結果

問題 No.3024 全単射的
ユーザー 👑 p-adic
提出日時 2023-09-06 22:49:36
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
TLE  
実行時間 -
コード長 2,474 bytes
コンパイル時間 11,067 ms
コンパイル使用メモリ 277,344 KB
最終ジャッジ日時 2025-02-16 19:08:56
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 11 TLE * 11
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

// O((log N)N 2^N)
#ifdef DEBUG
#define _GLIBCXX_DEBUG
#define UNTIE ios_base::sync_with_stdio( false ); cin.tie( nullptr ); signal( SIGABRT , &AlertAbort )
#define DEXPR( LL , BOUND , VALUE , DEBUG_VALUE ) CEXPR( LL , BOUND , DEBUG_VALUE )
#define CERR( MESSAGE ) cerr << MESSAGE << endl;
#define COUT( ANSWER ) cout << " " << ANSWER << endl
#define ASSERT( A , MIN , MAX ) CERR( "ASSERT " << ( MIN ) << ( ( MIN ) <= A ? "<=" : ">" ) << A << ( A <= ( MAX ) ? "<=" : ">" ) << ( MAX
      ) ); assert( ( MIN ) <= A && A <= ( MAX ) )
#else
#pragma GCC optimize ( "O3" )
#pragma GCC optimize( "unroll-loops" )
#pragma GCC target ( "sse4.2,fma,avx2,popcnt,lzcnt,bmi2" )
#define UNTIE ios_base::sync_with_stdio( false ); cin.tie( nullptr )
#define DEXPR( LL , BOUND , VALUE , DEBUG_VALUE ) CEXPR( LL , BOUND , VALUE )
#define CERR( MESSAGE )
#define COUT( ANSWER ) cout << ANSWER << "\n"
#define ASSERT( A , MIN , MAX ) assert( ( MIN ) <= A && A <= ( MAX ) )
#endif
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define MAIN main
#define TYPE_OF( VAR ) decay_t<decltype( VAR )>
#define CEXPR( LL , BOUND , VALUE ) constexpr LL BOUND = VALUE
#define CIN( LL , A ) LL A; cin >> A
#define SET_ASSERT( A , MIN , MAX ) cin >> A; ASSERT( A , MIN , MAX )
#define CIN_ASSERT( A , MIN , MAX ) TYPE_OF( MAX ) A; SET_ASSERT( A , MIN , MAX )
#define FOR( VAR , INITIAL , FINAL_PLUS_ONE ) for( TYPE_OF( FINAL_PLUS_ONE ) VAR = INITIAL ; VAR < FINAL_PLUS_ONE ; VAR ++ )
#define QUIT return 0
#define RETURN( ANSWER ) COUT( ( ANSWER ) ); QUIT
#ifdef DEBUG
inline void AlertAbort( int n ) { CERR(
      "abortassert" ); }
#endif
int MAIN()
{
UNTIE;
DEXPR( int , bound_N , 100000 , 100 ); // 05
CIN_ASSERT( N , 1 , bound_N );
CEXPR( ll , bound_M , 1000000000000000000 ); // 018
CIN_ASSERT( M , 2 , bound_M );
ll LR[bound_N][2];
FOR( i , 0 , N ){
CIN_ASSERT( Li , 1 , M );
CIN_ASSERT( Ri , Li + 1 , M );
auto& LRi = LR[i];
LRi[0] = --Li;
LRi[1] = --Ri;
}
int answer = 0;
ll S = -1;
while( ( ++S ) >> N == 0 ){
set<ll> fall{};
FOR( i , 0 , N ){
fall.insert( LR[i][(S>>i)&1] );
}
int temp = fall.size();
answer < temp ? answer = temp : answer;
}
RETURN( answer );
}
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