結果

問題 No.2540 同値性判定
ユーザー Kude
提出日時 2023-11-10 23:53:21
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 49 ms / 2,500 ms
コード長 3,780 bytes
コンパイル時間 3,731 ms
コンパイル使用メモリ 281,668 KB
実行使用メモリ 51,724 KB
最終ジャッジ日時 2024-09-26 02:27:52
合計ジャッジ時間 7,610 ms
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 37
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
namespace {
#pragma GCC diagnostic ignored "-Wunused-function"
#include<atcoder/all>
#pragma GCC diagnostic warning "-Wunused-function"
using namespace std;
using namespace atcoder;
#define rep(i,n) for(int i = 0; i < (int)(n); i++)
#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; i--)
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
template<class T> bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; } else return false; }
template<class T> bool chmin(T& a, const T& b) { if (b < a) { a = b; return true; } else return false; }
using ll = long long;
using P = pair<int,int>;
using VI = vector<int>;
using VVI = vector<VI>;
using VL = vector<ll>;
using VVL = vector<VL>;
template <class F, F (*composition)(F, F), F (*id)()> struct dual_segtree {
public:
dual_segtree() : dual_segtree(0) {}
explicit dual_segtree(int n) : dual_segtree(std::vector<F>(n, id())) {}
explicit dual_segtree(const std::vector<F>& v) : _n(int(v.size())) {
auto ceil_log2 = [](int n) {
int x = 0;
while ((1U << x) < (unsigned int)(n)) x++;
return x;
};
log = ceil_log2(_n);
size = 1 << log;
lz = std::vector<F>(2 * size, id());
for (int i = 0; i < _n; i++) lz[size + i] = v[i];
}
void set(int p, F x) {
assert(0 <= p && p < _n);
p += size;
for (int i = log; i >= 1; i--) push(p >> i);
lz[p] = x;
}
F get(int p) {
assert(0 <= p && p < _n);
p += size;
for (int i = log; i >= 1; i--) push(p >> i);
return lz[p];
}
void apply(int p, F f) {
assert(0 <= p && p < _n);
p += size;
for (int i = log; i >= 1; i--) push(p >> i);
lz[p] = composition(f, lz[p]);
}
void apply(int l, int r, F f) {
assert(0 <= l && l <= r && r <= _n);
if (l == r) return;
l += size;
r += size;
for (int i = log; i >= 1; i--) {
if (((l >> i) << i) != l) push(l >> i);
if (((r >> i) << i) != r) push((r - 1) >> i);
}
while (l < r) {
if (l & 1) all_apply(l++, f);
if (r & 1) all_apply(--r, f);
l >>= 1;
r >>= 1;
}
}
void push_all() {
for (int i = 1; i < size; i++) push(i);
}
F get_raw(int p) {
assert(0 <= p && p < _n);
return lz[size + p];
}
private:
int _n, size, log;
std::vector<F> lz;
void all_apply(int k, F f) {
lz[k] = composition(f, lz[k]);
}
void push(int k) {
all_apply(2 * k, lz[k]);
all_apply(2 * k + 1, lz[k]);
lz[k] = id();
}
};
using ull = unsigned long long;
struct F {
ull a, b;
};
F composition(F f, F g) {
// fa(gax+gb)+fb
return F{f.a & g.a, (f.a & g.b) ^ f.b};
}
F id() { return {~0ULL, 0}; }
} int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int n, q;
cin >> n >> q;
ull p[6]{};
rep(s, 1 << 6) {
rep(k, 6) p[k] |= ull(s >> k & 1) << s;
}
vector<F> init(n);
rep(i, n) init[i] = F{0ULL, p[i % 6]};
dual_segtree<F, composition, id> seg(init);
rep(_, q) {
int h, l1, r1, l2, r2;
string o;
cin >> h >> o >> l1 >> r1 >> l2 >> r2;
r1++, r2++;
ull y = seg.get(h).b;
F f;
if (o == "land") {
f = F{y, 0};
} else if (o == "lor") {
f = F{y ^ ~0ULL, y};
} else {
assert(o == "Rightarrow");
f = F{y ^ ~0ULL, ~0ULL};
}
seg.apply(l1, r1, f);
set<ull> seen;
bool ok = false;
for (int i = l2; i < r2; i++) {
ull x = seg.get(i).b;
if (seen.contains(x)) {
ok = true;
break;
}
seen.insert(x);
}
cout << (ok ? "Yes\n" : "No\n");
}
}
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