#907675 (C++17) No.2443 特殊線形群の標準表現

• 問題: No.2443 特殊線形群の標準表現
• ユーザー: tokusakurai
• 提出日時: 2023-08-25 21:38:48
• 言語: C++17 (gcc 15.2.0 + boost 1.89.0)
• 結果: WA
• 実行時間: -
• コード長: 14,764 bytes
• コンパイル時間: 2,427 ms
• コンパイル使用メモリ: 210,236 KB
• 最終ジャッジ日時: 2025-02-16 13:50:24
• ジャッジサーバーID （参考情報）: judge2 / judge5

ファイルパターン	結果
other	AC * 6 WA * 15

ソースコード

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (n); i++)
#define per(i, n) for (int i = (n)-1; i >= 0; i--)
#define rep2(i, l, r) for (int i = (l); i < (r); i++)
#define per2(i, l, r) for (int i = (r)-1; i >= (l); i--)
#define each(e, v) for (auto &e : v)
#define MM << " " <<
#define pb push_back
#define eb emplace_back
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
#define sz(x) (int)x.size()
using ll = long long;
using pii = pair<int, int>;
using pil = pair<int, ll>;
using pli = pair<ll, int>;
using pll = pair<ll, ll>;

template <typename T>
using minheap = priority_queue<T, vector<T>, greater<T>>;

template <typename T>
using maxheap = priority_queue<T>;

template <typename T>
bool chmax(T &x, const T &y) {
    return (x < y) ? (x = y, true) : false;
}

template <typename T>
bool chmin(T &x, const T &y) {
    return (x > y) ? (x = y, true) : false;
}

template <typename T>
int flg(T x, int i) {
    return (x >> i) & 1;
}

int pct(int x) { return __builtin_popcount(x); }
int pct(ll x) { return __builtin_popcountll(x); }
int topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }
int topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }
int botbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); }
int botbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }

template <typename T>
void print(const vector<T> &v, T x = 0) {
    int n = v.size();
    for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' ');
    if (v.empty()) cout << '\n';
}

template <typename T>
void printn(const vector<T> &v, T x = 0) {
    int n = v.size();
    for (int i = 0; i < n; i++) cout << v[i] + x << '\n';
}

template <typename T>
int lb(const vector<T> &v, T x) {
    return lower_bound(begin(v), end(v), x) - begin(v);
}

template <typename T>
int ub(const vector<T> &v, T x) {
    return upper_bound(begin(v), end(v), x) - begin(v);
}

template <typename T>
void rearrange(vector<T> &v) {
    sort(begin(v), end(v));
    v.erase(unique(begin(v), end(v)), end(v));
}

template <typename T>
vector<int> id_sort(const vector<T> &v, bool greater = false) {
    int n = v.size();
    vector<int> ret(n);
    iota(begin(ret), end(ret), 0);
    sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; });
    return ret;
}

template <typename T>
void reorder(vector<T> &a, const vector<int> &ord) {
    int n = a.size();
    vector<T> b(n);
    for (int i = 0; i < n; i++) b[i] = a[ord[i]];
    swap(a, b);
}

template <typename T>
T floor(T x, T y) {
    assert(y != 0);
    if (y < 0) x = -x, y = -y;
    return (x >= 0 ? x / y : (x - y + 1) / y);
}

template <typename T>
T ceil(T x, T y) {
    assert(y != 0);
    if (y < 0) x = -x, y = -y;
    return (x >= 0 ? (x + y - 1) / y : x / y);
}

template <typename S, typename T>
pair<S, T> operator+(const pair<S, T> &p, const pair<S, T> &q) {
    return make_pair(p.first + q.first, p.second + q.second);
}

template <typename S, typename T>
pair<S, T> operator-(const pair<S, T> &p, const pair<S, T> &q) {
    return make_pair(p.first - q.first, p.second - q.second);
}

template <typename S, typename T>
istream &operator>>(istream &is, pair<S, T> &p) {
    S a;
    T b;
    is >> a >> b;
    p = make_pair(a, b);
    return is;
}

template <typename S, typename T>
ostream &operator<<(ostream &os, const pair<S, T> &p) {
    return os << p.first << ' ' << p.second;
}

struct io_setup {
    io_setup() {
        ios_base::sync_with_stdio(false);
        cin.tie(NULL);
        cout << fixed << setprecision(15);
        cerr << fixed << setprecision(15);
    }
} io_setup;

constexpr int inf = (1 << 30) - 1;
constexpr ll INF = (1LL << 60) - 1;
// constexpr int MOD = 1000000007;
constexpr int MOD = 998244353;

template <typename Monoid>
struct Segment_Tree {
    using M = typename Monoid::V;
    int n, m;
    vector<M> seg;

