結果

問題 No.2577 Simple Permutation Guess
ユーザー nullnull
提出日時 2023-11-27 23:17:36
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 248 ms / 2,000 ms
コード長 4,716 bytes
コンパイル時間 7,128 ms
コンパイル使用メモリ 464,420 KB
実行使用メモリ 25,580 KB
平均クエリ数 545.71
最終ジャッジ日時 2024-09-26 22:33:19
合計ジャッジ時間 23,752 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 111
権限があれば一括ダウンロードができます

ソースコード

diff #

/*
このコード、と~おれ!
Be accepted!
∧_∧ 
(。・ω・。)つ━☆・*。
⊂   ノ    ・゜+.
 しーJ   °。+ *´¨)
          .· ´¸.·*´¨) ¸.·*¨)
		            (¸.·´ (¸.·'* ☆
*/

#include <cstdio>
#include <algorithm>
#include <string>
#include <cmath>
#include <cstring>
#include <vector>
#include <numeric>
#include <iostream>
#include <random>
#include <map>
#include <unordered_map>
#include <queue>
#include <regex>
#include <functional>
#include <complex>
#include <list>
#include <cassert>
#include <iomanip>
#include <set>
#include <stack>
#include <bitset>
#include <array>
#include <chrono>
#include <unordered_set>

//#pragma GCC target("arch=skylake-avx512")
//#pragma GCC target("avx2")
//#pragma GCC optimize("O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse4")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#define repeat(i, n, m) for(int i = n; i < (m); ++i)
#define rep(i, n) for(int i = 0; i < (n); ++i)
#define printynl(a) printf(a ? "yes\n" : "no\n")
#define printyn(a) printf(a ? "Yes\n" : "No\n")
#define printYN(a) printf(a ? "YES\n" : "NO\n")
#define printim(a) printf(a ? "possible\n" : "imposible\n")
#define printdb(a) printf("%.50lf\n", a)
#define printLdb(a) printf("%.50Lf\n", a)
#define printdbd(a) printf("%.16lf\n", a)
#define prints(s) printf("%s\n", s.c_str())
#define all(x) (x).begin(), (x).end()
#define deg_to_rad(deg) (((deg)/360.0L)*2.0L*PI)
#define rad_to_deg(rad) (((rad)/2.0L/PI)*360.0L)
#define Please return
#define AC 0
#define manhattan_dist(a, b, c, d) (abs(a - c) + abs(b - d))

using ll = long long;
using ull = unsigned long long;

constexpr int INF = 1073741823;
constexpr int MINF = -1073741823;
constexpr ll LINF = ll(4661686018427387903);
constexpr ll MOD = 1e9 + 7;
constexpr ll mod = 998244353;
constexpr long double eps = 1e-14;
const long double PI = acosl(-1.0L);

using namespace std;

void scans(string& str) {
	char c;
	str = "";
	scanf("%c", &c);
	if (c == '\n')scanf("%c", &c);
	while (c != '\n' && c != -1 && c != ' ') {
		str += c;
		scanf("%c", &c);
	}
}

void scanc(char& str) {
	char c;
	scanf("%c", &c);
	if (c == -1)return;
	while (c == '\n') {
		scanf("%c", &c);
	}
	str = c;
}

double acot(double x) {
	return PI / 2 - atan(x);
}

ll LSB(ll n) { return (n & (-n)); }

template<typename T>
inline T chmin(T& a, const T& b) {
	if (a > b)a = b;
	return a;
}

template<typename T>
inline T chmax(T& a, const T& b) {
	if (a < b)a = b;
	return a;
}

//cpp_int
#if __has_include(<boost/multiprecision/cpp_int.hpp>)
#include <boost/multiprecision/cpp_int.hpp>
#include <boost/multiprecision/cpp_dec_float.hpp>
using namespace boost::multiprecision;
#else
using cpp_int = ll;
#endif

//atcoder library
#if __has_include(<atcoder/all>)
#include <atcoder/all>
//using namespace atcoder;
#endif

/*
	random_device seed_gen;
	mt19937 engine(seed_gen());
	uniform_int_distribution dist(1, 100);
*/


/*----------------------------------------------------------------------------------*/

/*
* @title kth_permutation
* @docs kyopro/docs/kth_permutation.md
*/

template<typename T = int>
vector<T> kth_permutation(int n, T k) {
	vector<T> a(n), b(n);
	rep(i, n)b[i] = i + 1;
	vector<T> x(n);
	rep(i, n) {
		x[i] = (k % (ll)(i + 1));
		k /= (i + 1);
	}
	reverse(all(x));
	rep(i, n) {
		a[i] = b[x[i]];
		b.erase(b.begin() + x[i]);
	}
	return a;
}

int main() {

	int n;
	scanf("%d", &n);
	vector<int> ans(n);
	if (n <= 15) {
		ll ng = 1, ok = 0;
		rep(i, n)ng *= i + 1;
		while (abs(ng - ok) > 1) {
			ll mid = (ok + ng) / 2;
			auto a = kth_permutation<int>(n, mid);
			puts("?");
			rep(i, n)printf("%d ", a[i]);
			puts("");
			fflush(stdout);
			int res;
			scanf("%d", &res);
			if (res == 1)ok = mid;
			else ng = mid;
		}
		ans = kth_permutation<int>(n, ok);
	}
	else {
		set<int> st;
		rep(i, n)st.insert(i + 1);
		map<vector<int>, int> mp;
		rep(i, n) {
			int k = st.size(),
				ok = 0, ng = k;
			while (abs(ok - ng) > 1) {
				int mid = (ok + ng) / 2;
				auto stt = st;
				vector<int> a(n);
				rep(j, i)a[j] = ans[j];
				a[i] = *next(stt.begin(), mid);
				stt.erase(next(stt.begin(), mid));
				rep(j, n - i - 1)a[i + j + 1] = *next(stt.begin(), j);
				int res;
				if (mp.find(a) == mp.end()) {
					puts("?");
					rep(i, n)printf("%d ", a[i]);
					puts("");
					fflush(stdout);
					scanf("%d", &res);
					mp[a] = res;
				}
				res = mp[a];
				if (res == 1)ok = mid;
				else ng = mid;
			}
			ans[i] = *next(st.begin(), ok);
			st.erase(next(st.begin(), ok));
		}
	}
	puts("!");
	rep(i, n)printf("%d\n", ans[i]);
	fflush(stdout);

	Please AC;
}
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