結果
問題 | No.2444 一次変換と体積 |
ユーザー | tokusakurai |
提出日時 | 2023-08-25 22:21:53 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 11,821 bytes |
コンパイル時間 | 2,658 ms |
コンパイル使用メモリ | 216,748 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-06-06 16:57:08 |
合計ジャッジ時間 | 3,473 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 1 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | WA | - |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 2 ms
5,376 KB |
testcase_07 | AC | 1 ms
5,376 KB |
testcase_08 | WA | - |
testcase_09 | AC | 1 ms
5,376 KB |
testcase_10 | AC | 2 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | AC | 1 ms
5,376 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #define rep(i, n) for (int i = 0; i < (n); i++) #define per(i, n) for (int i = (n)-1; i >= 0; i--) #define rep2(i, l, r) for (int i = (l); i < (r); i++) #define per2(i, l, r) for (int i = (r)-1; i >= (l); i--) #define each(e, v) for (auto &e : v) #define MM << " " << #define pb push_back #define eb emplace_back #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define sz(x) (int)x.size() using ll = long long; using pii = pair<int, int>; using pil = pair<int, ll>; using pli = pair<ll, int>; using pll = pair<ll, ll>; template <typename T> using minheap = priority_queue<T, vector<T>, greater<T>>; template <typename T> using maxheap = priority_queue<T>; template <typename T> bool chmax(T &x, const T &y) { return (x < y) ? (x = y, true) : false; } template <typename T> bool chmin(T &x, const T &y) { return (x > y) ? (x = y, true) : false; } template <typename T> int flg(T x, int i) { return (x >> i) & 1; } int pct(int x) { return __builtin_popcount(x); } int pct(ll x) { return __builtin_popcountll(x); } int topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); } int topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); } int botbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); } int botbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); } template <typename T> void print(const vector<T> &v, T x = 0) { int n = v.size(); for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' '); if (v.empty()) cout << '\n'; } template <typename T> void printn(const vector<T> &v, T x = 0) { int n = v.size(); for (int i = 0; i < n; i++) cout << v[i] + x << '\n'; } template <typename T> int lb(const vector<T> &v, T x) { return lower_bound(begin(v), end(v), x) - begin(v); } template <typename T> int ub(const vector<T> &v, T x) { return upper_bound(begin(v), end(v), x) - begin(v); } template <typename T> void rearrange(vector<T> &v) { sort(begin(v), end(v)); v.erase(unique(begin(v), end(v)), end(v)); } template <typename T> vector<int> id_sort(const vector<T> &v, bool greater = false) { int n = v.size(); vector<int> ret(n); iota(begin(ret), end(ret), 0); sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; }); return ret; } template <typename T> void reorder(vector<T> &a, const vector<int> &ord) { int n = a.size(); vector<T> b(n); for (int i = 0; i < n; i++) b[i] = a[ord[i]]; swap(a, b); } template <typename T> T floor(T x, T y) { assert(y != 0); if (y < 0) x = -x, y = -y; return (x >= 0 ? x / y : (x - y + 1) / y); } template <typename T> T ceil(T x, T y) { assert(y != 0); if (y < 0) x = -x, y = -y; return (x >= 0 ? (x + y - 1) / y : x / y); } template <typename S, typename T> pair<S, T> operator+(const pair<S, T> &p, const