結果

問題 No.1242 高橋君とすごろく
ユーザー FromBooskaFromBooska
提出日時 2023-09-05 11:59:54
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 5,643 bytes
コンパイル時間 1,045 ms
コンパイル使用メモリ 87,144 KB
実行使用メモリ 87,884 KB
最終ジャッジ日時 2023-09-05 12:00:01
合計ジャッジ時間 5,980 ms
ジャッジサーバーID
（参考情報） 		judge15 / judge12
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 174 ms
84,908 KB
testcase_01 AC 177 ms
80,604 KB
testcase_02 AC 177 ms
80,512 KB
testcase_03 AC 173 ms
80,496 KB
testcase_04 AC 180 ms
80,576 KB
testcase_05 AC 178 ms
80,376 KB
testcase_06 AC 171 ms
80,536 KB
testcase_07 AC 171 ms
80,496 KB
testcase_08 AC 169 ms
80,528 KB
testcase_09 AC 175 ms
80,284 KB
testcase_10 TLE -
testcase_11 -- -
testcase_12 -- -
testcase_13 -- -
testcase_14 -- -
testcase_15 -- -
testcase_16 -- -
testcase_17 -- -
testcase_18 -- -
testcase_19 -- -
testcase_20 -- -
testcase_21 -- -
testcase_22 -- -
testcase_23 -- -
testcase_24 -- -
testcase_25 -- -
testcase_26 -- -
testcase_27 -- -
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ソースコード

diff # 

# すごろくだしゴールから戻っていくか
# そのマスがOKかどうかの判定、1or6, 2or5, 3or4先のすべてが止まれればOKマス
# 戻っていってスタートの1がOKならYes
# コンセプトはそれでいいがN10**18は巨大すぎる
# ただしK<100なのでここは相当非効率でも間に合うと思ったがTLEしたのでマルチセット

# https://github.com/tatyam-prime/SortedSet/blob/main/SortedMultiset.py
import math
from bisect import bisect_left, bisect_right, insort
from typing import Generic, Iterable, Iterator, TypeVar, Union, List
T = TypeVar('T')
 
class SortedMultiset(Generic[T]):
    BUCKET_RATIO = 50
    REBUILD_RATIO = 170
 
    def _build(self, a=None) -> None:
        "Evenly divide `a` into buckets."
        if a is None: a = list(self)
        size = self.size = len(a)
        bucket_size = int(math.ceil(math.sqrt(size / self.BUCKET_RATIO)))
        self.a = [a[size * i // bucket_size : size * (i + 1) // bucket_size] for i in range(bucket_size)]
    
    def __init__(self, a: Iterable[T] = []) -> None:
        "Make a new SortedMultiset from iterable. / O(N) if sorted / O(N log N)"
        a = list(a)
        if not all(a[i] <= a[i + 1] for i in range(len(a) - 1)):
            a = sorted(a)
        self._build(a)
 
    def __iter__(self) -> Iterator[T]:
        for i in self.a:
            for j in i: yield j
 
    def __reversed__(self) -> Iterator[T]:
        for i in reversed(self.a):
            for j in reversed(i): yield j
    
    def __len__(self) -> int:
        return self.size
    
    def __repr__(self) -> str:
        return "SortedMultiset" + str(self.a)
    
    def __str__(self) -> str:
        s = str(list(self))
        return "{" + s[1 : len(s) - 1] + "}"
 
    def _find_bucket(self, x: T) -> List[T]:
        "Find the bucket which should contain x. self must not be empty."
        for a in self.a:
            if x <= a[-1]: return a
        return a
 
    def __contains__(self, x: T) -> bool:
        if self.size == 0: return False
        a = self._find_bucket(x)
        i = bisect_left(a, x)
        return i != len(a) and a[i] == x
 
    def count(self, x: T) -> int:
        "Count the number of x."
        return self.index_right(x) - self.index(x)
 
    def add(self, x: T) -> None:
        "Add an element. / O(√N)"
        if self.size == 0:
            self.a = [[x]]
            self.size = 1
            return
        a = self._find_bucket(x)
        insort(a, x)
        self.size += 1
        if len(a) > len(self.a) * self.REBUILD_RATIO:
            self._build()
 
    def discard(self, x: T) -> bool:
        "Remove an element and return True if removed. / O(√N)"
        if self.size == 0: return False
        a = self._find_bucket(x)
        i = bisect_left(a, x)
        if i == len(a) or a[i] != x: return False
        a.pop(i)
        self.size -= 1
        if len(a) == 0: self._build()
        return True
 
    def lt(self, x: T) -> Union[T, None]:
        "Find the largest element < x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] < x:
                return a[bisect_left(a, x) - 1]
 
    def le(self, x: T) -> Union[T, None]:
        "Find the largest element <= x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] <= x:
                return a[bisect_right(a, x) - 1]
 
    def gt(self, x: T) -> Union[T, None]:
        "Find the smallest element > x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] > x:
                return a[bisect_right(a, x)]
 
    def ge(self, x: T) -> Union[T, None]:
        "Find the smallest element >= x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] >= x:
                return a[bisect_left(a, x)]
    
    def __getitem__(self, x: int) -> T:
        "Return the x-th element, or IndexError if it doesn't exist."
        if x < 0: x += self.size
        if x < 0: raise IndexError
        for a in self.a:
            if x < len(a): return a[x]
            x -= len(a)
        raise IndexError
 
    def index(self, x: T) -> int:
        "Count the number of elements < x."
        ans = 0
        for a in self.a:
            if a[-1] >= x:
                return ans + bisect_left(a, x)
            ans += len(a)
        return ans
 
    def index_right(self, x: T) -> int:
        "Count the number of elements <= x."
        ans = 0
        for a in self.a:
            if a[-1] > x:
                return ans + bisect_right(a, x)
            ans += len(a)
        return ans

N, K = map(int, input().split())
A = list(map(int, input().split()))
SMS = SortedMultiset(A)

ans = 'Yes'
while SMS:
    largest = SMS[-1]
    SMS.discard(largest)
    if largest == 1:
        ans = 'No'
        break
    
    if largest-5 in SMS:
        if largest-6 >= 1 and largest-6 not in SMS:
            SMS.add(largest-6)
    if largest-3 in SMS:
        if largest-5 >= 1 and largest-5 not in SMS:
            SMS.add(largest-5)
    if largest-1 in SMS:
        if largest-4 >= 1 and largest-4 not in SMS:
            SMS.add(largest-4)
           
    # 上でNGとしたものを踏まえて加えるNGがないかチェック
    if largest-5 in SMS:
        if largest-6 >= 1 and largest-6 not in SMS:
            SMS.add(largest-6)
    if largest-3 in SMS:
        if largest-5 >= 1 and largest-5 not in SMS:
            SMS.add(largest-5)
    if largest-1 in SMS:
        if largest-4 >= 1 and largest-4 not in SMS:
            SMS.add(largest-4)
    #A.sort()
    #print('largest', largest, 'SMS', SMS)
    
print(ans)
0