結果
問題 | No.2501 Maximum Inversion Number |
ユーザー | woodywoody |
提出日時 | 2023-10-14 12:49:33 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 6,029 bytes |
コンパイル時間 | 4,125 ms |
コンパイル使用メモリ | 237,020 KB |
実行使用メモリ | 10,624 KB |
最終ジャッジ日時 | 2024-09-16 07:38:14 |
合計ジャッジ時間 | 8,005 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
(要ログイン)
テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
10,624 KB |
testcase_01 | TLE | - |
testcase_02 | -- | - |
testcase_03 | -- | - |
testcase_04 | -- | - |
testcase_05 | -- | - |
testcase_06 | -- | - |
testcase_07 | -- | - |
testcase_08 | -- | - |
testcase_09 | -- | - |
testcase_10 | -- | - |
testcase_11 | -- | - |
testcase_12 | -- | - |
testcase_13 | -- | - |
testcase_14 | -- | - |
testcase_15 | -- | - |
testcase_16 | -- | - |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,b) for(int i=0;i<b;i++) #define rrep(i,b) for(int i=b-1;i>=0;i--) #define rep1(i,b) for(int i=1;i<b;i++) #define repx(i,x,b) for(int i=x;i<b;i++) #define rrepx(i,x,b) for(int i=b-1;i>=x;i--) #define fore(i,a) for(auto& i:a) #define rng(x) (x).begin(), (x).end() #define rrng(x) (x).rbegin(), (x).rend() #define sz(x) ((int)(x).size()) #define pb push_back #define fi first #define se second #define pcnt __builtin_popcountll using namespace std; using namespace atcoder; using ll = long long; using ld = long double; template<typename T> using mpq = priority_queue<T, vector<T>, greater<T>>; template<typename T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; } template<typename T> bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; } template<typename T> ll sumv(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}} #define retval(x) {cout << #x << endl; return;} #define cout2(x,y) cout << x << " " << y << endl; #define coutp(p) cout << p.fi << " " << p.se << endl; #define out cout << ans << endl; #define outd cout << fixed << setprecision(20) << ans << endl; #define outm cout << ans.val() << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define outdv fore(yans , ans) cout << yans.val() << "\n"; #define assertmle(x) if (!(x)) {vi v(3e8);} #define asserttle(x) if (!(x)) {while(1){}} #define coutv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define coutv2(v) fore(vy , v) cout << vy << "\n"; #define coutvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define coutvm2(v) fore(vy , v) cout << vy.val() << "\n"; using pll = pair<ll,ll>;using pil = pair<int,ll>;using pli = pair<ll,int>;using pii = pair<int,int>;using pdd = pair<ld,ld>; using vi = vector<int>;using vd = vector<ld>;using vl = vector<ll>;using vs = vector<string>;using vb = vector<bool>; using vpii = vector<pii>;using vpli = vector<pli>;using vpll = vector<pll>;using vpil = vector<pil>; using vvi = vector<vector<int>>;using vvl = vector<vector<ll>>;using vvs = vector<vector<string>>;using vvb = vector<vector<bool>>; using vvpii = vector<vector<pii>>;using vvpli = vector<vector<pli>>;using vvpll = vector<vpll>;using vvpil = vector<vpil>; using mint = modint998244353; //using mint = modint1000000007; //using mint = dynamic_modint<0>; using vm = vector<mint>; using vvm = vector<vector<mint>>; vector<int> dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} #define yes {cout <<"Yes"<<endl;} #define no {cout <<"No"<<endl;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; #ifdef MY_LOCAL_DEBUG #include "./debug/localDebug.cpp" #define showp(p) cerr<<#p<<" = "<<p.fi<<" : "<<p.se<<endl #define show1(a) cerr<<#a<<" = "<<a<<endl #define show2(a,b) cerr<<#a<<" = "<<a<<" : "<<#b<<" = "<<b<<endl #define show3(a,b,c) cerr<<#a<<" = "<<a<<" : "<<#b<<" = "<<b<<" : "<<#c<<" = "<<c<<endl #define show4(a,b,c,d) cerr<<#a<<" = "<<a<<" : "<<#b<<" = "<<b<<" : "<<#c<<" = "<<c<<" : "<<#d<<" = "<<d<<endl #define show5(a,b,c,d,e) cerr<<#a<<" = "<<a<<" : "<<#b<<" = "<<b<<" : "<<#c<<" = "<<c<<" : "<<#d<<" = "<<d<<" : "<<#e<<" = "<<e<<endl #define DEBUG_LINE cout << "DEBUG_LINE : " << __LINE__ << endl #define showv(v) {cout<<#v<<" : "; fore(vy , v) {cout << vy << " ";} cout << endl;} #define showv2(v) {cout<<#v<<endl; fore(vy , v) cout << vy << "\n";} #define showvm(v) {cout<<#v<<" : "; fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define showvm2(v) {cout<<#v<<endl; fore(vy , v) cout << vy.val() << "\n";} #define showmat(v) {cout<<#v<<endl; fore(row , v) { fore(seg , row) cout << seg << " "; cout << endl;}} #define showmatm(v) {cout<<#v<<endl; fore(row , v) { fore(seg , row) cout << seg.val() << " "; cout << endl;}} #else #define showp(p) #define show1(a) #define show2(a,b) #define show3(a,b,c) #define show4(a,b,c,d) #define show5(a,b,c,d,e) #define DEBUG_LINE #define showv(v) #define showv2(v) #define showvm(v) #define showvm2(v) #define showmat(v) #define showmatm(v) #endif #define overload5(a,b,c,d,e,f, ...) f #define show(...) overload5(__VA_ARGS__, show5, show4, show3, show2, show1)(__VA_ARGS__) void solve(){ int n,m; cin>>n>>m; vl l(n), r(n); rep(i,n) cin>>l[i]; rep(i,n) cin>>r[i]; ll suml = sumv(l); ll sumr = sumv(r); if (suml > m) retval(-1); if (sumr < m) retval(-1); auto check = [&](ll mid)->bool{ ll sum = 0; rep(i,n){ if (mid <= l[i]) sum += l[i]; else if(mid >= r[i]) sum += r[i]; else sum += mid; } return (sum<=m); }; ll bsl = 0, bsu = 2e9; if (check(bsu)){ assertmle(sumv(r)==m); ll ans = 0; rep(i,n){ ans += (m-r[i])*r[i]; } ans /= 2; out; } while(bsu-bsl>1){ ll mid = (bsl+bsu)/2; if (check(mid)) bsl = mid; else bsu = mid; } ll res = m; mpq<pll> q; vl v; rep(i,n){ ll tmp = 0; if (l[i] >= bsl) tmp = l[i]; else if(r[i] <= bsl) tmp = r[i]; else tmp = bsl; res -= bsl; if (tmp == r[i]){ v.pb(r[i]); }else{ q.push({tmp,r[i]}); } } asserttle(res>=0); while(sz(q) && res){ pll p = q.top(); q.pop(); res--; pll nxt = {p.fi+1, p.se}; if (nxt.fi == nxt.se) v.pb(nxt.fi); else q.push(nxt); } while(sz(q)){ v.pb(q.top().fi); q.pop(); } assert(sumv(v)==m); assert(sz(v)==n); ll ans = 0; rep(i,n){ ans += (m-v[i])*v[i]; } ans /= 2; out; return; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int t = 1; cin>>t; rep(i,t){ solve(); } return 0; }