結果

問題 No.1961 Clear Brackets
ユーザー 👑 hos.lyric
提出日時 2023-11-25 23:23:40
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 107 ms / 2,000 ms
コード長 8,704 bytes
コンパイル時間 1,659 ms
コンパイル使用メモリ 125,596 KB
実行使用メモリ 26,668 KB
最終ジャッジ日時 2024-09-26 11:22:15
合計ジャッジ時間 6,071 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 42
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <cassert>
#include <cmath>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <functional>
#include <iostream>
#include <limits>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using Int = long long;
template <class T1, class T2> ostream &operator<<(ostream &os, const pair<T1, T2> &a) { return os << "(" << a.first << ", " << a.second << ")"; };
template <class T> ostream &operator<<(ostream &os, const vector<T> &as) { const int sz = as.size(); os << "["; for (int i = 0; i < sz; ++i) { if (i
    >= 256) { os << ", ..."; break; } if (i > 0) { os << ", "; } os << as[i]; } return os << "]"; }
template <class T> void pv(T a, T b) { for (T i = a; i != b; ++i) cerr << *i << " "; cerr << endl; }
template <class T> bool chmin(T &t, const T &f) { if (t > f) { t = f; return true; } return false; }
template <class T> bool chmax(T &t, const T &f) { if (t < f) { t = f; return true; } return false; }
#define COLOR(s) ("\x1b[" s "m")
// T: monoid representing information of an interval.
// T() should return the identity.
// T(S s) should represent a single element of the array.
// T::pull(const T &l, const T &r) should pull two intervals.
template <class T> struct SegmentTreePoint {
int logN, n;
vector<T> ts;
SegmentTreePoint() : logN(0), n(0) {}
explicit SegmentTreePoint(int n_) {
for (logN = 0, n = 1; n < n_; ++logN, n <<= 1) {}
ts.resize(n << 1);
}
template <class S> explicit SegmentTreePoint(const vector<S> &ss) {
const int n_ = ss.size();
for (logN = 0, n = 1; n < n_; ++logN, n <<= 1) {}
ts.resize(n << 1);
for (int i = 0; i < n_; ++i) at(i) = T(ss[i]);
build();
}
T &at(int i) {
return ts[n + i];
}
void build() {
for (int u = n; --u; ) pull(u);
}
inline void pull(int u) {
ts[u].pull(ts[u << 1], ts[u << 1 | 1]);
}
// Changes the value of point a to s.
template <class S> void change(int a, const S &s) {
assert(0 <= a); assert(a < n);
ts[a += n] = T(s);
for (; a >>= 1; ) pull(a);
}
// Applies T::f(args...) to point a.
template <class F, class... Args>
void ch(int a, F f, Args &&... args) {
assert(0 <= a); assert(a < n);
(ts[a += n].*f)(args...);
for (; a >>= 1; ) pull(a);
}
// Calculates the product for [a, b).
T get(int a, int b) {
assert(0 <= a); assert(a <= b); assert(b <= n);
if (a == b) return T();
a += n; b += n;
T prodL, prodR, t;
for (int aa = a, bb = b; aa < bb; aa >>= 1, bb >>= 1) {
if (aa & 1) { t.pull(prodL, ts[aa++]); prodL = t; }
if (bb & 1) { t.pull(ts[--bb], prodR); prodR = t; }
}
t.pull(prodL, prodR);
return t;
}
// Calculates T::f(args...) of a monoid type for [a, b).
// op(-, -) should calculate the product.
// e() should return the identity.
template <class Op, class E, class F, class... Args>
#if __cplusplus >= 201402L
auto
#else
decltype((std::declval<T>().*F())())
#endif
get(int a, int b, Op op, E e, F f, Args &&... args) {
assert(0 <= a); assert(a <= b); assert(b <= n);
if (a == b) return e();
a += n; b += n;
auto prodL = e(), prodR = e();
for (int aa = a, bb = b; aa < bb; aa >>= 1, bb >>= 1) {
if (aa & 1) prodL = op(prodL, (ts[aa++].*f)(args...));
if (bb & 1) prodR = op((ts[--bb].*f)(args...), prodR);
}
return op(prodL, prodR);
}
// Find min b s.t. T::f(args...) returns true,
// when called for the partition of [a, b) from left to right.
// Returns n + 1 if there is no such b.
template <class F, class... Args>
int findRight(int a, F f, Args &&... args) {
assert(0 <= a); assert(a <= n);
if ((T().*f)(args...)) return a;
if (a == n) return n + 1;
a += n;
for (; ; a >>= 1) if (a & 1) {
if ((ts[a].*f)(args...)) {
for (; a < n; ) {
if (!(ts[a <<= 1].*f)(args...)) ++a;
}
return a - n + 1;
}
++a;
if (!(a & (a - 1))) return n + 1;
}
}
// Find max a s.t. T::f(args...) returns true,
// when called for the partition of [a, b) from right to left.
