結果

問題 No.93 ペガサス
ユーザー hogloid
提出日時 2016-05-12 23:27:22
言語 C++11
(gcc 13.3.0)
結果
AC  
実行時間 23 ms / 5,000 ms
コード長 2,957 bytes
コンパイル時間 1,337 ms
コンパイル使用メモリ 160,588 KB
実行使用メモリ 19,272 KB
最終ジャッジ日時 2024-10-05 14:07:25
合計ジャッジ時間 2,156 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 16
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#define DEB
#include<bits/stdc++.h>
#define REP(i,m) for(int i=0;i<(m);++i)
#define REPN(i,m,in) for(int i=(in);i<(m);++i)
#define ALL(t) (t).begin(),(t).end()
#define CLR(a) memset((a),0,sizeof(a))
#define pb push_back
#define mp make_pair
#define fr first
#define sc second
using namespace std;
#ifdef DEB
#define dump(x) cerr << #x << " = " << (x) << endl
#define prl cerr<<"called:"<< __LINE__<<endl
template<class T> void debug(T a,T b){ for(;a!=b;++a) cerr<<*a<<' ';cerr<<endl;}
#else
#define dump(x) ;
#define prl ;
template<class T> void debug(T a,T b){ ;}
#endif
template<class T> void chmin(T& a,const T& b) { if(a>b) a=b; }
template<class T> void chmax(T& a,const T& b) { if(a<b) a=b; }
typedef long long int lint;
typedef pair<int,int> pi;
namespace std{
template<class S,class T>
ostream &operator <<(ostream& out,const pair<S,T>& a){
out<<'('<<a.fr<<','<<a.sc<<')';
return out;
}
}
template<lint mod>
struct Int_{
unsigned x;
unsigned mpow(Int_ a,unsigned k){
Int_ res=1;
while(k){
if(k&1) res=res*a;
a=a*a;
k>>=1;
}
return res.x;
}
unsigned inverse(Int_ a){
return mpow(a,mod-2);
}
Int_(): x(0) { }
Int_(long long sig) {
int sigt=sig%mod;
if(sigt<0) sigt+=mod;
x=sigt;
}
unsigned get() const { return (unsigned)x; }
Int_ &operator+=(Int_ that) { if((x += that.x) >= mod) x -= mod; return *this; }
Int_ &operator-=(Int_ that) { if((x += mod - that.x) >= mod) x -= mod; return *this; }
Int_ &operator*=(Int_ that) { x = (unsigned long long)x * that.x % mod; return *this; }
Int_ &operator=(Int_ that) { x=that.x; return *this;}
Int_ &operator/=(Int_ that) { x=(unsigned long long) x * inverse(that.x)%mod; return *this;}
bool operator==(Int_ that) const { return x==that.x; }
bool operator!=(Int_ that) const { return x!=that.x; }
Int_ operator-() const { return Int_(0)-Int_(*this);}
Int_ operator+(Int_ that) const { return Int_(*this) += that; }
Int_ operator-(Int_ that) const { return Int_(*this) -= that; }
Int_ operator*(Int_ that) const { return Int_(*this) *= that; }
Int_ operator/(Int_ that) const { return Int_(*this) /= that; }
};
namespace std{
template<lint mod>
ostream &operator <<(ostream& out,const Int_<mod>& a){
out<<a.get();
return out;
}
template<lint mod>
istream &operator >>(istream& in,Int_<mod>& a){
in>>a.x;
return in;
}
};
typedef Int_<1000000007> Int;
//const int INF=5e8;
Int dp[1005][1005][2][2];
int n;
int main(){
cin>>n;
dp[1][0][0][0]=1;
dp[2][0][0][0]=2;
for(int i=2;i<n;++i) REP(j,i+1) REP(t,2) REP(t2,2) if(dp[i][j][t][t2]!=0){
Int val=dp[i][j][t][t2];
dp[i+1][j+1][t2][1]+=val*(2-t);
dp[i+1][j][t2][1]+=val*t;
dp[i+1][j][t2][0]+=val*(i+1-j-(2-t));
if(j) dp[i+1][j-1][t2][0]+=val*(j-t-t2);
if(j) dp[i+1][j-1][0][0]+=val*t2;
}
Int res=0;
REP(t,2) REP(t2,2) res+=dp[n][0][t][t2];
cout<<res<<endl;
return 0;
}
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