結果
| 問題 |
No.1983 [Cherry 4th Tune C] 南の島のマーメイド
|
| コンテスト | |
| ユーザー |
mkawa2
|
| 提出日時 | 2023-11-11 18:45:59 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 784 ms / 4,000 ms |
| コード長 | 3,405 bytes |
| コンパイル時間 | 294 ms |
| コンパイル使用メモリ | 82,308 KB |
| 実行使用メモリ | 152,916 KB |
| 最終ジャッジ日時 | 2024-09-26 02:50:43 |
| 合計ジャッジ時間 | 20,851 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 41 |
ソースコード
import sys
# sys.setrecursionlimit(1000005)
# sys.set_int_max_str_digits(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
# inf = -1-(-1 << 31)
inf = -1-(-1 << 63)
# md = 10**9+7
md = 998244353
class UnionFind:
def __init__(self, n):
self._tree = [-1]*n
# number of connected component
self.cnt = n
def root(self, u):
stack = []
while self._tree[u] >= 0:
stack.append(u)
u = self._tree[u]
for v in stack: self._tree[v] = u
return u
def same(self, u, v):
return self.root(u) == self.root(v)
def merge(self, u, v):
u, v = self.root(u), self.root(v)
if u == v: return False
if self._tree[u] > self._tree[v]: u, v = v, u
self._tree[u] += self._tree[v]
self._tree[v] = u
self.cnt -= 1
return True
# size of connected component
def size(self, u):
return -self._tree[self.root(u)]
class LCA:
def __init__(self, parents, depth):
n = len(parents)
self._depth = depth
log = max(self._depth).bit_length()
self._table = [parents]+[[-1]*n for _ in range(log)]
row0 = self._table[0]
for lv in range(log):
row1 = self._table[lv+1]
for u in range(n):
if row0[u] == -1: continue
row1[u] = row0[row0[u]]
row0 = row1
def anc(self, u, v):
diff = self._depth[u]-self._depth[v]
if diff < 0: u, v = v, u
diff = abs(diff)
u = self.up(u, diff)
if u == v: return u
for lv in range(self._depth[u].bit_length()-1, -1, -1):
anclv = self._table[lv]
if anclv[u] != anclv[v]: u, v = anclv[u], anclv[v]
return self._table[0][u]
def up(self, u, dist):
lv = 0
while dist and u != -1:
if dist & 1: u = self._table[lv][u]
lv, dist = lv+1, dist >> 1
return u
n,m,q=LI()
to=[[] for _ in range(n)]
uv=[]
uf=UnionFind(n)
for _ in range(m):
u,v=LI1()
if uf.merge(u,v):
to[u].append(v)
to[v].append(u)
else:
uv.append((u,v))
def dfs(root=0):
uu, stack = [], [root]
while stack:
u = stack.pop()
uu.append(u)
for v in to[u]:
if v == parent[u]: continue
parent[v] = u
depth[v] = depth[u]+1
stack.append(v)
return uu
parent, depth = [-1]*n, [0]*n
uu=[]
for u in range(n):
if parent[u]==-1:uu+=dfs(u)
lca=LCA(parent,depth)
dp=[0]*n
for u,v in uv:
a=lca.anc(u,v)
dp[u]+=1
dp[v]+=1
dp[a]-=2
uf=UnionFind(n)
for u in uu[::-1]:
p=parent[u]
if p==-1:continue
dp[p]+=dp[u]
if dp[u]:continue
uf.merge(p,u)
for _ in range(q):
u,v=LI1()
print("Yes" if uf.same(u,v) else "No")
mkawa2