結果
問題 | No.2488 Mod Sum Maximization |
ユーザー | woodywoody |
提出日時 | 2023-09-30 15:10:46 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 5,032 bytes |
コンパイル時間 | 3,820 ms |
コンパイル使用メモリ | 230,116 KB |
実行使用メモリ | 9,680 KB |
最終ジャッジ日時 | 2024-07-23 09:10:29 |
合計ジャッジ時間 | 12,466 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 12 ms
7,136 KB |
testcase_01 | AC | 7 ms
7,176 KB |
testcase_02 | AC | 3 ms
7,084 KB |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | AC | 271 ms
9,288 KB |
testcase_07 | WA | - |
testcase_08 | AC | 275 ms
9,348 KB |
testcase_09 | AC | 208 ms
8,896 KB |
testcase_10 | WA | - |
testcase_11 | AC | 9 ms
7,268 KB |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | WA | - |
testcase_15 | AC | 164 ms
8,576 KB |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | AC | 225 ms
9,148 KB |
testcase_20 | WA | - |
testcase_21 | AC | 242 ms
9,136 KB |
testcase_22 | WA | - |
testcase_23 | AC | 288 ms
9,396 KB |
testcase_24 | WA | - |
testcase_25 | AC | 8 ms
7,168 KB |
testcase_26 | AC | 15 ms
7,200 KB |
testcase_27 | AC | 239 ms
8,400 KB |
testcase_28 | AC | 252 ms
8,356 KB |
testcase_29 | AC | 209 ms
8,264 KB |
testcase_30 | AC | 142 ms
7,872 KB |
testcase_31 | AC | 25 ms
7,316 KB |
testcase_32 | AC | 394 ms
8,940 KB |
testcase_33 | AC | 5 ms
7,168 KB |
testcase_34 | AC | 429 ms
9,372 KB |
testcase_35 | AC | 121 ms
7,904 KB |
testcase_36 | AC | 3 ms
7,136 KB |
testcase_37 | AC | 4 ms
7,108 KB |
testcase_38 | AC | 4 ms
7,192 KB |
testcase_39 | AC | 5 ms
7,168 KB |
testcase_40 | AC | 4 ms
7,208 KB |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,b) for(int i=0;i<b;i++) #define rrep(i,b) for(int i=b-1;i>=0;i--) #define rep1(i,b) for(int i=1;i<b;i++) #define repx(i,x,b) for(int i=x;i<b;i++) #define rrepx(i,x,b) for(int i=b-1;i>=x;i--) #define fore(i,a) for(auto& i:a) #define rng(x) (x).begin(), (x).end() #define rrng(x) (x).rbegin(), (x).rend() #define sz(x) ((int)(x).size()) #define pb push_back #define fi first #define se second #define pcnt __builtin_popcountll using namespace std; using namespace atcoder; using ll = long long; using ld = long double; template<typename T> using mpq = priority_queue<T, vector<T>, greater<T>>; template<typename T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; } template<typename T> bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; } template<typename T> ll sumv(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}} #define retval(x) {cout << #x << endl; return;} #define cout2(x,y) cout << x << " " << y << endl; #define coutp(p) cout << p.fi << " " << p.se << endl; #define out cout << ans << endl; #define outd cout << fixed << setprecision(20) << ans << endl; #define outm cout << ans.val() << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define outdv fore(yans , ans) cout << yans.val() << "\n"; #define assertmle(x) if (!x) {vi v(3e8);} #define asserttle(x) if (!x) {while(1){}} #define coutv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define coutv2(v) fore(vy , v) cout << vy << "\n"; #define coutvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define coutvm2(v) fore(vy , v) cout << vy.val() << "\n"; using pll = pair<ll,ll>;using pil = pair<int,ll>;using pli = pair<ll,int>;using pii = pair<int,int>;using pdd = pair<ld,ld>; using vi = vector<int>;using vd = vector<ld>;using vl = vector<ll>;using vs = vector<string>;using vb = vector<bool>; using vpii = vector<pii>;using vpli = vector<pli>;using vpll = vector<pll>;using vpil = vector<pil>; using vvi = vector<vector<int>>;using vvl = vector<vector<ll>>;using vvs = vector<vector<string>>;using vvb = vector<vector<bool>>; using vvpii = vector<vector<pii>>;using vvpli = vector<vector<pli>>;using vvpll = vector<vpll>;using vvpil = vector<vpil>; using mint = modint998244353; //using mint = modint1000000007; //using mint = dynamic_modint<0>; using vm = vector<mint>; using vvm = vector<vector<mint>>; vector<int> dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} #define yes {cout <<"Yes"<<endl;} #define no {cout <<"No"<<endl;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; #ifdef MY_LOCAL_DEBUG #include "./debug/localDebug.cpp" #define showp(p) cerr<<#p<<" = "<<p.fi<<" : "<<p.se<<endl #define show1(a) cerr<<#a<<" = "<<a<<endl #define show2(a,b) cerr<<#a<<" = "<<a<<" : "<<#b<<" = "<<b<<endl #define show3(a,b,c) cerr<<#a<<" = "<<a<<" : "<<#b<<" = "<<b<<" : "<<#c<<" = "<<c<<endl #define show4(a,b,c,d) cerr<<#a<<" = "<<a<<" : "<<#b<<" = "<<b<<" : "<<#c<<" = "<<c<<" : "<<#d<<" = "<<d<<endl #define show5(a,b,c,d,e) cerr<<#a<<" = "<<a<<" : "<<#b<<" = "<<b<<" : "<<#c<<" = "<<c<<" : "<<#d<<" = "<<d<<" : "<<#e<<" = "<<e<<endl #define DEBUG_LINE cout << "DEBUG_LINE : " << __LINE__ << endl #define showv(v) {cout<<#v<<" : "; fore(vy , v) {cout << vy << " ";} cout << endl;} #define showv2(v) {cout<<#v<<endl; fore(vy , v) cout << vy << "\n";} #define showvm(v) {cout<<#v<<" : "; fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define showvm2(v) {cout<<#v<<endl; fore(vy , v) cout << vy.val() << "\n";} #define showmat(v) {cout<<#v<<endl; fore(row , v) { fore(seg , row) cout << seg << " "; cout << endl;}} #define showmatm(v) {cout<<#v<<endl; fore(row , v) { fore(seg , row) cout << seg.val() << " "; cout << endl;}} #else #define showp(p) #define show1(a) #define show2(a,b) #define show3(a,b,c) #define show4(a,b,c,d) #define show5(a,b,c,d,e) #define DEBUG_LINE #define showv(v) #define showv2(v) #define showvm(v) #define showvm2(v) #define showmat(v) #define showmatm(v) #endif #define overload5(a,b,c,d,e,f, ...) f #define show(...) overload5(__VA_ARGS__, show5, show4, show3, show2, show1)(__VA_ARGS__) void solve(){ int n; cin>>n; vi a(n); rep(i,n) cin>>a[i]; vi dp(n,INF); dp[0] = 0; const int mxa = (int)1e6+1; vi idxr(mxa); rep(i,n) idxr[a[i]] = i; rep(i,n-1){ for(int j=a[i]; j<mxa+a[i]; j+=a[i]){ auto it = lower_bound(rng(a), j); if (it == a.begin()) continue; it--; int id = idxr[*it]; chmin(dp[id], dp[i] + (a[id]/a[i])*a[i]); } } ll ans = sumv(a) - dp[n-1]; out; return; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int t = 1; //cin>>t; rep(i,t){ solve(); } return 0; }