    // f(f(a,b),c) = f(a,f(b,c)), f(e1,a) = f(a,e1) = a

    Segment_Tree(const vector<M> &v) : n(v.size()) {
        m = 1;
        while (m < n) m <<= 1;
        seg.assign(2 * m, Monoid::id);
        copy(begin(v), end(v), begin(seg) + m);
        build();
    }

    Segment_Tree(int n, M x = Monoid::id) : Segment_Tree(vector<M>(n, x)) {}

    void set(int i, const M &x) { seg[m + i] = x; }

    void build() {
        for (int i = m - 1; i > 0; i--) seg[i] = Monoid::merge(seg[2 * i], seg[2 * i + 1]);
    }

    void update(int i, const M &x, bool apply = false) {
        seg[i + m] = apply ? Monoid::merge(seg[i + m], x) : x;
        i += m;
        while (i >>= 1) seg[i] = Monoid::merge(seg[2 * i], seg[2 * i + 1]);
    }

    M query(int l, int r) const {
        l = max(l, 0), r = min(r, n);
        M L = Monoid::id, R = Monoid::id;
        l += m, r += m;
        while (l < r) {
            if (l & 1) L = Monoid::merge(L, seg[l++]);
            if (r & 1) R = Monoid::merge(seg[--r], R);
            l >>= 1, r >>= 1;
        }
        return Monoid::merge(L, R);
    }

    M operator[](int i) const { return seg[m + i]; }

    template <typename C>
    int find_subtree(int i, const C &check, M &x, int type) const {
        while (i < m) {
            M nxt = type ? Monoid::merge(seg[2 * i + type], x) : Monoid::merge(x, seg[2 * i + type]);
            if (check(nxt)) {
                i = 2 * i + type;
            } else {
                x = nxt;
                i = 2 * i + (type ^ 1);
            }
        }
        return i - m;
    }

    // check(区間 [l,r] での演算結果) を満たす最小の r (存在しなければ n)
    template <typename C>
    int find_first(int l, const C &check) const {
        M L = Monoid::id;
        int a = l + m, b = 2 * m;
        while (a < b) {
            if (a & 1) {
                M nxt = Monoid::merge(L, seg[a]);
                if (check(nxt)) return find_subtree(a, check, L, 0);
                L = nxt;
                a++;
            }
            a >>= 1, b >>= 1;
        }
        return n;
    }

    // check((区間 [l,r) での演算結果)) を満たす最大の l (存在しなければ -1)
    template <typename C>
    int find_last(int r, const C &check) const {
        M R = Monoid::id;
        int a = m, b = r + m;
        while (a < b) {
            if ((b & 1) || a == 1) {
                M nxt = Monoid::merge(seg[--b], R);
                if (check(nxt)) return find_subtree(b, check, R, 1);
                R = nxt;
            }
            a >>= 1, b >>= 1;
        }
        return -1;
    }
};

struct Runtime_Mod_Int {
    int x;

    Runtime_Mod_Int() : x(0) {}

    Runtime_Mod_Int(long long y) {
        x = y % get_mod();
        if (x < 0) x += get_mod();
    }

    static inline int &get_mod() {
        static int mod = 0;
        return mod;
    }

    static void set_mod(int md) { get_mod() = md; }

    Runtime_Mod_Int &operator+=(const Runtime_Mod_Int &p) {
        if ((x += p.x) >= get_mod()) x -= get_mod();
        return *this;
    }

    Runtime_Mod_Int &operator-=(const Runtime_Mod_Int &p) {
        if ((x += get_mod() - p.x) >= get_mod()) x -= get_mod();
        return *this;
    }

    Runtime_Mod_Int &operator*=(const Runtime_Mod_Int &p) {
        x = (int)(1LL * x * p.x % get_mod());
        return *this;
    }

