結果

問題 No.2501 Maximum Inversion Number
ユーザー sgfcsgfc
提出日時 2023-10-14 00:10:21
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 390 ms / 2,000 ms
コード長 4,221 bytes
コンパイル時間 5,719 ms
コンパイル使用メモリ 315,080 KB
実行使用メモリ 7,936 KB
最終ジャッジ日時 2024-09-15 20:03:09
合計ジャッジ時間 7,874 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 17
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include "bits/stdc++.h"
#include <unordered_map>
#include <unordered_set>
#include <stdio.h>
#include <math.h>
#include <cassert>
#include "atcoder/all"
#include <float.h>
//#include <boost/multiprecision/cpp_int.hpp>
//using namespace boost::multiprecision;
// std::fixed << std::setprecision(10) <<
using namespace std;
using namespace atcoder;
using ll = long long;
using ull = unsigned long long;
using mint = modint998244353;
using mint2 = modint1000000007;
const double eps = 1e-9;
#define REP(i, n) for (ll i = 0; i < ll(n); ++i)
#define REPI(i, init, n) for (ll i = init; i < ll(n); ++i)
#define REPD(i, init) for (ll i = init; i >=0; --i)
#define REPDI(i, init, n) for (ll i = init; i >=n; --i)
#define REPE(i, c) for (const auto& i : c)
#define TCASE() ll _ttt; cin >> _ttt; while(_ttt--)
using vl = vector<ll>;
#define VL(a, n) vector<ll> a; a.assign(n, 0);
#define VLI(a, n) vector<ll> a; a.assign(n, 0); for(auto& x : a) cin >> x;
#define VSI(a, n) vector<string> a; a.assign(n, ""); for(auto& x : a) cin >> x;
using vvl = vector<vector<ll>>;
#define VVLI(a, n, m, init) vector<vector<ll>> a(n); for(auto& x : a) x.assign(m, init);
using vd = vector<double>;
using pl = pair<ll, ll>;
struct uv { ll u; ll v; ll c; };
#define VUVI(a, n) vector<uv> a; a.assign(n, {0, 0, 1}); for(auto& x : a) {cin >> x.u >> x.v; x.u--; x.v--;}
#define VUVCI(a, n) vector<uv> a; a.assign(n, {0, 0, 0}); for(auto& x : a) {cin >> x.u >> x.v >> x.c; x.u--; x.v--;}
vvl to_edge(const ll n, const vector<uv>& v) { vvl ret(n); for (auto& x : v) ret[x.u].push_back(x.v); return ret; }
vvl to_edge_d(const ll n, const vector<uv>& v) { vvl ret(n); for (auto& x : v) { ret[x.u].push_back(x.v); ret[x.v].push_back(x.u); } return ret; }
template <class T = long long> using pql = priority_queue<T>;
template <class T = long long> using pqg = priority_queue<T, vector<T>, greater<T>>;
using vm = vector<mint>;
using vvm = vector<vm>;
void yn(bool f) { std::cout << (f ? "Yes" : "No") << endl; };
template<class T> void ov(const T& v) { for (auto it = v.begin(); it != v.end(); it++) { if (it != v.begin()) cout << " "; cout << *it; } };
template<> void ov(const vm& v) { for (auto it = v.begin(); it != v.end(); it++) { if (it != v.begin()) cout << " "; cout << it->val(); } };
const ll llhuge = 1LL << 60; //
auto gmax(const auto& a, const auto& b) { return a > b ? a : b; };
auto gmin(const auto& a, const auto& b) { return a < b ? a : b; };
template<class T, class U> bool chmin(T& a, const U& b) { const T olda = a; a = gmin(a, b); return olda != a; }
template<class T, class U> bool chmax(T& a, const U& b) { const T olda = a; a = gmax(a, b); return olda != a; }
template<class T> void mysort(T& v) { std::sort(begin(v), end(v)); };
template<class T, class U> void mysort(T& v, U pr) { std::sort(begin(v), end(v), pr); };
template<class T> void myrev(T& v) { std::reverse(begin(v), end(v)); };
//f(t)t
//ng < ok t ng > ok t
template <class F>
ll bs(ll ng, ll ok, F f) {
while (abs(ok - ng) > 1) {
ll mid = (ok + ng) / 2;
if (f(mid)) ok = mid;
else ng = mid;
}
return ok;
}
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
TCASE() {
ll n, m;
cin >> n >> m;
VLI(l, n);
VLI(r, n);
ll lsum = 0;
ll rsum = 0;
REP(i, n) {
lsum += l[i];
rsum += r[i];
}
if (lsum > m || rsum < m) {
cout << -1 << endl;
continue;
}
//調
ll tv = bs(m + 1, 0, [&](ll t) {
ll sum = 0;
REP(i, n) {
ll add = t;
if (r[i] < t) add = r[i];
if (l[i] > t) add = l[i];
sum += add;
}
return sum <= m;
});
//
vl tl = l;
REP(i, n) {
if (r[i] < tv) tl[i] = r[i];
else chmax(tl[i], tv);
m -= tl[i];
}
//m1
REPD(i, n - 1) {
if (m <= 0) break;
if (tl[i] == tv && tl[i] < r[i]) {
tl[i]++;
m--;
}
}
//
ll ans = 0;
ll revt = 0;
REP(i, n) {
ans += revt * tl[i];
revt += tl[i];
}
cout << ans << endl;
}
}
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