結果

問題 No.2571 列辞書順列
ユーザー 👑 AngrySadEight
提出日時 2023-11-27 20:34:04
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
AC  
実行時間 326 ms / 3,000 ms
コード長 4,473 bytes
コンパイル時間 19,497 ms
コンパイル使用メモリ 262,508 KB
最終ジャッジ日時 2025-02-18 02:02:23
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 29
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <algorithm>
#include <atcoder/all>
#include <bitset>
#include <cassert>
#include <cmath>
#include <ctime>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <string>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using namespace atcoder;
typedef long long ll;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repr(i, n) for (int i = (int)(n)-1; i >= 0; i--)
#define repk(i, k, n) for (int i = k; i < (int)(n); i++)
#define all(v) v.begin(), v.end()
#define mod1 1000000007
#define mod2 998244353
#define mod3 100000007
#define vi vector<int>
#define vs vector<string>
#define vc vector<char>
#define vl vector<ll>
#define vb vector<bool>
#define vvi vector<vector<int>>
#define vvc vector<vector<char>>
#define vvl vector<vector<ll>>
#define vvb vector<vector<bool>>
#define vvvi vector<vector<vector<int>>>
#define vvvl vector<vector<vector<ll>>>
#define pii pair<int, int>
#define pil pair<int, ll>
#define pli pair<ll, int>
#define pll pair<ll, ll>
#define vpii vector<pair<int, int>>
#define vpll vector<pair<ll, ll>>
#define vvpii vector<vector<pair<int, int>>>
#define vvpll vector<vector<pair<ll, ll>>>
using mint = modint998244353;
template <typename T>
void debug(T e) {
cerr << e << endl;
}
template <typename T>
void debug(vector<T> &v) {
rep(i, v.size()) { cerr << v[i] << " "; }
cerr << endl;
}
template <typename T>
void debug(vector<vector<T>> &v) {
rep(i, v.size()) {
rep(j, v[i].size()) { cerr << v[i][j] << " "; }
cerr << endl;
}
}
template <typename T>
void debug(vector<pair<T, T>> &v) {
rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; }
}
template <typename T>
void debug(set<T> &st) {
for (auto itr = st.begin(); itr != st.end(); itr++) {
cerr << *itr << " ";
}
cerr << endl;
}
template <typename T>
void debug(multiset<T> &ms) {
for (auto itr = ms.begin(); itr != ms.end(); itr++) {
cerr << *itr << " ";
}
cerr << endl;
}
template <typename T>
void debug(map<T, T> &mp) {
for (auto itr = mp.begin(); itr != mp.end(); itr++) {
cerr << itr->first << " " << itr->second << endl;
}
}
void debug_out() { cerr << endl; }
template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
cerr << H << " ";
debug_out(T...);
}
ll my_pow(ll x, ll n, ll mod) {
//  x^nmod
ll ret;
if (n == 0) {
ret = 1;
} else if (n % 2 == 1) {
ret = (x * my_pow((x * x) % mod, n / 2, mod)) % mod;
} else {
ret = my_pow((x * x) % mod, n / 2, mod);
}
return ret;
}
ll inv(ll x, ll mod) { return my_pow(x, mod - 2, mod); }
ll op(ll a, ll b) { return (a + b) % mod2; }
ll e() { return 0LL; }
int main() {
ll N, M, K, Q;
cin >> N >> M >> K >> Q;
vector<ll> A(N);
for (ll i = 0; i < N; i++) {
cin >> A[i];
A[i]--;
}
ll inv_m = inv(M - 1, mod2);
vector<ll> pow_m(N + 1);
pow_m[0] = 1;
for (ll i = 0; i < N; i++) {
pow_m[i + 1] = (pow_m[i] * M) % mod2;
}
segtree<ll, op, e> seg1(N);
segtree<ll, op, e> seg2(N);
for (ll i = 0; i < N; i++) {
seg1.set(i, (my_pow(M, K - i, mod2) * A[i]) % mod2);
seg2.set(i, A[i]);
}
for (ll i = 0; i < Q; i++) {
/*for (ll j = 0; j < N; j++) {
cout << seg1.get(j) << " ";
}
cout << endl;
for (ll j = 0; j < N; j++) {
cout << seg2.get(j) << " ";
}
cout << endl;*/
ll t;
cin >> t;
if (t == 1) {
ll l, r;
cin >> l >> r;
l--;
r--;
ll ans = (r - l + 1);
ll prd1 = seg1.prod(l, r + 1);
prd1 = (prd1 * pow_m[l]) % mod2;
ll prd2 = seg2.prod(l, r + 1);
ll sums = (prd1 + mod2 - prd2) % mod2;
sums = (sums * inv_m) % mod2;
ans = (ans + sums) % mod2;
cout << ans << endl;
} else {
ll x, y;
cin >> x >> y;
x--;
y--;
seg1.set(x, (my_pow(M, K - x, mod2) * y) % mod2);
seg2.set(x, y);
}
}
}
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