    Runtime_Mod_Int &operator/=(const Runtime_Mod_Int &p) {
        *this *= p.inverse();
        return *this;
    }

    Runtime_Mod_Int &operator++() { return *this += Runtime_Mod_Int(1); }

    Runtime_Mod_Int operator++(int) {
        Runtime_Mod_Int tmp = *this;
        ++*this;
        return tmp;
    }

    Runtime_Mod_Int &operator--() { return *this -= Runtime_Mod_Int(1); }

    Runtime_Mod_Int operator--(int) {
        Runtime_Mod_Int tmp = *this;
        --*this;
        return tmp;
    }

    Runtime_Mod_Int operator-() const { return Runtime_Mod_Int(-x); }

    Runtime_Mod_Int operator+(const Runtime_Mod_Int &p) const { return Runtime_Mod_Int(*this) += p; }

    Runtime_Mod_Int operator-(const Runtime_Mod_Int &p) const { return Runtime_Mod_Int(*this) -= p; }

    Runtime_Mod_Int operator*(const Runtime_Mod_Int &p) const { return Runtime_Mod_Int(*this) *= p; }

    Runtime_Mod_Int operator/(const Runtime_Mod_Int &p) const { return Runtime_Mod_Int(*this) /= p; }

    bool operator==(const Runtime_Mod_Int &p) const { return x == p.x; }

    bool operator!=(const Runtime_Mod_Int &p) const { return x != p.x; }

    Runtime_Mod_Int inverse() const {
        assert(*this != Runtime_Mod_Int(0));
        return pow(get_mod() - 2);
    }

    Runtime_Mod_Int pow(long long k) const {
        Runtime_Mod_Int now = *this, ret = 1;
        for (; k > 0; k >>= 1, now *= now) {
            if (k & 1) ret *= now;
        }
        return ret;
    }

    friend ostream &operator<<(ostream &os, const Runtime_Mod_Int &p) { return os << p.x; }

    friend istream &operator>>(istream &is, Runtime_Mod_Int &p) {
        long long a;
        is >> a;
        p = Runtime_Mod_Int(a);
        return is;
    }
};

using mint = Runtime_Mod_Int;

template <typename T>
struct Matrix {
    vector<vector<T>> A;
    int n, m;

    Matrix(int n, int m) : A(n, vector<T>(m, 0)), n(n), m(m) {}

    inline const vector<T> &operator[](int k) const { return A[k]; }

    inline vector<T> &operator[](int k) { return A[k]; }

    static Matrix I(int l) {
        Matrix ret(l, l);
        for (int i = 0; i < l; i++) ret[i][i] = 1;
        return ret;
    }

    Matrix &operator*=(const Matrix &B) {
        assert(m == B.n);
        Matrix ret(n, B.m);
        for (int i = 0; i < n; i++) {
            for (int k = 0; k < m; k++) {
                for (int j = 0; j < B.m; j++) ret[i][j] += A[i][k] * B[k][j];
            }
        }
        swap(A, ret.A);
        m = B.m;
        return *this;
    }

    Matrix operator*(const Matrix &B) const { return Matrix(*this) *= B; }

    Matrix pow(long long k) const {
        assert(n == m);
        Matrix now = *this, ret = I(n);
        for (; k > 0; k >>= 1, now *= now) {
            if (k & 1) ret *= now;
        }
        return ret;
    }

    bool eq(const T &a, const T &b) const {
        return a == b;
        // return abs(a-b) <= EPS;
    }

    // 行基本変形を用いて簡約化を行い、(rank, det) の組を返す
    pair<int, T> row_reduction(vector<T> &b) {
        assert((int)b.size() == n);
        if (n == 0) return make_pair(0, m > 0 ? 0 : 1);
        int check = 0, rank = 0;
        T det = (n == m ? 1 : 0);
        for (int j = 0; j < m; j++) {
            int pivot = check;
            for (int i = check; i < n; i++) {
                if (A[i][j] != 0) pivot = i;
                // if(abs(A[i][j]) > abs(A[pivot][j])) pivot = i; // T が小数の場合はこちら
            }
            if (check != pivot) det *= T(-1);
            swap(A[check], A[pivot]), swap(b[check], b[pivot]);
            if (eq(A[check][j], T(0))) {
                det = T(0);
                continue;
            }
            rank++;
            det *= A[check][j];
            T r = T(1) / A[check][j];
            for (int k = j + 1; k < m; k++) A[check][k] *= r;
            b[check] *= r;
            A[check][j] = T(1);
            for (int i = 0; i < n; i++) {
                if (i == check) continue;
                if (!eq(A[i][j], 0)) {
                    for (int k = j + 1; k < m; k++) A[i][k] -= A[i][j] * A[check][k];
                    b[i] -= A[i][j] * b[check];
                }
                A[i][j] = T(0);
            }
            if (++check == n) break;
        }
        return make_pair(rank, det);
    }