pair<S, T> &q) { return make_pair(p.first + q.first, p.second + q.second); } template <typename S, typename T> pair<S, T> operator-(const pair<S, T> &p, const pair<S, T> &q) { return make_pair(p.first - q.first, p.second - q.second); } template <typename S, typename T> istream &operator>>(istream &is, pair<S, T> &p) { S a; T b; is >> a >> b; p = make_pair(a, b); return is; } template <typename S, typename T> ostream &operator<<(ostream &os, const pair<S, T> &p) { return os << p.first << ' ' << p.second; } struct io_setup { io_setup() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout << fixed << setprecision(15); cerr << fixed << setprecision(15); } } io_setup; constexpr int inf = (1 << 30) - 1; constexpr ll INF = (1LL << 60) - 1; // constexpr int MOD = 1000000007; constexpr int MOD = 998244353; struct Runtime_Mod_Int { int x; Runtime_Mod_Int() : x(0) {} Runtime_Mod_Int(long long y) { x = y % get_mod(); if (x < 0) x += get_mod(); } static inline int &get_mod() { static int mod = 0; return mod; } static void set_mod(int md) { get_mod() = md; } Runtime_Mod_Int &operator+=(const Runtime_Mod_Int &p) { if ((x += p.x) >= get_mod()) x -= get_mod(); return *this; } Runtime_Mod_Int &operator-=(const Runtime_Mod_Int &p) { if ((x += get_mod() - p.x) >= get_mod()) x -= get_mod(); return *this; } Runtime_Mod_Int &operator*=(const Runtime_Mod_Int &p) { x = (int)(1LL * x * p.x % get_mod()); return *this; } Runtime_Mod_Int &operator/=(const Runtime_Mod_Int &p) { *this *= p.inverse(); return *this; } Runtime_Mod_Int &operator++() { return *this += Runtime_Mod_Int(1); } Runtime_Mod_Int operator++(int) { Runtime_Mod_Int tmp = *this; ++*this; return tmp; } Runtime_Mod_Int &operator--() { return *this -= Runtime_Mod_Int(1); } Runtime_Mod_Int operator--(int) { Runtime_Mod_Int tmp = *this; --*this; return tmp; } Runtime_Mod_Int operator-() const { return Runtime_Mod_Int(-x); } Runtime_Mod_Int operator+(const Runtime_Mod_Int &p) const { return Runtime_Mod_Int(*this) += p; } Runtime_Mod_Int operator-(const Runtime_Mod_Int &p) const { return Runtime_Mod_Int(*this) -= p; } Runtime_Mod_Int operator*(const Runtime_Mod_Int &p) const { return Runtime_Mod_Int(*this) *= p; } Runtime_Mod_Int operator/(const Runtime_Mod_Int &p) const { return Runtime_Mod_Int(*this) /= p; } bool operator==(const Runtime_Mod_Int &p) const { return x == p.x; } bool operator!=(const Runtime_Mod_Int &p) const { return x != p.x; } Runtime_Mod_Int inverse() const { assert(*this != Runtime_Mod_Int(0)); return pow(get_mod() - 2); } Runtime_Mod_Int pow(long long k) const { Runtime_Mod_Int now = *this, ret = 1; for (; k > 0; k >>= 1, now *= now) { if (k & 1) ret *= now; } return ret; } friend ostream &operator<<(ostream &os, const Runtime_Mod_Int &p) { return os << p.x; } friend istream &operator>>(istream &is, Runtime_Mod_Int &p) { long long a; is >> a; p = Runtime_Mod_Int(a); return is; } }; using mint = Runtime_Mod_Int; template <typename T> struct Matrix { vector<vector<T>> A; int n, m; Matrix(int n, int m) : A(n, vector<T>(m, 0)), n(n), m(m) {} inline const vector<T> &operator[](int k) const { return A[k]; } inline vector<T> &operator[](int k) { return A[k]; } static Matrix I(int l) { Matrix ret(l, l); for (int i = 0; i < l; i++) ret[i][i] = 1; return ret; } Matrix &operator*=(const Matrix &B) { assert(m == B.n); Matrix ret(n, B.m); for (int i = 0; i < n; i++) { for (int k = 0; k < m; k++) { for (int j = 0; j < B.m; j++) ret[i][j] += A[i][k] * B[k][j]; } } swap(A, ret.A); m = B.m; return *this; } Matrix operator*(const Matrix &B) const { return Matrix(*this) *= B; } Matrix pow(long long k) const { assert(n == m); Matrix now = *this, ret = I(n); for (; k > 0; k >>= 1, now *= now) { if (k & 1) ret *= now; } return ret; } bool eq(const T &a, const T &b) const { return a == b; // return abs(a-b) <= EPS; } // 行基本変形を用いて簡約化を行い、(rank, det) の組を返す pair<int, T> row_reduction(vector<T> &b) { assert((int)b.size() == n); if (n == 0) return make_pair(0, m > 0 ? 0 : 1); int check = 0, rank = 0; T det = (n == m ? 1 : 0); for (int j = 0; j < m; j++) { int pivot = check; for (int i = check; i < n; i++) { if (A[i][j] != 0) pivot = i; // if(abs(A[i][j]) > abs(A[pivot][j])) pivot = i; // T が小数の場合はこちら } if (check != pivot) det *= T(-1); swap(A[check], A[pivot]), swap(b[check], b[pivot]); if (eq(A[check][j], T(0))) { det = T(0); continue; } rank++; det *= A[check][j]; T r = T(1) / A[check][j]; for (int k = j + 1; k < m; k++) A[check][k] *= r; b[check] *= r; A[check][j] = T(1); for (int i = 0; i < n; i++) { if (i == check) continue; if (!eq(A[i][j], 0)) { for (int k = j + 1; k < m; k++) A[i][k] -= A[i][j] * A[check][k]; b[i] -= A[i][j] * b[check]; } A[i][j] = T(0); } if (++check == n) break; } return make_pair(rank, det); } pair<int, T> row_reduction() { vector<T> b(n, T(0)); return row_reduction(b); } // 行基本変形を行い、逆行列を求める pair<bool, Matrix> inverse() { if (n != m) return make_pair(false, Matrix(0, 0)); if (n == 0) return make_pair(true, Matrix(0, 0)); Matrix ret = I(n); for (int j = 0; j < n; j++) { int pivot = j; for (int i = j; i < n; i++) { if (A[i][j] != 0) pivot = i; // if(abs(A[i][j]) > abs(A[pivot][j])) pivot = i; // T が小数の場合はこちら } swap(A[j], A[pivot]), swap(ret[j], ret[pivot]); if (eq(A[j][j], T(0))) return make_pair(false, Matrix(0, 0)); T r = T(1) / A[j][j]; for (int k = j + 1; k < n; k++) A[j][k] *= r; for (int k = 0; k < n; k++) ret[j][k] *= r; A[j][j] = T(1); for (int i = 0; i < n; i++) { if (i == j) continue; if (!eq(A[i][j], T(0))) { for (int k = j + 1; k < n; k++) A[i][k] -= A[i][j] * A[j][k]; for (int k = 0; k < n; k++) ret[i][k] -= A[i][j] * ret[j][k]; } A[i][j] = T(0); } } return make_pair(true, ret); } // Ax = b の解の 1 つと解空間の基底の組を返す vector<vector<T>> Gaussian_elimination(vector<T> b) { row_reduction(b); vector<vector<T>> ret; vector<int> p(n, m); vector<bool> is_zero(m, true); for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { if (!eq(A[i][j], T(0))) { p[i] = j; break; } } if (p[i] < m) { is_zero[p[i]] = false; } else if (!eq(b[i], T(0))) { return {}; } } vector<T> x(m, T(0)); for (int i = 0; i < n; i++) { if (p[i] < m) x[p[i]] = b[i]; } ret.push_back(x); for (int j = 0; j < m; j++) { if (!is_zero[j]) continue; x[j] = T(1); for (int i = 0; i < n; i++) { if (p[i] < m) x[p[i]] = -A[i][j]; } ret.push_back(x); x[j] = T(0); } return ret; } }; void solve() { int N, M; cin >> N >> M; vector<vector<ll>> a(3, vector<ll>(3)); rep(i, 3) rep(j, 3) cin >> a[i][j]; Matrix<ll> A(3, 3); rep(i, 3) rep(j, 3) A[i][j] = a[i][j]; ll V = A.row_reduction().second; if (V == 0) { cout << "0\n"; return; } mint::set_mod(M); Matrix<mint> B(3, 3); rep(i, 3) rep(j, 3) B[i][j] = a[i][j]; mint U = B.row_reduction().second; if (V < 0) U = -U; cout << U.pow(N) << '\n'; } int main() { int T = 1; // cin >> T; while (T--) solve(); }