結果

問題 No.2453 Seat Allocation
ユーザー TKTYITKTYI
提出日時 2023-09-01 22:55:29
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
TLE  
実行時間 -
コード長 3,934 bytes
コンパイル時間 10,774 ms
コンパイル使用メモリ 405,768 KB
実行使用メモリ 17,076 KB
最終ジャッジ日時 2025-01-03 10:51:04
合計ジャッジ時間 31,587 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 19 TLE * 3
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
using namespace std;
using namespace atcoder;
typedef long long int ll;
typedef long double ld;
typedef vector<ll> vi;
typedef vector<vi> vvi;
typedef vector<vvi> vvvi;
typedef vector<vvvi> vvvvi;
typedef vector<bool> vb;
typedef vector<vb> vvb;
typedef vector<vvb> vvvb;
typedef vector<vvvb> vvvvb;
typedef pair<ll,ll> pi;
typedef pair<ll,pi> ppi;
typedef pair<ll,ppi> pppi;
typedef pair<ll,pppi> ppppi;
#define FOR(i,l,r) for(ll i=l;i<r;i++)
#define REP(i,n) FOR(i,0,n)
#define RFOR(i,l,r) for(ll i=r-1;i>=l;i--)
#define RREP(i,n) RFOR(i,0,n)
#define ALL(x) x.begin(),x.end()
#define F first
#define S second
#define BS(A,x) binary_search(ALL(A),x)
#define LB(A,x) (ll)(lower_bound(ALL(A),x)-A.begin())
#define UB(A,x) (ll)(upper_bound(ALL(A),x)-A.begin())
#define COU(A,x) (UB(A,x)-LB(A,x))
#define sz(c) ((ll)(c).size())
//*
#include<boost/multiprecision/cpp_int.hpp>
namespace mp=boost::multiprecision;
using Bint=mp::cpp_int;
//*/
template<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;
template<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.F<<" "<<p.S;return os;}
template<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.F>>p.S;return is;}
template<typename T>ostream&operator<<(ostream&os,vector<T>&v){REP(i,sz(v))os<<v[i]<<(i+1!=sz(v)?" ":"");return os;}
template<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}
template<class T>bool chmax(T&a,T b){if(a<b){a=b;return 1;}return 0;}
template<class T>bool chmin(T&a,T b){if(b<a){a=b;return 1;}return 0;}
ld dist(ld x1,ld y1,ld x2,ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));}
vi fast_mod_convolution(vi&a,vi&b,ll mod){
const ll m1=167772161,m2=469762049,m3=1224736769;
const ll m1_inv_m2=inv_mod(m1,m2);
const ll m12_inv_m3=inv_mod(m1*m2,m3);
const ll m12_mod=m1*m2%mod;
auto x=convolution<m1>(a,b);
auto y=convolution<m2>(a,b);
auto z=convolution<m3>(a,b);
vector<ll>ret(sz(a)+sz(b)-1);
REP(i,sz(ret)){
ll v1=(y[i]-x[i])*m1_inv_m2%m2;if(v1<0)v1+=m2;
ll v2=(z[i]-(x[i]+m1*v1)%m3)*m12_inv_m3%m3;if(v2<0)v2+=m3;
ret[i]=(x[i]+m1*v1+m12_mod*v2)%mod;
}
return ret;
}
const ld EPS=1e-8;
//*
using mint=modint998244353;
const ll mod=998244353;
//*/
/*
using mint=modint1000000007;
const ll mod=1000000007;
//*/
//using mint=modint;
//*
typedef vector<mint> vm;
typedef vector<vm> vvm;
typedef vector<vvm> vvvm;
typedef vector<vvvm> vvvvm;
ostream&operator<<(ostream&os,mint&a){os<<a.val();return os;}
//*/
struct rational{
Bint x,y;
rational(ll a=0,ll b=1):x(a),y(b){}
rational(Bint a=0,Bint b=1):x(a),y(b){}
rational f(){
Bint g=gcd(x,y);
if((g<0)^(y<0))g*=-1;
return rational{x/g,y/g};
}
ld val(){
return (ld)x/(ld)y;
}
bool operator==(rational r){
return r.x*y==r.y*x;
}
bool operator!=(rational r){
return r.x*y!=r.y*x;
}
bool operator<(rational r){
return f().x*r.f().y<f().y*r.f().x;
}
bool operator>(rational r){
return f().x*r.f().y>f().y*r.f().x;
}
rational operator+(rational r){
rational ans={r.y*x+r.x*y,r.y*y};
return ans.f();
}
rational operator-(rational r){
rational ans={r.y*x-r.x*y,r.y*y};
return ans.f();
}
rational operator*(rational r){
rational ans={x*r.x,y*r.y};
return ans.f();
}
rational operator/(rational r){
rational ans={x*r.y,y*r.x};
return ans.f();
}
};
int main(){
ll N,M;cin>>N>>M;
vi A(N),B(M);cin>>A>>B;
auto compare=[](pair<rational,ll>a,pair<rational,ll>b){
if(a.F!=b.F)return a.F<b.F;
return a.S>b.S;
};
priority_queue<pair<rational,ll>,vector<pair<rational,ll>>,decltype(compare)>Q{compare};
REP(i,N)Q.emplace(make_pair(rational(A[i],B[0]),i));
vi T(N);
B.emplace_back(1);
while(M--){
ll i=Q.top().S;Q.pop();
cout<<i+1<<endl;
Q.emplace(make_pair(rational(A[i],B[++T[i]]),i));
}
return 0;
}
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