// Returns -1 if there is no such a.
template <class F, class... Args>
int findLeft(int b, F f, Args &&... args) {
assert(0 <= b); assert(b <= n);
if ((T().*f)(args...)) return b;
if (b == 0) return -1;
b += n;
for (; ; b >>= 1) if ((b & 1) || b == 2) {
if ((ts[b - 1].*f)(args...)) {
for (; b <= n; ) {
if (!(ts[(b <<= 1) - 1].*f)(args...)) --b;
}
return b - n - 1;
}
--b;
if (!(b & (b - 1))) return -1;
}
}
};
////////////////////////////////////////////////////////////////////////////////
constexpr int INF = 1001001001;
struct NodeMin {
int mn;
NodeMin() : mn(+INF) {}
NodeMin(int val) : mn(val) {}
void pull(const NodeMin &l, const NodeMin &r) {
mn = min(l.mn, r.mn);
}
void ch(int val) {
mn = val;
}
void chmin(int val) {
if (mn > val) mn = val;
}
bool test(int tar) const {
return (mn <= tar);
}
};
struct NodeMax {
int mx;
NodeMax() : mx(-INF) {}
NodeMax(int val) : mx(val) {}
void pull(const NodeMax &l, const NodeMax &r) {
mx = max(l.mx, r.mx);
}
void ch(int val) {
mx = val;
}
void chmax(int val) {
if (mx < val) mx = val;
}
bool test(int tar) const {
return (mx >= tar);
}
};
////////////////////////////////////////////////////////////////////////////////
int N;
char S[200'010];
int main() {
for (; ~scanf("%d", &N); ) {
scanf("%s", S);
vector<int> F(N + 1), G(N + 1);
{
vector<int> is(2 * (N + 1) + 1, N + 1);
int d = N + 1;
for (int i = N; i >= 0; --i) {
if (i < N) {
d = (S[i] == ')') ? (d + 1) : (d - 1);
}
F[i] = is[d - 1] - 1;
is[d] = i;
}
}
{
vector<int> is(2 * (N + 1) + 1, -1);
int d = N + 1;
for (int i = 0; i <= N; ++i) {
G[i] = is[d - 1] + 1;
is[d] = i;
if (i < N) {
d = (S[i] == '(') ? (d + 1) : (d - 1);
}
}
}
// cerr<<"F = "<<F<<endl;
// cerr<<"G = "<<G<<endl;
/*
o? - o? - o? - o? + o? + o?
0: down
1: up
2: down, o
3: up, o
i < j
2 | j - i
F[i] >= j
i >= G[j]
*/
vector<pair<int, int>> fis(N + 1);
for (int i = 0; i <= N; ++i) {
fis[i] = make_pair(F[i], i);
}
sort(fis.begin(), fis.end());
int pos = 0;
vector<int> on(N + 1, 1);
vector<vector<int>> dp(N + 1, vector<int>(4, -INF));
SegmentTreePoint<NodeMax> segs[2][2];
for (int u = 0; u < 2; ++u) for (int h = 0; h < 2; ++h) {
segs[u][h] = SegmentTreePoint<NodeMax>(N + 1);
}
for (int u = 0; u < 2; ++u) {
dp[0][u] = 0;
segs[u][0].change(0, 0);
}
for (int j = 1; j <= N; ++j) {
{
const int i = j - 1;
if (S[i] == '?' || S[i] == ')') {
for (int u = 0; u < 4; u += 2) {
chmax(dp[i + 1][0], dp[i][u]);
}
}
if (S[i] == '?' || S[i] == '(') {
for (int u = 0; u < 4; ++u) {
chmax(dp[i + 1][1], dp[i][u]);
}
}
}
for (; pos < N + 1 && fis[pos].first < j; ++pos) {
const int i = fis[pos].second;
on[i] = 0;
for (int u = 0; u < 2; ++u) {
segs[u][i & 1].change(i, -INF);
}
}
for (int u = 0; u < 2; ++u) {
chmax(dp[j][u + 2], segs[u][j & 1].get(G[j], j).mx + 1);
}
if (on[j]) {
for (int u = 0; u < 2; ++u) {
segs[u][j & 1].change(j, dp[j][u]);
}
}
}
const int ans = *max_element(dp[N].begin(), dp[N].end());
printf("%d\n", ans);
#ifdef LOCAL
vector<vector<int>>brt(N+1,vector<int>(4,-INF));
brt[0][0]=0;
brt[0][1]=0;
for(int i=0;i<N;++i){
if(S[i]=='?'||S[i]==')'){
chmax(brt[i+1][0],brt[i][0]);
chmax(brt[i+1][0],brt[i][2]);
}
if(S[i]=='?'||S[i]=='('){
chmax(brt[i+1][1],brt[i][0]);
chmax(brt[i+1][1],brt[i][1]);
chmax(brt[i+1][1],brt[i][2]);
chmax(brt[i+1][1],brt[i][3]);
}
for(int j=i+1;j<=N;++j)if((j-i)%2==0&&F[i]>=j&&i>=G[j]){
chmax(brt[j][2],brt[i][0]+1);
chmax(brt[j][3],brt[i][1]+1);
}
}
// for(int i=0;i<=N;++i)cerr<<"brt["<<i<<"] = "<<brt[i]<<endl;
// for(int i=0;i<=N;++i)cerr<<"dp["<<i<<"] = "<<dp[i]<<endl;
for(int i=0;i<=N;++i)for(int u=0;u<4;++u)assert(max(brt[i][u],-1)==max(dp[i][u],-1));
#endif
}
return 0;
}
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