結果
| 問題 |
No.2428 Returning Shuffle
|
| コンテスト | |
| ユーザー |
Kude
|
| 提出日時 | 2023-08-18 21:26:25 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 239 ms / 2,000 ms |
| コード長 | 3,112 bytes |
| コンパイル時間 | 2,076 ms |
| コンパイル使用メモリ | 227,292 KB |
| 最終ジャッジ日時 | 2025-02-16 09:35:38 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 23 |
コンパイルメッセージ
main.cpp: In function ‘std::pair<std::vector<int>, std::vector<int> > {anonymous}::primes_lpf(int)’:
main.cpp:33:48: warning: result of ‘2^4’ is 6; did you mean ‘1 << 4’ (16)? [-Wxor-used-as-pow]
33 | for (; x <= n5; x += add_next, add_next ^= 2 ^ 4) {
| ^
| -
| 1 <<
main.cpp:33:46: note: you can silence this warning by using a hexadecimal constant (0x2 rather than 2)
33 | for (; x <= n5; x += add_next, add_next ^= 2 ^ 4) {
| ^
| 0x2
main.cpp:47:47: warning: result of ‘2^4’ is 6; did you mean ‘1 << 4’ (16)? [-Wxor-used-as-pow]
47 | for (; x <= n; x += add_next, add_next ^= 2 ^ 4) {
| ^
| -
| 1 <<
main.cpp:47:45: note: you can silence this warning by using a hexadecimal constant (0x2 rather than 2)
47 | for (; x <= n; x += add_next, add_next ^= 2 ^ 4) {
| ^
| 0x2
ソースコード
#include<bits/stdc++.h>
namespace {
#pragma GCC diagnostic ignored "-Wunused-function"
#include<atcoder/all>
#pragma GCC diagnostic warning "-Wunused-function"
using namespace std;
using namespace atcoder;
#define rep(i,n) for(int i = 0; i < (int)(n); i++)
#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; i--)
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
template<class T> bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; } else return false; }
template<class T> bool chmin(T& a, const T& b) { if (b < a) { a = b; return true; } else return false; }
using ll = long long;
using P = pair<int,int>;
using VI = vector<int>;
using VVI = vector<VI>;
using VL = vector<ll>;
using VVL = vector<VL>;
using mint = modint998244353;
pair<vector<int>, vector<int>> primes_lpf(const int n) {
vector<int> primes; primes.reserve(n / 10);
vector<int> lpf(n + 1);
for (int i = 2; i <= n; i += 2) lpf[i] = 2;
for (int i = 3; i <= n; i += 6) lpf[i] = 3;
if (2 <= n) primes.push_back(2);
if (3 <= n) primes.push_back(3);
// 5 * x <= n, x <= floor(n / 5)
const int n5 = n / 5;
int x = 5;
char add_next = 2;
for (; x <= n5; x += add_next, add_next ^= 2 ^ 4) {
int px = lpf[x];
if (px == 0) {
lpf[x] = px = x;
primes.push_back(x);
}
for (int i = 2;; ++i) {
int q = primes[i];
int y = q * x;
if (y > n) break;
lpf[y] = q;
if (q == px) break;
}
}
for (; x <= n; x += add_next, add_next ^= 2 ^ 4) {
if (lpf[x] == 0) {
lpf[x] = x;
primes.push_back(x);
}
}
return {move(primes), move(lpf)};
}
constexpr int PSIZE = 1000010;
auto [primes, lpf] = primes_lpf(PSIZE);
vector<pair<int, int>>& factorize_lv(int x) {
int ps[10], cs[10];
int sz = 0;
while (x != 1) {
int p = lpf[x], c = 0;
do {x /= p; c++;} while (x % p == 0);
ps[sz] = p; cs[sz] = c; sz++;
}
static vector<pair<int, int>> fs;
fs.clear();
for (int i = 0; i < sz; i++) fs.emplace_back(ps[i], cs[i]);
return fs;
}
vector<vector<int>> cycle_decomposition(const vector<int>& a) {
const int n = a.size();
vector<char> visited(n);
vector<vector<int>> res;
for(int i = 0; i < n; i++) if (!visited[i]) {
res.emplace_back();
auto& vs = res.back();
int v = i;
do {
visited[v] = true;
vs.push_back(v);
v = a[v];
} while (v != i);
}
return res;
}
} int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int n, m;
cin >> n >> m;
VI s(n);
iota(all(s), 0);
VI s_inv(n);
iota(all(s_inv), 0);
rep(_, m) {
int t;
cin >> t;
static VI d;
d.resize(t);
rep(i, t) cin >> d[i], d[i]--;
static VI d_orig;
d_orig.resize(t);
rep(i, t) d_orig[i] = s_inv[d[i]];
rotate(d.begin(), d.begin() + 1, d.end());
rep(i, t) s[d_orig[i]] = d[i], s_inv[d[i]] = d_orig[i];
}
VI e(PSIZE);
for(const auto& c : cycle_decomposition(s)) {
for(auto [p, c] : factorize_lv(c.size())) {
chmax(e[p], c);
}
}
mint ans = 1;
rep(i, PSIZE) if (e[i]) {
ans *= mint(i).pow(e[i]);
}
cout << ans.val() << '\n';
}
Kude