結果

問題 No.177 制作進行の宮森あおいです!
ユーザー lemondo
提出日時 2023-09-29 15:16:57
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 7,257 bytes
コンパイル時間 3,109 ms
コンパイル使用メモリ 319,416 KB
最終ジャッジ日時 2025-02-17 02:57:18
ジャッジサーバーID
(参考情報)
judge3 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 13
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#pragma region Macros
#include <bits/stdc++.h>
#include <immintrin.h>
#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <cctype>
#include <cfenv>
#include <cfloat>
#include <chrono>
#include <cinttypes>
#include <climits>
#include <cmath>
#include <complex>
#include <cstdarg>
#include <cstddef>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <deque>
#include <fstream>
#include <functional>
#include <initializer_list>
#include <iomanip>
#include <ios>
#include <iostream>
#include <istream>
#include <iterator>
#include <limits>
#include <list>
#include <map>
#include <memory>
#include <new>
#include <numeric>
#include <ostream>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <streambuf>
#include <string>
#include <tuple>
#include <type_traits>
#include <typeinfo>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
#define ll long long
#define OVERLOAD(e1, e2, e3, e4, NAME, ...) NAME
#define _rep1(i, n) for (long long i = 0; i < n; i++)
#define _rep2(i, a, b) for (long long i = a; i < b; ++i)
#define _rep3(i, a, b, t) \
for (long long i = a; i * (t / abs(t)) < b * (t / abs(t)); i += t)
#define rep(...) OVERLOAD(__VA_ARGS__, _rep3, _rep2, _rep1, _)(__VA_ARGS__)
#define all(x) (x).begin(), (x).end()
#define sz(x) (int)x.size()
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define pcnt __builtin_popcountll
#define SORT(v) sort(all(v))
#define UNIQUE(v) \
SORT(v); \
v.erase(unique(v.begin(), v.end()), v.end());
#define COPY(A, B) copy(all(A), B.begin());
#define REV(v) reverse(all(v))
#define MAX(x) *max_element(all(x))
#define MIN(x) *min_element(all(x))
#ifdef LOCAL
#define dbg(x) \
{ \
cout << __LINE__ << " : " << #x << " = "; \
print(x); \
}
#define IS_LOCAL true
#else
#define dbg(x) true
#define IS_LOCAL false
#endif
using namespace std;
template <typename T>
using vc = vector<T>;
template <typename T>
using vvc = vector<vc<T>>;
template <typename T>
using vvvc = vector<vvc<T>>;
template <typename T>
bool chmin(T& k, T m) {
bool ret = k > m;
k = min(k, m);
return ret;
}
template <typename T>
bool chmax(T& k, T m) {
bool ret = k < m;
k = max(k, m);
return ret;
}
template <typename T>
inline void print(const vector<T>& v, string s = " ") {
for (int i = 0; i < (int)v.size(); i++)
cout << v[i] << (i != (int)v.size() - 1 ? s : "");
cout << "\n";
}
template <typename T, typename S>
inline void print(const pair<T, S>& p) {
cout << p.first << " " << p.second << endl;
}
template <typename T>
inline void print(const T& x) {
cout << x << "\n";
}
template <typename T, typename S>
inline void print(const vector<pair<T, S>>& v) {
for (auto&& p : v) print(p);
}
void yes(bool a) { cout << (a ? "yes" : "no") << endl; }
void YES(bool a) { cout << (a ? "YES" : "NO") << endl; }
void Yes(bool a) { cout << (a ? "Yes" : "No") << endl; }
template <typename T>
T SUM(vc<T> As) {
T ret = 0;
for (T a : As) ret += a;
return ret;
}
#pragma endregion
const ll INF = numeric_limits<long long>::max();
/**
* @brief Dinic()
* @docs docs/dinic.md
*/
template <typename flow_t>
struct Dinic {
const flow_t INF;
struct edge {
int to;
flow_t cap;
int rev;
bool isrev;
int idx;
};
vector<vector<edge>> graph;
vector<int> min_cost, iter;
explicit Dinic(int V) : INF(numeric_limits<flow_t>::max()), graph(V) {}
void add_edge(int from, int to, flow_t cap, int idx = -1) {
assert(cap >= 0);
graph[from].emplace_back(
(edge){to, cap, (int)graph[to].size(), false, idx});
graph[to].emplace_back(
(edge){from, 0, (int)graph[from].size() - 1, true, idx});
}
bool build_augment_path(int s, int t) {
min_cost.assign(graph.size(), -1);
queue<int> que;
min_cost[s] = 0;
que.push(s);
while (!que.empty() && min_cost[t] == -1) {
int p = que.front();
que.pop();
for (auto& e : graph[p]) {
if (e.cap > 0 && min_cost[e.to] == -1) {
min_cost[e.to] = min_cost[p] + 1;
que.push(e.to);
}
}
}
return min_cost[t] != -1;
}
flow_t find_min_dist_augment_path(int idx, const int t, flow_t flow) {
if (idx == t) return flow;
for (int& i = iter[idx]; i < (int)graph[idx].size(); i++) {
edge& e = graph[idx][i];
if (e.cap > 0 && min_cost[idx] < min_cost[e.to]) {
flow_t d =
find_min_dist_augment_path(e.to, t, min(flow, e.cap));
if (d > 0) {
e.cap -= d;
graph[e.to][e.rev].cap += d;
return d;
}
}
}
return 0;
}
flow_t max_flow(int s, int t) {
flow_t flow = 0;
while (build_augment_path(s, t)) {
iter.assign(graph.size(), 0);
flow_t f;
while ((f = find_min_dist_augment_path(s, t, INF)) > 0) flow += f;
}
return flow;
}
void output() {
for (int i = 0; i < graph.size(); i++) {
for (auto& e : graph[i]) {
if (e.isrev) continue;
auto& rev_e = graph[e.to][e.rev];
cout << i << "->" << e.to << " (flow: " << rev_e.cap << "/"
<< e.cap + rev_e.cap << ")" << endl;
}
}
}
vector<bool> min_cut(int s) {
// 使
vector<bool> used(graph.size());
queue<int> que;
que.emplace(s);
used[s] = true;
while (not que.empty()) {
int p = que.front();
que.pop();
for (auto& e : graph[p]) {
if (e.cap > 0 and not used[e.to]) {
used[e.to] = true;
que.emplace(e.to);
}
}
}
return used;
}
};
void solve() {
ll W;
cin >> W;
ll N;
cin >> N;
vc<ll> Js(N);
rep(i, N) cin >> Js[i];
ll M;
cin >> M;
vc<ll> Cs(M);
rep(i, M) cin >> Cs[i];
Dinic<ll> dinic(N + M + 2);
rep(i, N) { dinic.add_edge(N + M, i, Js[i]); }
rep(i, M) {
ll Q;
cin >> Q;
unordered_set<ll> cant;
rep(_, Q) {
ll x;
cin >> x;
x--;
cant.insert(x);
}
rep(j, N) {
if (cant.count(j)) continue;
dinic.add_edge(j, N + i, Js[j]);
}
dinic.add_edge(N + i, N + M + 1, Cs[i]);
}
ll f = dinic.max_flow(N + M, N + M + 1);
dbg(f);
if (f >= W) {
print("SHIROBAKO");
} else {
print("BANSAKUTSUKITA");
}
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout << fixed << setprecision(15);
// ll T; cin >> T;
// rep(_, T)
solve();
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0