結果
| 問題 | No.2519 Coins in Array |
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2023-10-27 22:42:08 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.89.0) |
| 結果 |
AC
|
| 実行時間 | 89 ms / 2,000 ms |
| コード長 | 2,528 bytes |
| 記録 | |
| コンパイル時間 | 3,544 ms |
| コンパイル使用メモリ | 253,024 KB |
| 最終ジャッジ日時 | 2025-02-17 15:31:28 |
|
ジャッジサーバーID (参考情報) |
judge4 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 37 |
ソースコード
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
template <int m>
std::ostream& operator<<(std::ostream& os, const atcoder::static_modint<m>& a) {os << a.val(); return os;}
template<typename T>
istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename T>
ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template <typename T>
ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
int main(){
int n;
cin >> n;
vl a(n);
cin >> a;
auto func = [&](ll x, ll y){
if(x == 0 or y == 0) return (long long)0;
ll g = gcd(x, y);
if(g >= 2) return (long long)0;
else return (x - 1) * (y - 1);
};
if(n >= 4){
vi e;
vi o;
rep(i, n){
if(a[i] % 2 == 0){
e.push_back(i);
if(int(e.size()) >= 2 and int(o.size()) >= 4) break;
}else{
o.push_back(i);
if(int(e.size()) >= 2 and int(o.size()) >= 4) break;
}
}
cout << "0\n";
if(int(e.size()) >= 2){
cout << e[0] + 1 << ' ' << e[1] + 1 << "\n";
rep(i, n - 2){
cout << 1 << ' ' << n - 1 - i << "\n";
}
return 0;
}
if(int(e.size()) == 1){
cout << o[0] + 1 << ' ' << o[1] + 1 << "\n";
int cnt = 0;
if(o[0] < e[0]) cnt++;
if(o[1] < e[0]) cnt++;
e[0] -= cnt;
cout << e[0] + 1 << ' ' << n - 1 << "\n";
rep(i, n - 3){
cout << 1 << ' ' << n - 2 - i << "\n";
}
return 0;
}
cout << o[0] + 1 << ' ' << o[1] + 1 << "\n";
o[2] -= 2;
o[3] -= 2;
cout << o[2] + 1 << ' ' << o[3] + 1 << "\n";
cout << n - 3 << ' ' << n - 2 << "\n";
rep(i, n - 4){
cout << 1 << ' ' << n - 3 - i << "\n";
}
return 0;
}
vi perm(n);
rep(i, n) perm[i] = i;
vi ans_perm = perm;
ll ans = 1001001001001001001;
do{
long long tmp = 0;
if(n == 2) tmp = func(a[perm[0]], a[perm[1]]);
if(n == 3) tmp = func(func(a[perm[0]], a[perm[1]]), a[perm[2]]);
if(tmp < ans){
ans = tmp;
ans_perm = perm;
}
}while(next_permutation(perm.begin(), perm.end()));
cout << ans << "\n";
cout << ans_perm[0] + 1 << ' ' << ans_perm[1] + 1 << "\n";
if(n == 3) cout << "1 2\n";
return 0;
}