結果
問題 | No.2543 Many Meetings |
ユーザー |
|
提出日時 | 2023-11-24 23:23:14 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
RE
|
実行時間 | - |
コード長 | 7,284 bytes |
コンパイル時間 | 2,413 ms |
コンパイル使用メモリ | 211,912 KB |
最終ジャッジ日時 | 2025-02-18 00:42:08 |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 10 RE * 30 |
ソースコード
#include <bits/stdc++.h>using namespace std;#define overload4(_1, _2, _3, _4, name, ...) name#define rep1(n) for(int i = 0; i < (int)(n); ++i)#define rep2(i, n) for(int i = 0; i < (int)(n); ++i)#define rep3(i, a, b) for(int i = (a); i < (int)(b); ++i)#define rep4(i, a, b, c) for(int i = (a); i < (int)(b); i += (c))#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; --i)#define ALL(a) (a).begin(), (a).end()#define Sort(a) (sort((a).begin(), (a).end()))#define RSort(a) (sort((a).rbegin(), (a).rend()))#define UNIQUE(a) (a.erase(unique((a).begin(), (a).end()), (a).end()))typedef long long int ll;typedef unsigned long long ul;typedef long double ld;typedef vector<int> vi;typedef vector<long long> vll;typedef vector<char> vc;typedef vector<string> vst;typedef vector<double> vd;typedef vector<long double> vld;typedef pair<long long, long long> P;template<class T> long long sum(const T& a){ return accumulate(a.begin(), a.end(), 0LL); }template<class T> auto min(const T& a){ return *min_element(a.begin(), a.end()); }template<class T> auto max(const T& a){ return *max_element(a.begin(), a.end()); }const long long MINF = 0x7fffffffffff;const long long INF = 0x1fffffffffffffff;const long long MOD = 998244353;const long double EPS = 1e-9;const long double PI = acos(-1);template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }template<typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p){ is >> p.first >> p.second; return is; }template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){ os << "(" << p.first << ", " << p.second << ")"; returnos; }template<typename T> istream &operator>>(istream &is, vector<T> &v){ for(T &in : v) is >> in; return is; }template<typename T> ostream &operator<<(ostream &os, const vector<T> &v){ for(int i = 0; i < (int) v.size(); ++i){ os << v[i] << (i + 1 != (int) v.size() ? " " : ""); } return os; }template <typename T, typename S> ostream &operator<<(ostream &os, const map<T, S> &mp){ for(auto &[key, val] : mp){ os << key << ":" << val << " ";} return os; }template <typename T> ostream &operator<<(ostream &os, const set<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr<< (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }template <typename T> ostream &operator<<(ostream &os, const multiset<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os <<*itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }template <typename T> ostream &operator<<(ostream &os, queue<T> q){ while(q.size()){ os << q.front() << " "; q.pop(); } return os; }template <typename T> ostream &operator<<(ostream &os, deque<T> q){ while(q.size()){ os << q.front() << " "; q.pop_front(); } return os; }template <typename T> ostream &operator<<(ostream &os, stack<T> st){ while(st.size()){ os << st.top() << " "; st.pop(); } return os; }template <class T, class Container, class Compare> ostream &operator<<(ostream &os, priority_queue<T, Container, Compare> pq){ while(pq.size()){ os<< pq.top() << " "; pq.pop(); } return os; }template<class T, class U> inline T vin(T& vec, U n) { vec.resize(n); for(int i = 0; i < (int) n; ++i) cin >> vec[i]; return vec; }template<class T> inline void vout(T vec, string s = "\n"){ for(auto x : vec) cout << x << s; }template<class... T> void in(T&... a){ (cin >> ... >> a); }void out(){ cout << '\n'; }template<class T, class... Ts> void out(const T& a, const Ts&... b){ cout << a; (cout << ... << (cout << ' ', b)); cout << '\n'; }template<class T, class U> void inGraph(vector<vector<T>>& G, U n, U m, bool directed = false){ G.resize(n); for(int i = 0; i < m; ++i){ int a, b;cin >> a >> b; a--, b--; G[a].push_back(b); if(!directed) G[b].push_back(a); } }template <typename X>struct SegTree{using FX = function<X(X, X)>; // X•X -> X となる関数の型int n;FX fx;const X ex;vector<X> dat;SegTree(int n_, const FX &fx_, const X &ex_) : n(), fx(fx_), ex(ex_){int x = 1;while(n_ > x){x *= 2;}n = x;dat.assign(n * 2, ex);}X get(int i) const {return dat[i + n];}void set(int i, X x){ dat[i + n] = x; }void build(){for(int k = n - 1; k >= 1; k--) dat[k] = fx(dat[k * 2], dat[k * 2 + 1]);}void update(int i, X x){i += n;dat[i] = x;while(i > 0){i >>= 1; // parentdat[i] = fx(dat[i * 2], dat[i * 2 + 1]);}}X query(int a, int b){X vl = ex;X vr = ex;int l = a + n;int r = b + n;while(l < r){if(l & 1) vl = fx(vl, dat[l++]);if(r & 1) vr = fx(dat[--r], vr);l >>= 1;r >>= 1;}return fx(vl, vr);}X operator [](int i) const {return dat[i + n];}};template <typename T>struct compress{vector<T> sorted, compressed;compress(const vector<T>& vec){int n = vec.size();compressed.resize(n);for(T x : vec){sorted.emplace_back(x);}sort(sorted.begin(), sorted.end());sorted.erase(unique(sorted.begin(), sorted.end()), sorted.end());for(int i = 0; i < n; ++i){compressed[i] = lower_bound(sorted.begin(), sorted.end(), vec[i]) - sorted.begin();}}int get(const T& x) const{return lower_bound(sorted.begin(), sorted.end(), x) - sorted.begin();}T inv(const T& x) const{return sorted[x];}size_t size() const{return sorted.size();}vector<T> getCompressed() const{return compressed;}};ll n, k;vector<P> lr;void input(){in(n, k);lr.resize(n);rep(i, n){in(lr[i].first, lr[i].second);}}void solve(){Sort(lr);map<ll, ll> mp;ll mn = INF, mnK = -1;rrep(i, n){auto [l, r] = lr[i];if(chmin(mn, r)){mnK = i;}mp[l] = mnK;}ll logK = 20;vector<vll> doubling(logK, vll(20, -1));rep(i, n){auto iter = mp.lower_bound(lr[i].second);if(iter == mp.end()){doubling[0][i] = -1;}else{doubling[0][i] = iter->second;}}rep(j, logK - 1){rep(i, n){if(doubling[j][i] == -1) continue;doubling[j + 1][i] = doubling[j][doubling[j][i]];}}ll ans = INF;rep(i, n){ll now = i;ll nowK = k - 1;for(int j = 0; (nowK > 0 && now >= 0); j++){if(nowK & 1) now = doubling[j][now];nowK = nowK >> 1;}if(now != -1){chmin(ans, lr[now].second - lr[i].first);}}if(ans == INF){out(-1);}else{out(ans);}}int main(){ios::sync_with_stdio(false);cin.tie(nullptr);cout << fixed << setprecision(20);input();solve();}