結果
問題 | No.2435 Order All Company |
ユーザー | woodywoody |
提出日時 | 2023-08-18 23:16:48 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 5,818 bytes |
コンパイル時間 | 4,002 ms |
コンパイル使用メモリ | 237,764 KB |
実行使用メモリ | 14,976 KB |
最終ジャッジ日時 | 2024-11-28 10:10:03 |
合計ジャッジ時間 | 85,922 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
10,496 KB |
testcase_01 | AC | 2 ms
8,320 KB |
testcase_02 | AC | 2 ms
10,496 KB |
testcase_03 | AC | 2 ms
9,600 KB |
testcase_04 | TLE | - |
testcase_05 | TLE | - |
testcase_06 | TLE | - |
testcase_07 | TLE | - |
testcase_08 | TLE | - |
testcase_09 | TLE | - |
testcase_10 | TLE | - |
testcase_11 | TLE | - |
testcase_12 | TLE | - |
testcase_13 | TLE | - |
testcase_14 | TLE | - |
testcase_15 | TLE | - |
testcase_16 | TLE | - |
testcase_17 | TLE | - |
testcase_18 | TLE | - |
testcase_19 | TLE | - |
testcase_20 | AC | 14 ms
10,496 KB |
testcase_21 | TLE | - |
testcase_22 | TLE | - |
testcase_23 | TLE | - |
testcase_24 | TLE | - |
testcase_25 | TLE | - |
testcase_26 | TLE | - |
testcase_27 | TLE | - |
testcase_28 | AC | 14 ms
10,496 KB |
testcase_29 | TLE | - |
testcase_30 | TLE | - |
testcase_31 | AC | 2 ms
10,496 KB |
testcase_32 | AC | 2 ms
8,320 KB |
testcase_33 | AC | 2 ms
10,496 KB |
testcase_34 | TLE | - |
testcase_35 | TLE | - |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,b) for(int i=0;i<b;i++) #define rrep(i,b) for(int i=b-1;i>=0;i--) #define rep1(i,b) for(int i=1;i<b;i++) #define repx(i,x,b) for(int i=x;i<b;i++) #define rrepx(i,x,b) for(int i=b-1;i>=x;i--) #define fore(i,a) for(auto& i:a) #define rng(x) (x).begin(), (x).end() #define rrng(x) (x).rbegin(), (x).rend() #define sz(x) ((int)(x).size()) #define pb push_back #define fi first #define se second #define pcnt __builtin_popcountll using namespace std; using namespace atcoder; using ll = long long; using ld = long double; template<typename T> using mpq = priority_queue<T, vector<T>, greater<T>>; template<typename T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; } template<typename T> bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; } template<typename T> ll sumv(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}} #define retval(x) {cout << #x << endl; return;} #define cout2(x,y) cout << x << " " << y << endl; #define coutp(p) cout << p.fi << " " << p.se << endl; #define out cout << ans << endl; #define outd cout << fixed << setprecision(20) << ans << endl; #define outm cout << ans.val() << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define outdv fore(yans , ans) cout << yans.val() << "\n"; #define coutv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define coutv2(v) fore(vy , v) cout << vy << "\n"; #define coutvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define coutvm2(v) fore(vy , v) cout << vy.val() << "\n"; using pll = pair<ll,ll>;using pil = pair<int,ll>;using pli = pair<ll,int>;using pii = pair<int,int>;using pdd = pair<ld,ld>; using vi = vector<int>;using vd = vector<ld>;using vl = vector<ll>;using vs = vector<string>;using vb = vector<bool>; using vpii = vector<pii>;using vpli = vector<pli>;using vpll = vector<pll>;using vpil = vector<pil>; using vvi = vector<vector<int>>;using vvl = vector<vector<ll>>;using vvs = vector<vector<string>>;using vvb = vector<vector<bool>>; using vvpii = vector<vector<pii>>;using vvpli = vector<vector<pli>>;using vvpll = vector<vpll>;using vvpil = vector<vpil>; using mint = modint998244353; //using mint = modint1000000007; //using mint = dynamic_modint<0>; using vm = vector<mint>; using vvm = vector<vector<mint>>; vector<int> dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} #define yes {cout <<"Yes"<<endl;} #define no {cout <<"No"<<endl;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; #ifdef MY_LOCAL_DEBUG #define show(x) cerr<<#x<<" = "<<x<<endl #define showp(p) cerr<<#p<<" = "<<p.fi<<" : "<<p.se<<endl #define show2(x,y) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<endl #define show3(x,y,z) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<endl #define show4(x,y,z,x2) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<" : "<<#x2<<" = "<<x2<<endl #define test(x) cout << "test" << x << endl #define showv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define showv2(v) fore(vy , v) cout << vy << "\n"; #define showvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define showvm2(v) fore(vy , v) cout << vy.val() << "\n"; #else #define show(x) #define showp(p) #define show2(x,y) #define show3(x,y,z) #define show4(x,y,z,x2) #define test(x) #define showv(v) #define showv2(v) #define showvm(v) #define showvm2(v) #endif void solve(){ int n,k; cin>>n>>k; vector<vvi> e(k,vvi(n)); rep(i,k){ int t; cin>>t; rep(j,t){ int a,b; cin>>a>>b; a--; b--; e[i][a].pb(b); e[i][b].pb(a); } } // map<bitset<100>,mint> mp; auto f = [&](auto f,const vvm& v, bitset<50> row, bitset<50> col)->mint{ // bitset<100> b; // rep(i,n) b[i] = row[i]; // rep(i,n) b[i+n] = col[i]; // if (mp.count(b)) return mp[b]; vvm now; vi ridx,cidx; rep(i,n) if (row[i]==0) ridx.pb(i); rep(i,n) if (col[i]==0) cidx.pb(i); int k = sz(ridx); mint ret = 0; if (k == 2){ ret = v[ridx[0]][cidx[0]]*v[ridx[1]][cidx[1]] - v[ridx[0]][cidx[1]]*v[ridx[1]][cidx[0]]; return ret; }else if(k == 1){ return v[ridx[0]][cidx[0]]; } col[cidx[0]] = 1; rep(i,k){ mint tmp = v[ridx[i]][cidx[0]]; row[ridx[i]] = 1; tmp *= f(f,v,row,col); if ((i)%2==1) tmp *= -1; row[ridx[i]] = 0; ret += tmp; } col[cidx[0]] = 0; // mp[b] = ret; return ret; }; mint ans = 0; int l = 1 << k; rep1(i,l){ int p = pcnt(i); vvm v(n,vm(n)); vvi ee(n); rep(j,k) if ((i>>j&1) == 1){ rep(jj,n){ fore(y , e[j][jj]){ v[jj][jj]++; v[jj][y]--; } } } bitset<50> row,col; row[0] = 1; col[0] = 1; mint tmp = f(f,v,row,col); // rep(ii,n-1){ // rep(jj,n-1){ // int l = v2[ii][jj].val(); // if (l >= 10000) l = (l - 998244353 ); // cout << l << " "; // } // cout << endl; // } // show(tmp.val()); // cout << endl; if ((k-p)%2==1) tmp *= -1; ans += tmp; } outm; return; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int t = 1; //cin>>t; rep(i,t){ solve(); } return 0; }