結果

問題 No.2421 entersys?
コンテスト
ユーザー titia
提出日時 2023-08-21 03:20:34
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 7,372 bytes
コンパイル時間 1,438 ms
コンパイル使用メモリ 82,152 KB
実行使用メモリ 268,600 KB
最終ジャッジ日時 2024-12-14 11:33:13
合計ジャッジ時間 22,716 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 22 WA * 6
権限があれば一括ダウンロードができます

ソースコード

diff # 

import sys
input = sys.stdin.readline

from collections import defaultdict
from operator import itemgetter

# https://github.com/tatyam-prime/SortedSet/blob/main/SortedSet.py
import math
from bisect import bisect_left, bisect_right
from typing import Generic, Iterable, Iterator, List, Tuple, TypeVar, Optional
T = TypeVar('T')

class SortedSet(Generic[T]):
    BUCKET_RATIO = 50
    REBUILD_RATIO = 170

    def _build(self, a: Optional[List[T]] = None) -> None:
        "Evenly divide `a` into buckets."
        if a is None: a = list(self)
        size = len(a)
        bucket_size = int(math.ceil(math.sqrt(size / self.BUCKET_RATIO)))
        self.a = [a[size * i // bucket_size : size * (i + 1) // bucket_size] for i in range(bucket_size)]
    
    def __init__(self, a: Iterable[T] = []) -> None:
        "Make a new SortedSet from iterable. / O(N) if sorted and unique / O(N log N)"
        a = list(a)
        self.size = len(a)
        if not all(a[i] < a[i + 1] for i in range(len(a) - 1)):
            a = sorted(set(a))
        self._build(a)

    def __iter__(self) -> Iterator[T]:
        for i in self.a:
            for j in i: yield j

    def __reversed__(self) -> Iterator[T]:
        for i in reversed(self.a):
            for j in reversed(i): yield j
    
    def __eq__(self, other) -> bool:
        return list(self) == list(other)
    
    def __len__(self) -> int:
        return self.size
    
    def __repr__(self) -> str:
        return "SortedSet" + str(self.a)
    
    def __str__(self) -> str:
        s = str(list(self))
        return "{" + s[1 : len(s) - 1] + "}"

    def _position(self, x: T) -> Tuple[List[T], int]:
        "Find the bucket and position which x should be inserted. self must not be empty."
        for a in self.a:
            if x <= a[-1]: break
        return (a, bisect_left(a, x))

    def __contains__(self, x: T) -> bool:
        if self.size == 0: return False
        a, i = self._position(x)
        return i != len(a) and a[i] == x

    def add(self, x: T) -> bool:
        "Add an element and return True if added. / O(√N)"
        if self.size == 0:
            self.a = [[x]]
            self.size = 1
            return True
        a, i = self._position(x)
        if i != len(a) and a[i] == x: return False
        a.insert(i, x)
        self.size += 1
        if len(a) > len(self.a) * self.REBUILD_RATIO:
            self._build()
        return True
    
    def _pop(self, a: List[T], i: int) -> T:
        ans = a.pop(i)
        self.size -= 1
        if not a: self._build()
        return ans

    def discard(self, x: T) -> bool:
        "Remove an element and return True if removed. / O(√N)"
        if self.size == 0: return False
        a, i = self._position(x)
        if i == len(a) or a[i] != x: return False
        self._pop(a, i)
        return True
    
    def lt(self, x: T) -> Optional[T]:
        "Find the largest element < x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] < x:
                return a[bisect_left(a, x) - 1]

    def le(self, x: T) -> Optional[T]:
        "Find the largest element <= x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] <= x:
                return a[bisect_right(a, x) - 1]

    def gt(self, x: T) -> Optional[T]:
        "Find the smallest element > x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] > x:
                return a[bisect_right(a, x)]

    def ge(self, x: T) -> Optional[T]:
        "Find the smallest element >= x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] >= x:
                return a[bisect_left(a, x)]
    
    def __getitem__(self, i: int) -> T:
        "Return the i-th element."
        if i < 0:
            for a in reversed(self.a):
                i += len(a)
                if i >= 0: return a[i]
        else:
            for a in self.a:
                if i < len(a): return a[i]
                i -= len(a)
        raise IndexError
    
