結果

問題 No.2452 Incline
コンテスト
ユーザー lemondo
提出日時 2023-09-01 23:29:57
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 153 ms / 2,000 ms
コード長 5,991 bytes
コンパイル時間 2,996 ms
コンパイル使用メモリ 300,832 KB
最終ジャッジ日時 2025-02-16 17:29:18
ジャッジサーバーID
（参考情報） 		judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 8
権限があれば一括ダウンロードができます

ソースコード

diff # 

#pragma region Macros
#include <bits/stdc++.h>
#include <immintrin.h>

#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <cctype>
#include <cfenv>
#include <cfloat>
#include <chrono>
#include <cinttypes>
#include <climits>
#include <cmath>
#include <complex>
#include <cstdarg>
#include <cstddef>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <deque>
#include <fstream>
#include <functional>
#include <initializer_list>
#include <iomanip>
#include <ios>
#include <iostream>
#include <istream>
#include <iterator>
#include <limits>
#include <list>
#include <map>
#include <memory>
#include <new>
#include <numeric>
#include <ostream>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <streambuf>
#include <string>
#include <tuple>
#include <type_traits>
#include <typeinfo>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

#define ll long long
#define OVERLOAD(e1, e2, e3, e4, NAME, ...) NAME
#define _rep1(i, n) for (long long i = 0; i < n; i++)
#define _rep2(i, a, b) for (long long i = a; i < b; ++i)
#define _rep3(i, a, b, t) \
    for (long long i = a; i * (t / abs(t)) < b * (t / abs(t)); i += t)
#define rep(...) OVERLOAD(__VA_ARGS__, _rep3, _rep2, _rep1, _)(__VA_ARGS__)
#define all(x) (x).begin(), (x).end()
#define sz(x) (ll) x.size()
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define pcnt __builtin_popcountll
#define SORT(v) sort(all(v))
#define UNIQUE(v) \
    SORT(v);      \
    v.erase(unique(v.begin(), v.end()), v.end());
#define COPY(A, B) copy(all(A), B.begin());
#define REV(v) reverse(all(v))
#define MAX(x) *max_element(all(x))
#define MIN(x) *min_element(all(x))

#ifdef LOCAL
#define dbg(x)                                \
    cout << __LINE__ << " : " << #x << " = "; \
    print(x);
#else
#define dbg(x) true
#endif

using namespace std;
template <typename T>
using vc = vector<T>;
template <typename T>
using vvc = vector<vc<T>>;
template <typename T>
using vvvc = vector<vvc<T>>;

template <typename T>
bool chmin(T &k, T m) {
    bool ret = k > m;
    k = min(k, m);
    return ret;
}
template <typename T>
bool chmax(T &k, T m) {
    bool ret = k < m;
    k = max(k, m);
    return ret;
}

template <typename T>
inline void print(const vector<T> &v, string s = " ") {
    for (ll i = 0; i < (ll)v.size(); i++)
        cout << v[i] << (i != (ll)v.size() - 1 ? s : "\n");
}
template <typename T, typename S>
inline void print(const pair<T, S> &p) {
    cout << p.first << " " << p.second << endl;
}
template <typename T>
inline void print(const T &x) {
    cout << x << "\n";
}
template <typename T, typename S>
inline void print(const vector<pair<T, S>> &v) {
    for (auto &&p : v) print(p);
}
void yes(bool a) { cout << (a ? "yes" : "no") << endl; }
void YES(bool a) { cout << (a ? "YES" : "NO") << endl; }
void Yes(bool a) { cout << (a ? "Yes" : "No") << endl; }
template <typename T>
T SUM(vc<T> As) {
    T ret = 0;
    for (T a : As) ret += a;
    return ret;
}

#pragma endregion

const ll INF = numeric_limits<long long>::max() / 3;

template <int mod>
struct ModInt {
    int x;

    ModInt() : x(0) {}

    ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}

    ModInt &operator+=(const ModInt &p) {
        if ((x += p.x) >= mod) x -= mod;
        return *this;
    }

    ModInt &operator-=(const ModInt &p) {
        if ((x += mod - p.x) >= mod) x -= mod;
        return *this;
    }

    ModInt &operator*=(const ModInt &p) {
        x = (int)(1LL * x * p.x % mod);
        return *this;
    }

    ModInt &operator/=(const ModInt &p) {
        *this *= p.inverse();
        return *this;
    }

    ModInt operator-() const { return ModInt(-x); }

    ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }

    ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }

    ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }

    ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }

    bool operator==(const ModInt &p) const { return x == p.x; }

    bool operator!=(const ModInt &p) const { return x != p.x; }

    ModInt inverse() const {
        int a = x, b = mod, u = 1, v = 0, t;
        while (b > 0) {
            t = a / b;
            swap(a -= t * b, b);
            swap(u -= t * v, v);
        }
        return ModInt(u);
    }

    ModInt pow(int64_t n) const {
        ModInt ret(1), mul(x);
        while (n > 0) {
            if (n & 1) ret *= mul;
            mul *= mul;
            n >>= 1;
        }
        return ret;
    }

    friend ostream &operator<<(ostream &os, const ModInt &p) {
        return os << p.x;
    }

    friend istream &operator>>(istream &is, ModInt &a) {
        int64_t t;
        is >> t;
        a = ModInt<mod>(t);
        return (is);
    }

    static int get_mod() { return mod; }

    int val() const { return x; }
};

const int mod = 998244353;
using mint = ModInt<mod>;

void solve() {
    ll N, M, L, R;
    cin >> N >> M >> L >> R;

    auto f = [&](ll L, ll R) -> mint {
        if (R <= L) return 0;
        ll l = 0, r = INF;
        while (l + 1 < r) {
            ll tar = (l + r) / 2;
            if (double(L) + double(N - 1) * tar > double(INF)) {
                r = tar;
            } else if (L + (N - 1) * tar > R) {
                r = tar;
            } else {
                l = tar;
            }
        }
        ll X = l;
        mint ret =
            mint(R) * X + X - mint(L + (N - 1) + L + (N - 1) * X) * X / 2;
        return ret;
    };

    mint ans = f(0, R) - f(0, L - 1);
    ll L2 = M - R;
    ll R2 = L2 + (R - L);
    ans += f(0, R2) - f(0, L2 - 1);
    ans += R - L + 1;
    print(ans);
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout << fixed << setprecision(15);

    ll T;
    cin >> T;
    rep(_, T)

        solve();
}
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