結果

問題 No.2543 Many Meetings
ユーザー dyktr_06
提出日時 2023-11-24 23:23:14
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
RE  
実行時間 -
コード長 7,284 bytes
コンパイル時間 2,413 ms
コンパイル使用メモリ 211,912 KB
最終ジャッジ日時 2025-02-18 00:42:08
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 10 RE * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define overload4(_1, _2, _3, _4, name, ...) name
#define rep1(n) for(int i = 0; i < (int)(n); ++i)
#define rep2(i, n) for(int i = 0; i < (int)(n); ++i)
#define rep3(i, a, b) for(int i = (a); i < (int)(b); ++i)
#define rep4(i, a, b, c) for(int i = (a); i < (int)(b); i += (c))
#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)
#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; --i)
#define ALL(a) (a).begin(), (a).end()
#define Sort(a) (sort((a).begin(), (a).end()))
#define RSort(a) (sort((a).rbegin(), (a).rend()))
#define UNIQUE(a) (a.erase(unique((a).begin(), (a).end()), (a).end()))
typedef long long int ll;
typedef unsigned long long ul;
typedef long double ld;
typedef vector<int> vi;
typedef vector<long long> vll;
typedef vector<char> vc;
typedef vector<string> vst;
typedef vector<double> vd;
typedef vector<long double> vld;
typedef pair<long long, long long> P;
template<class T> long long sum(const T& a){ return accumulate(a.begin(), a.end(), 0LL); }
template<class T> auto min(const T& a){ return *min_element(a.begin(), a.end()); }
template<class T> auto max(const T& a){ return *max_element(a.begin(), a.end()); }
const long long MINF = 0x7fffffffffff;
const long long INF = 0x1fffffffffffffff;
const long long MOD = 998244353;
const long double EPS = 1e-9;
const long double PI = acos(-1);
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
template<typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p){ is >> p.first >> p.second; return is; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){ os << "(" << p.first << ", " << p.second << ")"; return
    os; }
template<typename T> istream &operator>>(istream &is, vector<T> &v){ for(T &in : v) is >> in; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &v){ for(int i = 0; i < (int) v.size(); ++i){ os << v[i] << (i + 1 != (int) v
    .size() ? " " : ""); } return os; }
template <typename T, typename S> ostream &operator<<(ostream &os, const map<T, S> &mp){ for(auto &[key, val] : mp){ os << key << ":" << val << " ";
    } return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr
    << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os <<
    *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, queue<T> q){ while(q.size()){ os << q.front() << " "; q.pop(); } return os; }
template <typename T> ostream &operator<<(ostream &os, deque<T> q){ while(q.size()){ os << q.front() << " "; q.pop_front(); } return os; }
template <typename T> ostream &operator<<(ostream &os, stack<T> st){ while(st.size()){ os << st.top() << " "; st.pop(); } return os; }
template <class T, class Container, class Compare> ostream &operator<<(ostream &os, priority_queue<T, Container, Compare> pq){ while(pq.size()){ os
    << pq.top() << " "; pq.pop(); } return os; }
template<class T, class U> inline T vin(T& vec, U n) { vec.resize(n); for(int i = 0; i < (int) n; ++i) cin >> vec[i]; return vec; }
template<class T> inline void vout(T vec, string s = "\n"){ for(auto x : vec) cout << x << s; }
template<class... T> void in(T&... a){ (cin >> ... >> a); }
void out(){ cout << '\n'; }
template<class T, class... Ts> void out(const T& a, const Ts&... b){ cout << a; (cout << ... << (cout << ' ', b)); cout << '\n'; }
template<class T, class U> void inGraph(vector<vector<T>>& G, U n, U m, bool directed = false){ G.resize(n); for(int i = 0; i < m; ++i){ int a, b;
    cin >> a >> b; a--, b--; G[a].push_back(b); if(!directed) G[b].push_back(a); } }
template <typename X>
struct SegTree{
using FX = function<X(X, X)>; // X•X -> X
int n;
FX fx;
const X ex;
vector<X> dat;
SegTree(int n_, const FX &fx_, const X &ex_) : n(), fx(fx_), ex(ex_){
int x = 1;
while(n_ > x){
x *= 2;
}
n = x;
dat.assign(n * 2, ex);
}
X get(int i) const {
return dat[i + n];
}
void set(int i, X x){ dat[i + n] = x; }
void build(){
for(int k = n - 1; k >= 1; k--) dat[k] = fx(dat[k * 2], dat[k * 2 + 1]);
}
void update(int i, X x){
i += n;
dat[i] = x;
while(i > 0){
i >>= 1; // parent
dat[i] = fx(dat[i * 2], dat[i * 2 + 1]);
}
}
X query(int a, int b){
X vl = ex;
X vr = ex;
int l = a + n;
int r = b + n;
while(l < r){
if(l & 1) vl = fx(vl, dat[l++]);
if(r & 1) vr = fx(dat[--r], vr);
l >>= 1;
r >>= 1;
}
return fx(vl, vr);
}
X operator [](int i) const {
return dat[i + n];
}
};
template <typename T>
struct compress{
vector<T> sorted, compressed;
compress(const vector<T>& vec){
int n = vec.size();
compressed.resize(n);
for(T x : vec){
sorted.emplace_back(x);
}
sort(sorted.begin(), sorted.end());
sorted.erase(unique(sorted.begin(), sorted.end()), sorted.end());
for(int i = 0; i < n; ++i){
compressed[i] = lower_bound(sorted.begin(), sorted.end(), vec[i]) - sorted.begin();
}
}
int get(const T& x) const{
return lower_bound(sorted.begin(), sorted.end(), x) - sorted.begin();
}
T inv(const T& x) const{
return sorted[x];
}
size_t size() const{
return sorted.size();
}
vector<T> getCompressed() const{
return compressed;
}
};
ll n, k;
vector<P> lr;
void input(){
in(n, k);
lr.resize(n);
rep(i, n){
in(lr[i].first, lr[i].second);
}
}
void solve(){
Sort(lr);
map<ll, ll> mp;
ll mn = INF, mnK = -1;
rrep(i, n){
auto [l, r] = lr[i];
if(chmin(mn, r)){
mnK = i;
}
mp[l] = mnK;
}
ll logK = 20;
vector<vll> doubling(logK, vll(20, -1));
rep(i, n){
auto iter = mp.lower_bound(lr[i].second);
if(iter == mp.end()){
doubling[0][i] = -1;
}else{
doubling[0][i] = iter->second;
}
}
rep(j, logK - 1){
rep(i, n){
if(doubling[j][i] == -1) continue;
doubling[j + 1][i] = doubling[j][doubling[j][i]];
}
}
ll ans = INF;
rep(i, n){
ll now = i;
ll nowK = k - 1;
for(int j = 0; (nowK > 0 && now >= 0); j++){
if(nowK & 1) now = doubling[j][now];
nowK = nowK >> 1;
}
if(now != -1){
chmin(ans, lr[now].second - lr[i].first);
}
}
if(ans == INF){
out(-1);
}else{
out(ans);
}
}
int main(){
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout << fixed << setprecision(20);
input();
solve();
}
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