
res0 = [[a[ind] for ind in plist] for a in A]
res1 = B[:r]
print(2)
print(N, r)
for res in res0:
print(*res)
print(r, M)
for res in res1:
print(*res)
# print(prod(res0,res1,P))
gr1msl3y