結果

問題 No.2553 Holidays
ユーザー dyktr_06
提出日時 2023-11-18 05:18:53
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 4 ms / 2,000 ms
コード長 2,991 bytes
コンパイル時間 2,118 ms
コンパイル使用メモリ 214,236 KB
最終ジャッジ日時 2025-02-17 22:27:41
ジャッジサーバーID
(参考情報)
judge2 / judge2
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ファイルパターン 結果
sample AC * 3
other AC * 55
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
int main(){
ios::sync_with_stdio(false);
cin.tie(nullptr);
int n, m; cin >> n >> m;
string s; cin >> s;
assert(3 <= n && n <= 100000);
assert(0 <= m && m <= n);
s += "x";
map<string, vector<int>> memo;
for(int l = 0; l < n;){
int r = l + 1;
while(r < n && s[l] == s[r]) r++;
if(s[l] == '-'){
string t = "";
if(l == 0) t += "x";
else t += s[l - 1];
t += s[r];
t += ((r - l) % 2) + '0';
memo[t].push_back(r - l);
}
l = r;
}
int ans = 0, can_ope = m, cnt = 0;
for(int i = 0; i < n; i++){
if(s[i] == 'o'){
ans++;
}
}
{
sort(memo["oo1"].begin(), memo["oo1"].end());
for(auto x : memo["oo1"]){
int cost = x / 2;
if(can_ope >= cost){
ans += x;
}else{
ans += can_ope * 2;
}
can_ope = max(0, can_ope - cost);
}
}
{
for(auto x : memo["oo0"]){
int cost = x / 2;
if(can_ope >= cost){
ans += x;
}else{
ans += can_ope * 2;
}
can_ope = max(0, can_ope - cost);
}
}
{
for(auto x : memo["ox0"]){
int cost = x / 2;
if(can_ope >= cost){
ans += x;
}else{
ans += can_ope * 2;
}
can_ope = max(0, can_ope - cost);
}
}
{
for(auto x : memo["xo0"]){
int cost = x / 2;
if(can_ope >= cost){
ans += x;
}else{
ans += can_ope * 2;
}
can_ope = max(0, can_ope - cost);
}
}
{
for(auto x : memo["ox1"]){
int cost = x / 2;
if(can_ope >= cost){
ans += x - 1;
}else{
ans += can_ope * 2;
}
can_ope = max(0, can_ope - cost);
cnt++;
}
}
{
for(auto x : memo["xo1"]){
int cost = x / 2;
if(can_ope >= cost){
ans += x - 1;
}else{
ans += can_ope * 2;
}
can_ope = max(0, can_ope - cost);
cnt++;
}
}
{
vector<int> xx;
cnt += (int) memo["xx0"].size();
for(auto x : memo["xx1"]) xx.push_back(x);
for(auto x : memo["xx0"]) xx.push_back(x - 1);
sort(xx.rbegin(), xx.rend());
for(auto x : xx){
int cost = (x + 1) / 2;
if(can_ope >= cost){
ans += x;
}else{
ans += max(0, can_ope * 2 - 1);
}
can_ope = max(0, can_ope - cost);
}
}
// ox1, xo1, xx0
ans += min(can_ope, cnt);
cout << ans << endl;
}
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