結果
問題 | No.2546 Many Arithmetic Sequences |
ユーザー |
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提出日時 | 2023-11-24 22:49:45 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
RE
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 5,249 bytes |
コンパイル時間 | 12,262 ms |
コンパイル使用メモリ | 297,172 KB |
最終ジャッジ日時 | 2025-02-18 00:26:21 |
ジャッジサーバーID (参考情報) |
judge5 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 35 RE * 1 |
ソースコード
//* #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") //*/ #include <bits/stdc++.h> // #include <atcoder/all> // #include <atcoder/lazysegtree> using namespace std; // using namespace atcoder; // #define _GLIBCXX_DEBUG #define DEBUG(x) cerr << #x << ": " << x << endl; #define DEBUG_VEC(v) \ cerr << #v << ":"; \ for (int iiiiiiii = 0; iiiiiiii < v.size(); iiiiiiii++) \ cerr << " " << v[iiiiiiii]; \ cerr << endl; #define DEBUG_MAT(v) \ cerr << #v << endl; \ for (int iv = 0; iv < v.size(); iv++) { \ for (int jv = 0; jv < v[iv].size(); jv++) { \ cerr << v[iv][jv] << " "; \ } \ cerr << endl; \ } typedef long long ll; // #define int ll #define vi vector<int> #define vl vector<ll> #define vii vector<vector<int>> #define vll vector<vector<ll>> #define vs vector<string> #define pii pair<int, int> #define pis pair<int, string> #define psi pair<string, int> #define pll pair<ll, ll> template <class S, class T> pair<S, T> operator+(const pair<S, T> &s, const pair<S, T> &t) { return pair<S, T>(s.first + t.first, s.second + t.second); } template <class S, class T> pair<S, T> operator-(const pair<S, T> &s, const pair<S, T> &t) { return pair<S, T>(s.first - t.first, s.second - t.second); } template <class S, class T> ostream &operator<<(ostream &os, pair<S, T> p) { os << "(" << p.first << ", " << p.second << ")"; return os; } #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define rep1(i, n) for (int i = 1; i <= (int)(n); i++) #define rrep(i, n) for (int i = (int)(n)-1; i >= 0; i--) #define rrep1(i, n) for (int i = (int)(n); i > 0; i--) #define REP(i, a, b) for (int i = a; i < b; i++) #define in(x, a, b) (a <= x && x < b) #define all(c) c.begin(), c.end() void YES(bool t = true) { cout << (t ? "YES" : "NO") << endl; } void Yes(bool t = true) { cout << (t ? "Yes" : "No") << endl; } void yes(bool t = true) { cout << (t ? "yes" : "no") << endl; } void NO(bool t = true) { cout << (t ? "NO" : "YES") << endl; } void No(bool t = true) { cout << (t ? "No" : "Yes") << endl; } void no(bool t = true) { cout << (t ? "no" : "yes") << endl; } template <class T> bool chmax(T &a, const T &b) { if (a < b) { a = b; return 1; } return 0; } template <class T> bool chmin(T &a, const T &b) { if (a > b) { a = b; return 1; } return 0; } #define UNIQUE(v) v.erase(std::unique(v.begin(), v.end()), v.end()); const ll inf = 1000000001; const ll INF = (ll)1e18 + 1; const long double pi = 3.1415926535897932384626433832795028841971L; int popcount(ll t) { return __builtin_popcountll(t); } // int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1}; // int dx2[8] = { 1,1,0,-1,-1,-1,0,1 }, dy2[8] = { 0,1,1,1,0,-1,-1,-1 }; vi dx = {0, 0, -1, 1}, dy = {-1, 1, 0, 0}; vi dx2 = {1, 1, 0, -1, -1, -1, 0, 1}, dy2 = {0, 1, 1, 1, 0, -1, -1, -1}; struct Setup_io { Setup_io() { ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0); cout << fixed << setprecision(25); } } setup_io; // const ll MOD = 1000000007; const ll MOD = 998244353; // #define mp make_pair // #define endl '\n' signed main() { int n, m; cin >> n >> m; vector<pll> ad; priority_queue<pll> pq; rep(i, n) { ll a, d; cin >> a >> d; if (d <= 0) { pq.emplace(a, d); } else { ad.emplace_back(a, d); } } vl neg; while (neg.size() < m) { auto [a, d] = pq.top(); pq.pop(); neg.emplace_back(a); pq.emplace(a + d, d); } vl sum(m + 1); rep(i, m) { sum[i + 1] = sum[i] + neg[i]; } // DEBUG_VEC(sum); ll ans = sum[m]; if (ad.size() == 0) { cout << ans << endl; return 0; } sort(all(ad)); reverse(all(ad)); vector<pll> nad; nad.push_back(ad[0]); for (int i = 1; i < ad.size(); i++) { if (nad.back().second < ad[i].second) { nad.push_back(ad[i]); } } swap(ad, nad); int done = 0; rep(i, ad.size() - 1) { ll a = ad[i].first, d = ad[i].second; ll na = ad[i + 1].first, nd = ad[i + 1].second; auto f1 = [&](ll x) { ll ret = a * x + x * (x - 1) / 2 * d; return ret; }; auto f2 = [&](ll x) { ll ret = na * x + x * (x - 1) / 2 * nd; return ret; }; // DEBUG(ad[i]); int ok = done, ng = m + 1; while (ng - ok > 1) { int mid = (ok + ng) / 2; if (f1(mid) >= f2(mid + 1)) { ok = mid; } else { ng = mid; } } for (ll j = done; j <= ok; j++) { chmax(ans, f1(j) + sum[m - j]); } done = ok; } for (ll j = done; j <= m; j++) { chmax(ans, ad.back().first * j + j * (j - 1) / 2 * ad.back().second + sum[m - j]); } cout << ans << endl; }