    def pop(self, i: int = -1) -> T:
        "Pop and return the i-th element."
        if i < 0:
            for a in reversed(self.a):
                i += len(a)
                if i >= 0: return self._pop(a, i)
        else:
            for a in self.a:
                if i < len(a): return self._pop(a, i)
                i -= len(a)
        raise IndexError
    
    def index(self, x: T) -> int:
        "Count the number of elements < x."
        ans = 0
        for a in self.a:
            if a[-1] >= x:
                return ans + bisect_left(a, x)
            ans += len(a)
        return ans

    def index_right(self, x: T) -> int:
        "Count the number of elements <= x."
        ans = 0
        for a in self.a:
            if a[-1] > x:
                return ans + bisect_right(a, x)
            ans += len(a)
        return ans

NAME=defaultdict(SortedSet)

N=int(input())
A=[input().split() for i in range(N)]
Q=int(input())
B=[input().split() for i in range(Q)]

LIST=[]

for i in range(N):
    A[i][1]=int(A[i][1])
    A[i][2]=int(A[i][2])

    LIST.append(A[i][1])
    LIST.append(A[i][2])

for i in range(Q):
    B[i][0]=int(B[i][0])

    if B[i][0]==1:
        B[i][2]=int(B[i][2])
        LIST.append(B[i][2])
        
    elif B[i][0]==2:
        B[i][1]=int(B[i][1])
        LIST.append(B[i][1])
        
    elif B[i][0]==3:
        B[i][2]=int(B[i][2])
        B[i][3]=int(B[i][3])
        LIST.append(B[i][2])
        LIST.append(B[i][3])

LIST.sort()
LIST2=[]

for l in LIST:
    if LIST2!=[] and LIST2[-1]==l:
        continue
    LIST2.append(l)

D={LIST2[i]:i+2 for i in range(len(LIST2))}

for i in range(N):
    A[i][1]=D[A[i][1]]
    A[i][2]=D[A[i][2]]

for i in range(Q):
    B[i][0]=int(B[i][0])

    if B[i][0]==1:
        B[i][2]=D[B[i][2]]
        
    elif B[i][0]==2:
        B[i][1]=D[B[i][1]]
        
    elif B[i][0]==3:
        B[i][2]=D[B[i][2]]
        B[i][3]=D[B[i][3]]


LEN=max(A) # 必要なら座標圧縮する

LEN=10**6
BIT=[0]*(LEN+1) # 1-indexedなtree. 配列BITの長さはLEN+1にしていることに注意。

def update(v,w): # index vにwを加える
    while v<=LEN:
        BIT[v]+=w
        v+=(v&(-v)) # v&(-v)で、最も下の立っているビット. 自分を含む大きなノードへ. たとえばv=3→v=4

def getvalue(v): # [1,v]の区間の和を求める
    ANS=0
    while v!=0:
        ANS+=BIT[v]
        v-=(v&(-v)) # 自分より小さい自分の和を構成するノードへ. たとえばv=14→v=12へ
    return ANS

for x,l,r in A:
    NAME[x].add((l,r))
    update(l,1)
    update(r+1,-1)

for i in range(Q):
    if B[i][0]==3:
        NAME[B[i][1]].add((B[i][2],B[i][3]))
        update(B[i][2],1)
        update(B[i][3]+1,-1)
        
ANS=[]

for i in range(Q-1,-1,-1):
    if B[i][0]==3:
        NAME[B[i][1]].discard((B[i][2],B[i][3]))
        update(B[i][2],-1)
        update(B[i][3],1)
    elif B[i][0]==2:
        ANS.append(getvalue(B[i][1]))
    else:
        x=B[i][1]
        y=B[i][2]

        ind=NAME[x].lt((y,10**9))
        if ind!=None:
            a,b=ind
            if a<=y<=b:
                ANS.append("Yes")
            else:
                ANS.append("No")
        else:
            ANS.append("No")

ANS.reverse()

print("\n".join(map(str,ANS)))
0