結果
問題 | No.2441 行列累乗 |
ユーザー |
![]() |
提出日時 | 2023-08-25 21:22:49 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 9,918 bytes |
コンパイル時間 | 2,340 ms |
コンパイル使用メモリ | 217,040 KB |
最終ジャッジ日時 | 2025-02-16 13:39:17 |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 20 |
ソースコード
#include<bits/stdc++.h>#define PPque priority_queue<tuple<ll, ll, ll>, vector<tuple<ll, ll, ll>>, greater<tuple<ll, ll, ll>>>#define Pque priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>#define pque priority_queue<int, vector<int>, greater<int>>#define umap unordered_map#define uset unordered_set#define rep(i, s, f) for(ll i = s; i <= f; i++)#define per(i, s, f) for(ll i = s; i >= f; i--)#define all0(x) (x).begin() ,(x).end()#define all(x) (x).begin() + 1, (x).end()#define vvvi vector<vector<vector<int>>>#define vvvl vector<vector<vector<ll>>>#define vvvc vector<vector<vector<char>>>#define vvvd vector<vector<vector<double>>>#define vvi vector<vector<int>>#define vvl vector<vector<ll>>#define vvs vector<vector<string>>#define vvc vector<vector<char>>#define vvp vector<vector<pair<ll, ll>>>#define vvb vector<vector<bool>>#define vvd vector<vector<double>>#define vp vector<pair<ll, ll>>#define vi vector<int>#define vl vector<ll>#define vs vector<string>#define vc vector<char>#define vb vector<bool>#define vd vector<double>#define P pair<ll, ll>#define TU tuple<ll, ll, ll>#define rrr(l, r) mt()%(r-l+1)+l#define ENDL '\n'#define ull unsigned long long#define debug(a, s) rep(i, s, a.size()-1) {cout << a.at(i) << " ";}cout << endl;#define Debug(a, s) rep(i, s, a.size()-1) {rep(j, s, a.at(i).size()-1) {cout << a.at(i).at(j) << " ";}cout << endl;}typedef long long ll;using namespace std;//////////////////////////////////////////////////////////////////////////////////////////////////////////////これが本当の組み込み関数ってね(笑)template <typename T>T or_less(vector<T> &A, T x) { //x以下で最大要素の添字 前提: sort済み 存在しない: -1return distance(A.begin(), upper_bound(A.begin(), A.end(), x)-1);}template <typename T>T under(vector<T> &A, T x) { //x未満の最大要素の添字 前提: sort済み 存在しない: -1return distance(A.begin(), lower_bound(A.begin(), A.end(), x)-1);}template <typename T>T or_more(vector<T> &A, T x) { //x以上で最小要素の添字 前提: sort済み 存在しない: N . //distanceのA.beginは添字を出すために常にA.begin() NG: A.begin() + 1return distance(A.begin(), lower_bound(A.begin(), A.end(), x));}template <typename T>T over(vector<T> &A, T x) { //xより大きい最小要素の添字前提: sort済み 存在しない: Nreturn distance(A.begin(), upper_bound(A.begin(), A.end(), x));}void compress(vector<ll> &A) {//小さい順に順位、大きい順にしたいならreverseはNG最後に変換vector<ll> temp = A;sort(temp.begin()+1, temp.end());for (int i = 1; i <= int(A.size()-1); i++) {A.at(i) = distance(temp.begin(), lower_bound(temp.begin()+1, temp.end(), A.at(i)));}}ll LIS1(vl &A) {//at(0)は番兵、広義単調増加ll N = A.size()-1;vl L(N+1, 1001001001001001001LL);L.at(0) = -1 * 1001001001001001001LL;ll ans = 0;rep(i, 1, N) {ll idx = over<ll>(L, A.at(i));L.at(idx) = A.at(i);ans = max(ans, idx);}return ans;}ll LIS2(vl &A) {//狭義単調増加ll N = A.size() - 1;vl L(N+1, 1001001001001001001LL);L.at(0) = -1 * 1001001001001001001LL;ll ans = 0;rep(i, 1, N) {ll idx = or_more<ll>(L, A.at(i));L.at(idx) = A.at(i);ans = max(ans, idx);}return ans;}////////////////////////////////////////////////////////////////////////数学系///////////////////////////////////////////////////////////////////////ll POWER(ll a, ll b, ll mod) {a %= mod;vector<ll> pow (61);pow.at(0) = a;bitset<60> bina(b);ll answer = 1;for (int i = 1; i <= 60; i++) {pow.at(i) = pow.at(i-1) * pow.at(i-1) % mod;if (bina.test(i-1)) {answer = (answer*pow.at(i-1)) % mod;}}return answer;}ll Div(ll a, ll b, ll mod) {return a * POWER(b, mod-2, mod) % mod;}ll round(ll x, ll i) {return ll(x + 5 * pow(10, i-1))/ll(pow(10, i)) * ll(pow(10, i));}template <typename T> //約分void normalize(T &mol, T &deno) {T mol_temp = abs(mol);T deno_temp = abs(deno);T GCD = gcd(mol_temp, deno_temp);mol /= GCD;deno /= GCD;}vvl mat_mul(vvl &a, vvl &b, ll mod) {//0-indexed && 正方行列ll n = a.size();vvl res(n , vl(n, 0));rep(i, 0, n-1) {rep(j, 0, n-1) {rep(k, 0, n-1) {res.at(i).at(j) += a.at(i).at(k) * b.at(k).at(j);res.at(i).at(j) %= mod;}}}return res;}vvl mat_pow(vvl &a, ll b, ll mod) {//0-indexed && 正方行列bitset<60> bina(b);vvl power = a;int N = a.size();vvl res(N, vl(N, 0));rep(i, 0, N-1) {res.at(i).at(i) = 1;}rep(i, 1, 60) {if (bina.test(i-1)) {res = mat_mul(res, power, mod);}power = mat_mul(power, power, mod);}return res;}vvl comb(ll n, ll mod) {//計算にO(N^2) 読み取りにO(1)vvl v(n+1, vl(n+1, 0));rep(i, 0, v.size() - 1) {v.at(i).at(0) = 1;v.at(i).at(i) = 1;}rep(i, 1, v.size()-1) {rep(j, 1, i) {v.at(i).at(j) = v.at(i-1).at(j-1) + v.at(i-1).at(j);v.at(i).at(j) %= mod;}}return v;}ll nCk(int n, int k, ll mod) {//毎回O(max(分子、 分母))ll ue = 1;ll sita = 1;for (int i = 1; i <= k; i++) {sita *= i;sita %= mod;}for (int i = 1; i <= k; i++) {ue *= (n-i+1);ue %= mod;}return Div(ue, sita, mod);}ll gaiseki(P a, P b) { //原点を中心としてaからbの方向 0以下なら角aObが180°以上return a.first * b.second - a.second * b.first;}ll gaiseki(P a, P b, P c) { //cを中心としてaからbの方向return (a.first - c.first) * (b.second - c.second) - (a.second - c.second) * (b.first - c.first);}ll nto10(string S, ll base) {ll res = 0;reverse(all0(S));while(!S.empty()) {ll num = S.back() - '0';if(num < 0 || num > 9) num = 9 + S.back() - 'a' + 1;res = res * base + num;S.pop_back();}return res;}string toN(ll N, ll base) {if(N == 0) return "0";string ans ="";ll MOD = abs(base);while(N != 0) {ll first = N % MOD;while(first < 0) first += MOD;ans += to_string(first);N -= first;N /= base;}reverse(all0(ans));return ans;}vp factrization(ll N) {vp res;for (int i = 2; i * i <= N; i++) {ll cnt = 0;while(N % i == 0) {cnt++;N /= i;}if(cnt != 0) res.push_back(P(i, cnt));}if(N != 1) res.push_back(P(N, 1));return res;}struct comb_fast {//must素数vl fac;vl facinv;vl inv;ll mod_comb;comb_fast (ll n, ll mod) {mod_comb = mod;fac.assign(n+1, 1);facinv.assign(n+1, 1);inv.assign(n+1, 1);rep(i, 2, n) {fac.at(i) = fac.at(i-1) * i % mod_comb;inv.at(i) = mod_comb - inv.at(mod_comb%i) * (mod_comb/i)%mod_comb;facinv.at(i) = facinv.at(i-1) * inv.at(i) % mod_comb;}}ll get(ll n, ll k) {if(n < k) return 0;if(n < 0 || k < 0) return 0;return fac.at(n) * (facinv.at(k) * facinv.at(n-k)%mod_comb)%mod_comb;}};double KAKUDO(double rad) {double res = rad * 180 / 3.141592653589793;return res;}double RAD(double kakudo) {return kakudo / 180 * 3.141592653589793;}double KAKUDO(P from, P to, P inside) {from.first -= inside.first; from.second -= inside.second;to.first -= inside.first; to.second -= inside.second;double kakudor = atan2(from.first, from.second);kakudor = KAKUDO(kakudor);double kakudol = atan2(to.first, to.second);kakudol = KAKUDO(kakudol);double res = kakudol - kakudor;if(res < 0)res += 360;if(res > 360) res -= 360;return res;}ll extgcd (ll a, ll b, ll &x, ll &y) {if(b == 0) {x = 1;y = 0;return a;}ll d = extgcd(b, a%b, y, x);y -= a/b * x;return d;}//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////グローバル変数を置くところ(情報工学意識高め)ll int_max = 1001001001;ll ll_max = 1001001001001001001LL;const double pi = 3.141592653589793;vl dx{0, 1, 0, -1, 0, 1, 1, -1, -1};vl dy{0, 0, -1, 0, 1, 1, -1, -1, 1};//#pragma GCC optimize ("-O3")//ll mod = 1000000007;//ll mod = 998244353;//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////template<typename T>struct Matrix {int h, w;vector<vector<T>> d;Matrix() {}Matrix(int h, int w, T val = 0): h(h), w(w), d(h, vector<T>(w, val)){}Matrix& unit() {assert(h == w);rep(i, 0, h-1) {d[i][i] = 1;}return *this;}const vector<T>& operator[](int i) const{return d[i];}vector<T>& operator[](int i) {return d[i];}Matrix operator*(const Matrix&a) const{assert(w == a.h);Matrix r(h, a.w);rep(i, 0, h-1) {rep(k, 0, w-1) {rep(j, 0, a.w-1) {r[i][j] += d[i][k] * a[k][j];}}}return r;}Matrix pow(ll t) const {assert(h == w);if(!t) return Matrix(h, h).unit();if(t == 1) return *this;Matrix r = pow(t >> 1);r = r * r;if(t&1) r = r*(*this);return r;}};void solve() {Matrix<ll> A(2, 2);cin >> A[0][0];cin >> A[0][1];cin >> A[1][0];cin >> A[1][1];Matrix<ll> ans = A.pow(3);rep(i, 0, 1) {rep(j, 0, 1) {cout << ans[i][j] << " ";}cout << endl;}}//stringでの数字の下から1桁目は 正:S.at(N-1) 誤:S.at(0)//if(S.at(i) == 1 ← charなのに1...?// modは取りましたか...?(´・ω・`)int main() {ios::sync_with_stdio(false);std::cin.tie(nullptr);cout << fixed << setprecision(15);solve();return 0;}