    pair<int, T> row_reduction() {
        vector<T> b(n, T(0));
        return row_reduction(b);
    }

    // 行基本変形を行い、逆行列を求める
    pair<bool, Matrix> inverse() {
        if (n != m) return make_pair(false, Matrix(0, 0));
        if (n == 0) return make_pair(true, Matrix(0, 0));
        Matrix ret = I(n);
        for (int j = 0; j < n; j++) {
            int pivot = j;
            for (int i = j; i < n; i++) {
                if (A[i][j] != 0) pivot = i;
                // if(abs(A[i][j]) > abs(A[pivot][j])) pivot = i; // T が小数の場合はこちら
            }
            swap(A[j], A[pivot]), swap(ret[j], ret[pivot]);
            if (eq(A[j][j], T(0))) return make_pair(false, Matrix(0, 0));
            T r = T(1) / A[j][j];
            for (int k = j + 1; k < n; k++) A[j][k] *= r;
            for (int k = 0; k < n; k++) ret[j][k] *= r;
            A[j][j] = T(1);
            for (int i = 0; i < n; i++) {
                if (i == j) continue;
                if (!eq(A[i][j], T(0))) {
                    for (int k = j + 1; k < n; k++) A[i][k] -= A[i][j] * A[j][k];
                    for (int k = 0; k < n; k++) ret[i][k] -= A[i][j] * ret[j][k];
                }
                A[i][j] = T(0);
            }
        }
        return make_pair(true, ret);
    }

    // Ax = b の解の 1 つと解空間の基底の組を返す
    vector<vector<T>> Gaussian_elimination(vector<T> b) {
        row_reduction(b);
        vector<vector<T>> ret;
        vector<int> p(n, m);
        vector<bool> is_zero(m, true);
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                if (!eq(A[i][j], T(0))) {
                    p[i] = j;
                    break;
                }
            }
            if (p[i] < m) {
                is_zero[p[i]] = false;
            } else if (!eq(b[i], T(0))) {
                return {};
            }
        }
        vector<T> x(m, T(0));
        for (int i = 0; i < n; i++) {
            if (p[i] < m) x[p[i]] = b[i];
        }
        ret.push_back(x);
        for (int j = 0; j < m; j++) {
            if (!is_zero[j]) continue;
            x[j] = T(1);
            for (int i = 0; i < n; i++) {
                if (p[i] < m) x[p[i]] = -A[i][j];
            }
            ret.push_back(x);
            x[j] = T(0);
        }
        return ret;
    }
};

void solve() {
    int N, M, T;
    cin >> N >> M >> T;

    mint::set_mod(M);

    using mat = Matrix<mint>;

    vector<mat> A(N, mat(2, 2));

    rep(i, N) {
        rep(j, 2) rep(k, 2) cin >> A[i][j][k]; //
    }

    vector<mat> P(N + 1, mat::I(2));
    rep(i, N) P[i + 1] = P[i] * A[i];

    vector<mat> Q(N + 1, mat::I(2));
    rep(i, N) Q[i + 1] = A[i] * Q[i];

    while (T--) {
        int l, r;
        mint x, y;
        cin >> l >> r >> x >> y;
        if (M == 1) {
            cout << "0 0\n";
        } else {
            mat X(2, 1);
            X[0][0] = x, X[1][0] = y;
            X = Q[r] * Q[l].inverse().second * X;
            cout << X[0][0] MM X[1][0] << '\n';
        }
    }
}

int main() {
    int T = 1;
    // cin >> T;
    while (T--) solve();
}